Amount of Hydropower Solution

STEP 0: Pre-Calculation Summary
Formula Used
Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000
P = (γf*qflow*(Hl-HWater)*η)/1000
This formula uses 6 Variables
Variables Used
Amount of Hydropower - (Measured in Kilowatt) - Amount of Hydropower is a form of renewable energy that uses the water stored in dams, as well as flowing in rivers to create electricity in hydropower plants.
Specific Weight of Liquid - (Measured in Kilonewton per Cubic Meter) - Specific Weight of Liquid represents the force exerted by gravity on a unit volume of a fluid.
Rate of Flow - (Measured in Cubic Meter per Second) - Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc.
Head loss - (Measured in Meter) - Head loss refers to the total pressure losses sustained by the fluid as it flows from the suction point to the discharge point.
Head of Water - (Measured in Meter) - Head of Water is defined as the height of water columns.
Efficiency of Hydropower - Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy.
STEP 1: Convert Input(s) to Base Unit
Specific Weight of Liquid: 9.81 Kilonewton per Cubic Meter --> 9.81 Kilonewton per Cubic Meter No Conversion Required
Rate of Flow: 32 Cubic Meter per Second --> 32 Cubic Meter per Second No Conversion Required
Head loss: 5 Meter --> 5 Meter No Conversion Required
Head of Water: 2.3 Meter --> 2.3 Meter No Conversion Required
Efficiency of Hydropower: 0.8 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
P = (γf*qflow*(Hl-HWater)*η)/1000 --> (9.81*32*(5-2.3)*0.8)/1000
Evaluating ... ...
P = 0.6780672
STEP 3: Convert Result to Output's Unit
678.0672 Watt -->0.6780672 Kilowatt (Check conversion ​here)
FINAL ANSWER
0.6780672 0.678067 Kilowatt <-- Amount of Hydropower
(Calculation completed in 00.004 seconds)

Credits

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Created by M Naveen
National Institute of Technology (NIT), Warangal
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Verified by Mithila Muthamma PA
Coorg Institute of Technology (CIT), Coorg
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11 Assessment of Available Power Calculators

Head Loss given Energy through Hydraulic Turbines
​ Go Head Loss due to Friction = -((Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave))-Head of Water)
Efficiency of Hydropower Station given Energy through Hydraulic Turbines
​ Go Efficiency of Hydropower = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Time Period of Progressive Wave)
Rate of Flow of Water given Energy through Hydraulic Turbines
​ Go Rate of Flow = Energy through Hydraulic Turbines/(9.81*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower*Time Period of Progressive Wave)
Period of Flow given Energy through Hydraulic Turbines
​ Go Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower)
Head given Energy through Hydraulic Turbines
​ Go Head of Water = (Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave))+Head Loss due to Friction
Energy through Hydraulic Turbines
​ Go Energy through Hydraulic Turbines = (9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower*Time Period of Progressive Wave)
Amount of Hydropower
​ Go Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000
Effective Head given Energy through Hydraulic Turbines
​ Go Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave)
Head Loss given Amount of Hydropower
​ Go Head Loss due to Friction = ((Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))-Head of Water)
Head given Amount of Hydropower
​ Go Head of Water = (Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))+Head Loss due to Friction
Efficiency of Hydropower Station given Amount of Hydropower
​ Go Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water))

Amount of Hydropower Formula

Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000
P = (γf*qflow*(Hl-HWater)*η)/1000

What is meant by Rate of Flow of Water?

The flow rate of a liquid is a measure of the volume of liquid that moves in a certain amount of time. The flow rate depends on the area of the section.

What is Hydropower?

Hydropower, also known as water power, is the use of falling or fast-running water to produce electricity or to power machines. This is achieved by converting the gravitational potential or kinetic energy of a water source to produce electrical or mechanical power.

How to Calculate Amount of Hydropower?

Amount of Hydropower calculator uses Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000 to calculate the Amount of Hydropower, The Amount of Hydropower is defined as a form of renewable energy that uses the water stored in dams, as well as flowing in rivers to create electricity in hydropower plants. Amount of Hydropower is denoted by P symbol.

How to calculate Amount of Hydropower using this online calculator? To use this online calculator for Amount of Hydropower, enter Specific Weight of Liquid f), Rate of Flow (qflow), Head loss (Hl), Head of Water (HWater) & Efficiency of Hydropower (η) and hit the calculate button. Here is how the Amount of Hydropower calculation can be explained with given input values -> 0.000678 = (9810*32*(5-2.3)*0.8)/1000.

FAQ

What is Amount of Hydropower?
The Amount of Hydropower is defined as a form of renewable energy that uses the water stored in dams, as well as flowing in rivers to create electricity in hydropower plants and is represented as P = (γf*qflow*(Hl-HWater)*η)/1000 or Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000. Specific Weight of Liquid represents the force exerted by gravity on a unit volume of a fluid, Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc, Head loss refers to the total pressure losses sustained by the fluid as it flows from the suction point to the discharge point, Head of Water is defined as the height of water columns & Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy.
How to calculate Amount of Hydropower?
The Amount of Hydropower is defined as a form of renewable energy that uses the water stored in dams, as well as flowing in rivers to create electricity in hydropower plants is calculated using Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000. To calculate Amount of Hydropower, you need Specific Weight of Liquid f), Rate of Flow (qflow), Head loss (Hl), Head of Water (HWater) & Efficiency of Hydropower (η). With our tool, you need to enter the respective value for Specific Weight of Liquid, Rate of Flow, Head loss, Head of Water & Efficiency of Hydropower and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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