Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule Calculator

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✖Molar Specific Heat Capacity at Constant Volume, of a gas is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant volume.ⓘ Molar Specific Heat Capacity at Constant Volume [C_v]

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✖The Atomicity is defined as the total number of atoms present in a molecule or element.ⓘ Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule [N]

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Formula

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Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule

Formula

`"N" = (("C"_{"v"}/"[R]")+3)/3`

Example

`"5.129351"=(("103J/K*mol"/"[R]")+3)/3`

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Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule Solution

STEP 0: Pre-Calculation Summary

Formula Used

Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+3)/3
N = ((C_v/[R])+3)/3
This formula uses 1 Constants, 2 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Atomicity - The Atomicity is defined as the total number of atoms present in a molecule or element.
Molar Specific Heat Capacity at Constant Volume - (Measured in Joule Per Kelvin Per Mole) - Molar Specific Heat Capacity at Constant Volume, of a gas is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant volume.

STEP 1: Convert Input(s) to Base Unit

Molar Specific Heat Capacity at Constant Volume: 103 Joule Per Kelvin Per Mole --> 103 Joule Per Kelvin Per Mole No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

N = ((C_v/[R])+3)/3 --> ((103/[R])+3)/3

Evaluating ... ...

N = 5.12935085646693

STEP 3: Convert Result to Output's Unit

5.12935085646693 --> No Conversion Required

FINAL ANSWER

5.12935085646693 ≈ 5.129351 <-- Atomicity

(Calculation completed in 00.004 seconds)

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Home » Chemistry » Kinetic Theory of Gases » Equipartition Principle and Heat Capacity » Atomicity » Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule

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< 22 Atomicity Calculators

Atomicity given Molar Heat Capacity at Constant Pressure and Volume of Linear Molecule

Go Atomicity = ((2.5*( Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-1.5)/((3*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-3)

Atomicity given Molar Heat Capacity at Constant Pressure and Volume of Non-Linear Molecule

Go Atomicity = ((3*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-2)/((3*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-3)

Atomicity given Molar Heat Capacity at Constant Pressure of Linear Molecule

Go Atomicity = (((Molar Specific Heat Capacity at Constant Pressure-[R])/[R])+2.5)/3

Atomicity given Molar Heat Capacity at Constant Pressure of Non-Linear Molecule

Go Atomicity = (((Molar Specific Heat Capacity at Constant Pressure-[R])/[R])+3)/3

Atomicity given Average Thermal Energy of Linear Polyatomic Gas Molecule

Go Atomicity = ((Internal Molar Energy/(0.5*[BoltZ]*Temperature))+5)/6

Atomicity given Internal Molar Energy of Non-Linear Molecule

Go Atomicity = ((Internal Molar Energy/(0.5*[R]*Temperature))+6)/6

Atomicity given Internal Molar Energy of Linear Molecule

Go Atomicity = ((Internal Molar Energy/(0.5*[R]*Temperature))+5)/6

Atomicity given Molar Vibrational Energy of Non-Linear Molecule

Go Atomicity = ((Molar Vibrational Energy/([R]*Temperature))+6)/3

Atomicity given Molar Vibrational Energy of Linear Molecule

Go Atomicity = ((Molar Vibrational Energy/([R]*Temperature))+5)/3

Atomicity given Average Thermal Energy of Non-linear Polyatomic Gas Molecule

Go Atomicity = ((Thermal Energy/(0.5*[BoltZ]*Temperature))+6)/6

Atomicity given Vibrational Energy of Non-Linear Molecule

Go Atomicity = ((Vibrational Energy/([BoltZ]*Temperature))+6)/3

Atomicity given Vibrational Energy of Linear Molecule

Go Atomicity = ((Vibrational Energy/([BoltZ]*Temperature))+5)/3

Atomicity given Ratio of Molar Heat Capacity of Linear Molecule

Go Atomicity = ((2.5*Ratio of Molar Heat Capacity)-1.5)/((3*Ratio of Molar Heat Capacity)-3)

Atomicity given Ratio of Molar Heat Capacity of Non-Linear Molecule

Go Atomicity = ((3*Ratio of Molar Heat Capacity)-2)/((3*Ratio of Molar Heat Capacity)-3)

