Efficiency of Hydropower Station given Amount of Hydropower Solution

STEP 0: Pre-Calculation Summary
Formula Used
Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water))
η = P/(9.81*qflow*(Hl-HWater))
This formula uses 5 Variables
Variables Used
Efficiency of Hydropower - Efficiency of Hydropower is the ratio of useful energy output generated from water flow compared to the input energy.
Amount of Hydropower - (Measured in Watt) - Amount of Hydropower is a form of renewable energy that uses the water stored in dams, as well as flowing in rivers to create electricity in hydropower plants.
Rate of Flow - (Measured in Cubic Meter per Second) - Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc.
Head loss - (Measured in Meter) - Head loss refers to the total pressure losses sustained by the fluid as it flows from the suction point to the discharge point.
Head of Water - (Measured in Meter) - Head of Water is defined as the height of water columns.
STEP 1: Convert Input(s) to Base Unit
Amount of Hydropower: 0.77 Kilowatt --> 770 Watt (Check conversion here)
Rate of Flow: 32 Cubic Meter per Second --> 32 Cubic Meter per Second No Conversion Required
Head loss: 5 Meter --> 5 Meter No Conversion Required
Head of Water: 2.3 Meter --> 2.3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
η = P/(9.81*qflow*(Hl-HWater)) --> 770/(9.81*32*(5-2.3))
Evaluating ... ...
η = 0.908464529769321
STEP 3: Convert Result to Output's Unit
0.908464529769321 --> No Conversion Required
FINAL ANSWER
0.908464529769321 0.908465 <-- Efficiency of Hydropower
(Calculation completed in 00.004 seconds)

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11 Assessment of Available Power Calculators

Head Loss given Energy through Hydraulic Turbines
Go Head Loss due to Friction = -((Energy through Hydraulic Turbines/ (9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave))-Head of Water)
Head given Energy through Hydraulic Turbines
Go Head of Water = (Energy through Hydraulic Turbines/ (9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave))+Head Loss due to Friction
Efficiency of Hydropower Station given Energy through Hydraulic Turbines
Go Efficiency of Hydropower = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Time Period of Progressive Wave)
Rate of Flow of Water given Energy through Hydraulic Turbines
Go Rate of Flow = Energy through Hydraulic Turbines/(9.81*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower*Time Period of Progressive Wave)
Period of Flow given Energy through Hydraulic Turbines
Go Time Period of Progressive Wave = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower)
Energy through Hydraulic Turbines
Go Energy through Hydraulic Turbines = (9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Efficiency of Hydropower*Time Period of Progressive Wave)
Amount of Hydropower
Go Amount of Hydropower = (Specific Weight of Liquid*Rate of Flow*(Head loss-Head of Water)*Efficiency of Hydropower)/1000
Effective Head given Energy through Hydraulic Turbines
Go Effective Head = Energy through Hydraulic Turbines/(9.81*Rate of Flow*Efficiency of Hydropower*Time Period of Progressive Wave)
Head Loss given Amount of Hydropower
Go Head Loss due to Friction = ((Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))-Head of Water)
Head given Amount of Hydropower
Go Head of Water = (Amount of Hydropower/(9.81*Rate of Flow*Efficiency of Hydropower))+Head Loss due to Friction
Efficiency of Hydropower Station given Amount of Hydropower
Go Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water))

Efficiency of Hydropower Station given Amount of Hydropower Formula

Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water))
η = P/(9.81*qflow*(Hl-HWater))

What is meant by Rate of Flow of Water?

The flow rate of a liquid is a measure of the volume of liquid that moves in a certain amount of time. The flow rate depends on the area of the section.

How to Calculate Efficiency of Hydropower Station given Amount of Hydropower?

Efficiency of Hydropower Station given Amount of Hydropower calculator uses Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water)) to calculate the Efficiency of Hydropower, The Efficiency of Hydropower Station given Amount of Hydropower is defined as a fundamental reduction in amount of wasted resources that are used to produce given number of goods or services (output). Efficiency of Hydropower is denoted by η symbol.

How to calculate Efficiency of Hydropower Station given Amount of Hydropower using this online calculator? To use this online calculator for Efficiency of Hydropower Station given Amount of Hydropower, enter Amount of Hydropower (P), Rate of Flow (qflow), Head loss (Hl) & Head of Water (HWater) and hit the calculate button. Here is how the Efficiency of Hydropower Station given Amount of Hydropower calculation can be explained with given input values -> 8.176181 = 770/(9.81*32*(5-2.3)).

FAQ

What is Efficiency of Hydropower Station given Amount of Hydropower?
The Efficiency of Hydropower Station given Amount of Hydropower is defined as a fundamental reduction in amount of wasted resources that are used to produce given number of goods or services (output) and is represented as η = P/(9.81*qflow*(Hl-HWater)) or Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water)). Amount of Hydropower is a form of renewable energy that uses the water stored in dams, as well as flowing in rivers to create electricity in hydropower plants, Rate of Flow is the rate at which a liquid or other substance flows through a particular channel, pipe, etc, Head loss refers to the total pressure losses sustained by the fluid as it flows from the suction point to the discharge point & Head of Water is defined as the height of water columns.
How to calculate Efficiency of Hydropower Station given Amount of Hydropower?
The Efficiency of Hydropower Station given Amount of Hydropower is defined as a fundamental reduction in amount of wasted resources that are used to produce given number of goods or services (output) is calculated using Efficiency of Hydropower = Amount of Hydropower/(9.81*Rate of Flow*(Head loss-Head of Water)). To calculate Efficiency of Hydropower Station given Amount of Hydropower, you need Amount of Hydropower (P), Rate of Flow (qflow), Head loss (Hl) & Head of Water (HWater). With our tool, you need to enter the respective value for Amount of Hydropower, Rate of Flow, Head loss & Head of Water and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Efficiency of Hydropower?
In this formula, Efficiency of Hydropower uses Amount of Hydropower, Rate of Flow, Head loss & Head of Water. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Efficiency of Hydropower = Energy through Hydraulic Turbines/(9.81*Rate of Flow*(Head of Water-Head Loss due to Friction)*Time Period of Progressive Wave)
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