Coefficient of Transmissibility given Depth of Water in Two Wells Calculator

✖Discharge is the rate of flow of a liquid.ⓘ Discharge [Q]			+10% -10%
✖Depth of water 2 means the depth of the water in 2nd well.ⓘ Depth of Water 2 [h₂]			+10% -10%
✖Depth of water 1 is the depth of water in the 1st considered well.ⓘ Depth of Water 1 [h₁]			+10% -10%
✖Radial Distance at Observation Well 2 is the value of radial distance from well 2 when we have prior information of other parameters used.ⓘ Radial Distance at Observation Well 2 [r₂]			+10% -10%
✖Radial Distance at Well 1 is the value of radial distance from well 1 when we have prior information of other parameters used.ⓘ Radial Distance at Well 1 [r1^']			+10% -10%

✖Coefficient of transmissibility is defined as the rate of flow of water in gallons per day through a vertical strip of the aquifer.ⓘ Coefficient of Transmissibility given Depth of Water in Two Wells [T_envi]

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Coefficient of Transmissibility given Depth of Water in Two Wells

Formula

`"T"_{"envi"} = "Q"/((2.72*("h"_{"2"}-"h"_{"1"}))/(log(("r"_{"2"}/"r1"^{"'"}),10)))`

Example

`"2.578636m²/s"="1.01m³/s"/((2.72*("17.8644m"-"17.85m"))/(log(("10.0m"/"0.000000001m"),10)))`

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Coefficient of Transmissibility given Depth of Water in Two Wells Solution

STEP 0: Pre-Calculation Summary

Formula Used

Coefficient of Transmissibility = Discharge/((2.72*(Depth of Water 2-Depth of Water 1))/(log((Radial Distance at Observation Well 2/Radial Distance at Well 1),10)))
T_envi = Q/((2.72*(h₂-h₁))/(log((r₂/r1^'),10)))
This formula uses 1 Functions, 6 Variables

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Coefficient of Transmissibility - (Measured in Square Meter per Second) - Coefficient of transmissibility is defined as the rate of flow of water in gallons per day through a vertical strip of the aquifer.
Discharge - (Measured in Cubic Meter per Second) - Discharge is the rate of flow of a liquid.
Depth of Water 2 - (Measured in Meter) - Depth of water 2 means the depth of the water in 2nd well.
Depth of Water 1 - (Measured in Meter) - Depth of water 1 is the depth of water in the 1st considered well.
Radial Distance at Observation Well 2 - (Measured in Meter) - Radial Distance at Observation Well 2 is the value of radial distance from well 2 when we have prior information of other parameters used.
Radial Distance at Well 1 - (Measured in Meter) - Radial Distance at Well 1 is the value of radial distance from well 1 when we have prior information of other parameters used.

STEP 1: Convert Input(s) to Base Unit

Discharge: 1.01 Cubic Meter per Second --> 1.01 Cubic Meter per Second No Conversion Required
Depth of Water 2: 17.8644 Meter --> 17.8644 Meter No Conversion Required
Depth of Water 1: 17.85 Meter --> 17.85 Meter No Conversion Required
Radial Distance at Observation Well 2: 10 Meter --> 10 Meter No Conversion Required
Radial Distance at Well 1: 1E-09 Meter --> 1E-09 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

T_envi = Q/((2.72*(h₂-h₁))/(log((r₂/r1^'),10))) --> 1.01/((2.72*(17.8644-17.85))/(log((10/1E-09),10)))

Evaluating ... ...

T_envi = 2.57863562091532

STEP 3: Convert Result to Output's Unit

2.57863562091532 Square Meter per Second --> No Conversion Required

FINAL ANSWER

2.57863562091532 ≈ 2.578636 Square Meter per Second <-- Coefficient of Transmissibility

(Calculation completed in 00.004 seconds)

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Home » Engineering » Civil » Environmental Engineering » Water Resources : Ground Water » Well Hydraulics » Confined Aquifer » Coefficient of Transmissibility » Coefficient of Transmissibility given Depth of Water in Two Wells

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< 5 Coefficient of Transmissibility Calculators

Coefficient of Transmissibility given Discharge

Go Coefficient of Transmissibility = Discharge/((2*pi*(Aquifer Thickness-Depth of Water in Well))/(log((Radius of Influence/Radius of well),e)))

Coefficient of Transmissibility given Depth of Water in Two Wells

Go Coefficient of Transmissibility = Discharge/((2.72*(Depth of Water 2-Depth of Water 1))/(log((Radial Distance at Observation Well 2/Radial Distance at Well 1),10)))

Coefficient of Transmissibility given Confined Aquifer Discharge

Go Coefficient of Transmissibility = Discharge/((2*pi*Total Drawdown in Well)/(log((Radius of Influence/Radius of well),e)))

Coefficient of Transmissibility given Discharge in Confined Aquifer with Base 10

Go Coefficient of Transmissibility = Discharge/((2.72*(Aquifer Thickness-Depth of Water in Well))/(log((Radius of Influence/Radius of well),10)))

Coefficient of Transmissibility given Confined Aquifer Discharge with Base 10

Go Coefficient of Transmissibility = Discharge/((2.72*Total Drawdown in Well in Well Hydraulics)/(log((Radius of Influence/Radius of well),10)))

Coefficient of Transmissibility given Depth of Water in Two Wells Formula

What is Coefficient of Transmissibility?