Atomicity given Molar Heat Capacity at Constant Volume of Linear Molecule

Go Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+2.5)/3

Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule

Go Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+3)/3

Atomicity given Vibrational Mode of Non-Linear Molecule

Go Atomicity = (Number of Normal modes+6)/3

Atomicity given Vibrational Mode of Linear Molecule

Go Atomicity = (Number of Normal modes+5)/3

Atomicity given Vibrational Degree of Freedom in Non-Linear Molecule

Go Atomicity = (Degree of Freedom+6)/3

Atomicity given Vibrational Degree of Freedom in Linear Molecule

Go Atomicity = (Degree of Freedom+5)/3

Atomicity given Number of modes in Non-Linear Molecule

Go Atomicity = (Number of Modes+6)/6

Atomicity given Number of modes in Linear Molecule

Go Atomicity = (Number of Modes+5)/6

Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule Formula

Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+3)/3
N = ((C_v/[R])+3)/3

What is the statement of Equipartition Theorem?

The original concept of equipartition was that the total kinetic energy of a system is shared equally among all of its independent parts, on the average, once the system has reached thermal equilibrium. Equipartition also makes quantitative predictions for these energies. The key point is that the kinetic energy is quadratic in the velocity. The equipartition theorem shows that in thermal equilibrium, any degree of freedom (such as a component of the position or velocity of a particle) which appears only quadratically in the energy has an average energy of 1⁄2kBT and therefore contributes 1⁄2kB to the system's heat capacity.

How to Calculate Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule?

Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule calculator uses Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+3)/3 to calculate the Atomicity, The Atomicity given Molar Heat Capacity at constant volume of Non-Linear Molecule is defined as the total number of atoms present in a molecule of an element. Atomicity is denoted by N symbol.

How to calculate Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule using this online calculator? To use this online calculator for Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule, enter Molar Specific Heat Capacity at Constant Volume (C_v) and hit the calculate button. Here is how the Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule calculation can be explained with given input values -> 5.129351 = ((103/[R])+3)/3.

FAQ

What is Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule?

The Atomicity given Molar Heat Capacity at constant volume of Non-Linear Molecule is defined as the total number of atoms present in a molecule of an element and is represented as N = ((C_v/[R])+3)/3 or Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+3)/3. Molar Specific Heat Capacity at Constant Volume, of a gas is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant volume.

How to calculate Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule?

The Atomicity given Molar Heat Capacity at constant volume of Non-Linear Molecule is defined as the total number of atoms present in a molecule of an element is calculated using Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+3)/3. To calculate Atomicity given Molar Heat Capacity at Constant Volume of Non-Linear Molecule, you need Molar Specific Heat Capacity at Constant Volume (C_v). With our tool, you need to enter the respective value for Molar Specific Heat Capacity at Constant Volume and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Atomicity?

In this formula, Atomicity uses Molar Specific Heat Capacity at Constant Volume. We can use 21 other way(s) to calculate the same, which is/are as follows -

Atomicity = (((Molar Specific Heat Capacity at Constant Pressure-[R])/[R])+2.5)/3
Atomicity = (((Molar Specific Heat Capacity at Constant Pressure-[R])/[R])+3)/3
Atomicity = ((Molar Specific Heat Capacity at Constant Volume/[R])+2.5)/3
Atomicity = ((Internal Molar Energy/(0.5*[BoltZ]*Temperature))+5)/6
Atomicity = ((Thermal Energy/(0.5*[BoltZ]*Temperature))+6)/6
Atomicity = ((Internal Molar Energy/(0.5*[R]*Temperature))+5)/6
Atomicity = ((Internal Molar Energy/(0.5*[R]*Temperature))+6)/6
Atomicity = ((2.5*( Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-1.5)/((3*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-3)
Atomicity = ((3*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-2)/((3*(Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume))-3)
Atomicity = ((Molar Vibrational Energy/([R]*Temperature))+5)/3
Atomicity = ((Molar Vibrational Energy/([R]*Temperature))+6)/3
Atomicity = (Number of Modes+5)/6
Atomicity = (Number of Modes+6)/6
Atomicity = ((2.5*Ratio of Molar Heat Capacity)-1.5)/((3*Ratio of Molar Heat Capacity)-3)
Atomicity = ((3*Ratio of Molar Heat Capacity)-2)/((3*Ratio of Molar Heat Capacity)-3)
Atomicity = (Degree of Freedom+5)/3
Atomicity = (Degree of Freedom+6)/3
Atomicity = ((Vibrational Energy/([BoltZ]*Temperature))+5)/3
Atomicity = ((Vibrational Energy/([BoltZ]*Temperature))+6)/3
Atomicity = (Number of Normal modes+5)/3
Atomicity = (Number of Normal modes+6)/3

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