Effective thermal conductivity for space between two concentric spheres Solution

STEP 0: Pre-Calculation Summary
Formula Used
Effective Thermal Conductivity = Heat transfer/((pi*(Inside Temperature-Outside Temperature))*((Outside Diameter*Inside Diameter)/Length))
kEff = q/((pi*(ti-to))*((Do*Di)/L))
This formula uses 1 Constants, 7 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Variables Used
Effective Thermal Conductivity - (Measured in Watt per Meter per K) - Effective Thermal Conductivity is the rate of heat transfer through a unit thickness of the material per unit area per unit temperature difference.
Heat transfer - (Measured in Watt) - Heat transfer is defined as the movement of heat across the border of the system due to a difference in temperature between the system and its surroundings.
Inside Temperature - (Measured in Kelvin) - Inside Temperature is the temperature of air present inside.
Outside Temperature - (Measured in Kelvin) - Outside Temperature is the temperature of air present outside.
Outside Diameter - (Measured in Meter) - Outside Diameter is the diameter of the outside surface.
Inside Diameter - (Measured in Meter) - Inside diameter is the diameter of the inside surface.
Length - (Measured in Meter) - Length is the measurement or extent of something from end to end.
STEP 1: Convert Input(s) to Base Unit
Heat transfer: 2 Watt --> 2 Watt No Conversion Required
Inside Temperature: 353 Kelvin --> 353 Kelvin No Conversion Required
Outside Temperature: 273 Kelvin --> 273 Kelvin No Conversion Required
Outside Diameter: 0.05 Meter --> 0.05 Meter No Conversion Required
Inside Diameter: 0.005 Meter --> 0.005 Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
kEff = q/((pi*(ti-to))*((Do*Di)/L)) --> 2/((pi*(353-273))*((0.05*0.005)/3))
Evaluating ... ...
kEff = 95.4929658551372
STEP 3: Convert Result to Output's Unit
95.4929658551372 Watt per Meter per K --> No Conversion Required
FINAL ANSWER
95.4929658551372 95.49297 Watt per Meter per K <-- Effective Thermal Conductivity
(Calculation completed in 00.004 seconds)

Credits

Created by Nishan Poojary
Shri Madhwa Vadiraja Institute of Technology and Management (SMVITM), Udupi
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Verified by Rajat Vishwakarma
University Institute of Technology RGPV (UIT - RGPV), Bhopal
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8 Effective Thermal Conductivity and Heat Transfer Calculators

Effective thermal conductivity for annular space between concentric cylinders
Go Effective Thermal Conductivity = Heat Transfer per Unit Length*((ln(Outside Diameter/Inside Diameter))/(2*pi)*(Inside Temperature-Outside Temperature))
Heat transfer per unit length for annular space between concentric cylinders
Go Heat Transfer per Unit Length = ((2*pi*Effective Thermal Conductivity)/(ln(Outside Diameter/Inside Diameter)))*(Inside Temperature-Outside Temperature)
Effective thermal conductivity for space between two concentric spheres
Go Effective Thermal Conductivity = Heat transfer/((pi*(Inside Temperature-Outside Temperature))*((Outside Diameter*Inside Diameter)/Length))
Heat transfer between concentric spheres given both diameters
Go Heat transfer = (Effective Thermal Conductivity*pi*(Inside Temperature-Outside Temperature))*((Outside Diameter*Inside Diameter)/Length)
Effective thermal conductivity
Go Effective Thermal Conductivity = (Heat transfer*(Outer Radius-Inside Radius))/(4*pi*Inside Radius*Outer Radius*Temperature Difference)
Heat transfer between concentric spheres given both radii
Go Heat transfer = (4*pi*Effective Thermal Conductivity*Inside Radius*Outer Radius*Temperature Difference)/(Outer Radius-Inside Radius)
Effective thermal conductivity given Prandtl number
Go Effective Thermal Conductivity = 0.386*Thermal Conductivity of Liquid*(((Prandtl Number)/(0.861+Prandtl Number))^0.25)*(Rayleigh Number(t))^0.25
Effective Thermal Conductivity given Rayleigh Number based on Turbulence
Go Effective Thermal Conductivity = Thermal Conductivity of Liquid*0.74*((Prandtl Number/(0.861+Prandtl Number))^0.25)*Rayleigh Number(t)^0.25

Effective thermal conductivity for space between two concentric spheres Formula

Effective Thermal Conductivity = Heat transfer/((pi*(Inside Temperature-Outside Temperature))*((Outside Diameter*Inside Diameter)/Length))
kEff = q/((pi*(ti-to))*((Do*Di)/L))

What is convection

Convection is the process of heat transfer by the bulk movement of molecules within fluids such as gases and liquids. The initial heat transfer between the object and the fluid takes place through conduction, but the bulk heat transfer happens due to the motion of the fluid.