The coefficient of transmissibility. is defined as the rate of flow of water. in gallons per day through a vertical. strip of the aquifer 1 ft wide and ex- tending the full saturated thickness.

How to Calculate Coefficient of Transmissibility given Depth of Water in Two Wells?

Coefficient of Transmissibility given Depth of Water in Two Wells calculator uses Coefficient of Transmissibility = Discharge/((2.72*(Depth of Water 2-Depth of Water 1))/(log((Radial Distance at Observation Well 2/Radial Distance at Well 1),10))) to calculate the Coefficient of Transmissibility, The Coefficient of Transmissibility given Depth of Water in Two Wells is defined as the value of the coefficient of transmissibility when we have prior information on other parameters used. Coefficient of Transmissibility is denoted by T_envi symbol.

How to calculate Coefficient of Transmissibility given Depth of Water in Two Wells using this online calculator? To use this online calculator for Coefficient of Transmissibility given Depth of Water in Two Wells, enter Discharge (Q), Depth of Water 2 (h₂), Depth of Water 1 (h₁), Radial Distance at Observation Well 2 (r₂) & Radial Distance at Well 1 (r1^') and hit the calculate button. Here is how the Coefficient of Transmissibility given Depth of Water in Two Wells calculation can be explained with given input values -> 2.578636 = 1.01/((2.72*(17.8644-17.85))/(log((10/1E-09),10))).

FAQ

What is Coefficient of Transmissibility given Depth of Water in Two Wells?

The Coefficient of Transmissibility given Depth of Water in Two Wells is defined as the value of the coefficient of transmissibility when we have prior information on other parameters used and is represented as T_envi = Q/((2.72*(h₂-h₁))/(log((r₂/r1^'),10))) or Coefficient of Transmissibility = Discharge/((2.72*(Depth of Water 2-Depth of Water 1))/(log((Radial Distance at Observation Well 2/Radial Distance at Well 1),10))). Discharge is the rate of flow of a liquid, Depth of water 2 means the depth of the water in 2nd well, Depth of water 1 is the depth of water in the 1st considered well, Radial Distance at Observation Well 2 is the value of radial distance from well 2 when we have prior information of other parameters used & Radial Distance at Well 1 is the value of radial distance from well 1 when we have prior information of other parameters used.

How to calculate Coefficient of Transmissibility given Depth of Water in Two Wells?

The Coefficient of Transmissibility given Depth of Water in Two Wells is defined as the value of the coefficient of transmissibility when we have prior information on other parameters used is calculated using Coefficient of Transmissibility = Discharge/((2.72*(Depth of Water 2-Depth of Water 1))/(log((Radial Distance at Observation Well 2/Radial Distance at Well 1),10))). To calculate Coefficient of Transmissibility given Depth of Water in Two Wells, you need Discharge (Q), Depth of Water 2 (h₂), Depth of Water 1 (h₁), Radial Distance at Observation Well 2 (r₂) & Radial Distance at Well 1 (r1^'). With our tool, you need to enter the respective value for Discharge, Depth of Water 2, Depth of Water 1, Radial Distance at Observation Well 2 & Radial Distance at Well 1 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Coefficient of Transmissibility?

In this formula, Coefficient of Transmissibility uses Discharge, Depth of Water 2, Depth of Water 1, Radial Distance at Observation Well 2 & Radial Distance at Well 1. We can use 4 other way(s) to calculate the same, which is/are as follows -

Coefficient of Transmissibility = Discharge/((2*pi*(Aquifer Thickness-Depth of Water in Well))/(log((Radius of Influence/Radius of well),e)))
Coefficient of Transmissibility = Discharge/((2.72*(Aquifer Thickness-Depth of Water in Well))/(log((Radius of Influence/Radius of well),10)))
Coefficient of Transmissibility = Discharge/((2*pi*Total Drawdown in Well)/(log((Radius of Influence/Radius of well),e)))
Coefficient of Transmissibility = Discharge/((2.72*Total Drawdown in Well in Well Hydraulics)/(log((Radius of Influence/Radius of well),10)))

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