Convection is the process of heat transfer in fluids by the actual motion of matter.
It happens in liquids and gases.
It may be natural or forced.
It involves a bulk transfer of portions of the fluid.

How to Calculate Effective thermal conductivity for space between two concentric spheres?

Effective thermal conductivity for space between two concentric spheres calculator uses Effective Thermal Conductivity = Heat transfer/((pi*(Inside Temperature-Outside Temperature))*((Outside Diameter*Inside Diameter)/Length)) to calculate the Effective Thermal Conductivity, The Effective thermal conductivity for space between two concentric spheres formula is defined as defined as transport of energy due to random molecular motion across temperature gradient. Effective Thermal Conductivity is denoted by kEff symbol.

How to calculate Effective thermal conductivity for space between two concentric spheres using this online calculator? To use this online calculator for Effective thermal conductivity for space between two concentric spheres, enter Heat transfer (q), Inside Temperature (ti), Outside Temperature (to), Outside Diameter (Do), Inside Diameter (Di) & Length (L) and hit the calculate button. Here is how the Effective thermal conductivity for space between two concentric spheres calculation can be explained with given input values -> 95.49297 = 2/((pi*(353-273))*((0.05*0.005)/3)).

FAQ

What is Effective thermal conductivity for space between two concentric spheres?
The Effective thermal conductivity for space between two concentric spheres formula is defined as defined as transport of energy due to random molecular motion across temperature gradient and is represented as kEff = q/((pi*(ti-to))*((Do*Di)/L)) or Effective Thermal Conductivity = Heat transfer/((pi*(Inside Temperature-Outside Temperature))*((Outside Diameter*Inside Diameter)/Length)). Heat transfer is defined as the movement of heat across the border of the system due to a difference in temperature between the system and its surroundings, Inside Temperature is the temperature of air present inside, Outside Temperature is the temperature of air present outside, Outside Diameter is the diameter of the outside surface, Inside diameter is the diameter of the inside surface & Length is the measurement or extent of something from end to end.
How to calculate Effective thermal conductivity for space between two concentric spheres?
The Effective thermal conductivity for space between two concentric spheres formula is defined as defined as transport of energy due to random molecular motion across temperature gradient is calculated using Effective Thermal Conductivity = Heat transfer/((pi*(Inside Temperature-Outside Temperature))*((Outside Diameter*Inside Diameter)/Length)). To calculate Effective thermal conductivity for space between two concentric spheres, you need Heat transfer (q), Inside Temperature (ti), Outside Temperature (to), Outside Diameter (Do), Inside Diameter (Di) & Length (L). With our tool, you need to enter the respective value for Heat transfer, Inside Temperature, Outside Temperature, Outside Diameter, Inside Diameter & Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Effective Thermal Conductivity?
In this formula, Effective Thermal Conductivity uses Heat transfer, Inside Temperature, Outside Temperature, Outside Diameter, Inside Diameter & Length. We can use 4 other way(s) to calculate the same, which is/are as follows -
  • Effective Thermal Conductivity = Heat Transfer per Unit Length*((ln(Outside Diameter/Inside Diameter))/(2*pi)*(Inside Temperature-Outside Temperature))
  • Effective Thermal Conductivity = 0.386*Thermal Conductivity of Liquid*(((Prandtl Number)/(0.861+Prandtl Number))^0.25)*(Rayleigh Number(t))^0.25
  • Effective Thermal Conductivity = (Heat transfer*(Outer Radius-Inside Radius))/(4*pi*Inside Radius*Outer Radius*Temperature Difference)
  • Effective Thermal Conductivity = Thermal Conductivity of Liquid*0.74*((Prandtl Number/(0.861+Prandtl Number))^0.25)*Rayleigh Number(t)^0.25
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