Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Overhead AC Wire)^2/((Maximum Voltage Overhead AC*cos(Phase Difference))^2*Volume of Conductor)
Ploss = ((2+sqrt(2))*P)^2*ρ*(L)^2/((Vm*cos(Φ))^2*V)
This formula uses 2 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Overhead AC line when in use.
Power Transmitted - (Measured in Watt) - Power Transmitted is defined as the product of current and voltage phasor in a overhead ac line at the receiving end.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Overhead AC Wire - (Measured in Meter) - Length of Overhead AC Wire is the total length of the wire from one end to other end.
Maximum Voltage Overhead AC - (Measured in Volt) - Maximum Voltage Overhead AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Volume of Conductor - (Measured in Cubic Meter) - Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 890 Watt --> 890 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Overhead AC Wire: 10.63 Meter --> 10.63 Meter No Conversion Required
Maximum Voltage Overhead AC: 62 Volt --> 62 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Volume of Conductor: 26 Cubic Meter --> 26 Cubic Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Ploss = ((2+sqrt(2))*P)^2*ρ*(L)^2/((Vm*cos(Φ))^2*V) --> ((2+sqrt(2))*890)^2*1.7E-05*(10.63)^2/((62*cos(0.5235987755982))^2*26)
Evaluating ... ...
Ploss = 0.236624026205848
STEP 3: Convert Result to Output's Unit
0.236624026205848 Watt --> No Conversion Required
FINAL ANSWER
0.236624026205848 0.236624 Watt <-- Line Losses
(Calculation completed in 00.004 seconds)

Credits

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15 Wire Parameters Calculators

Length using Volume of Conductor Material (Two-Phase Three-Wire OS)
Go Length of Overhead AC Wire = sqrt(2*Volume of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Overhead AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))
Line Losses using Area of X-Section(Two-Phase Three-Wire OS)
Go Line Losses = (Length of Overhead AC Wire*Resistivity*(Power Transmitted^2)*(2+sqrt(2)))/(2*Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*((cos(Phase Difference))^2))
Length of Wire using Area of X-Section(Two-Phase Three-Wire OS)
Go Length of Overhead AC Wire = 2*Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*Line Losses*((cos(Phase Difference))^2)/((2+sqrt(2))*Resistivity*(Power Transmitted^2))
Area of X-Section(Two-Phase Three-Wire OS)
Go Area of Overhead AC Wire = (2+sqrt(2))*(Power Transmitted^2)*Resistivity*Length of Overhead AC Wire/(((cos(Phase Difference))^2)*2*Line Losses*(Maximum Voltage Overhead AC^2))
Area of X-Section using Line Losses (Two-Phase Three-Wire OS)
Go Area of Overhead AC Wire = (2+sqrt(2))*Resistivity*Length of Overhead AC Wire*(Power Transmitted)^2/(2*Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2)
Length using Line Losses (Two-Phase Three-Wire OS)
Go Length of Overhead AC Wire = 2*Line Losses*Area of Overhead AC Wire*(Maximum Voltage Overhead AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted^2)*Resistivity)
Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS)
Go Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Overhead AC Wire)^2/((Maximum Voltage Overhead AC*cos(Phase Difference))^2*Volume of Conductor)
Constant(Two-Phase Three-Wire OS)
Go Constant Overhead AC = (4*(Power Transmitted^2)*Resistivity*(Length of Overhead AC Wire)^2)/(Line Losses*(Voltage Overhead AC^2))
Area of X-Section using Resistance (Two-Phase Three-Wire OS)
Go Area of Overhead AC Wire = (Resistance Overhead AC*sqrt(2))/(Resistivity*Length of Overhead AC Wire)
Length of Wire using Resistance (Two-Phase Three-Wire OS)
Go Length of Overhead AC Wire = (sqrt(2)*Resistance Overhead AC*Area of Overhead AC Wire)/(Resistivity)
Area of X-Section using Volume of Conductor Material (Two-Phase Three-Wire OS)
Go Area of Overhead AC Wire = Volume of Conductor/((2+sqrt(2))*Length of Overhead AC Wire)
Volume of Conductor Material using Area of X-Section(Two-Phase Three-Wire OS)
Go Volume of Conductor = (2+sqrt(2))*Area of Overhead AC Wire*Length of Overhead AC Wire
Volume of Conductor Material(Two-Phase Three-Wire OS)
Go Volume of Conductor = (2+sqrt(2))*Area of Overhead AC Wire*Length of Overhead AC Wire
Constant using Volume of Conductor Material (Two-Phase Three-Wire OS)
Go Constant Overhead AC = Volume of Conductor*((cos(Phase Difference))^2)/(1.457)
Line Losses(Two-Phase Three-Wire OS)
Go Line Losses = (((Current Overhead AC)^2)*Resistance Overhead AC)*(2+sqrt(2))

Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS) Formula

Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Overhead AC Wire)^2/((Maximum Voltage Overhead AC*cos(Phase Difference))^2*Volume of Conductor)
Ploss = ((2+sqrt(2))*P)^2*ρ*(L)^2/((Vm*cos(Φ))^2*V)

What is the value of maximum voltage and volume of conductor material in 2-phase 3-wire system?

The volume of conductor material required in this system is 1.457/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS)?

Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS) calculator uses Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Overhead AC Wire)^2/((Maximum Voltage Overhead AC*cos(Phase Difference))^2*Volume of Conductor) to calculate the Line Losses, The Line Losses using Volume of Conductor Material (two-phase three-wire OS) formula is defined as the loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by Ploss symbol.

How to calculate Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS) using this online calculator? To use this online calculator for Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS), enter Power Transmitted (P), Resistivity (ρ), Length of Overhead AC Wire (L), Maximum Voltage Overhead AC (Vm), Phase Difference (Φ) & Volume of Conductor (V) and hit the calculate button. Here is how the Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS) calculation can be explained with given input values -> 0.236624 = ((2+sqrt(2))*890)^2*1.7E-05*(10.63)^2/((62*cos(0.5235987755982))^2*26).

FAQ

What is Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS)?
The Line Losses using Volume of Conductor Material (two-phase three-wire OS) formula is defined as the loss of electric energy due to the heating of line wires by the current and is represented as Ploss = ((2+sqrt(2))*P)^2*ρ*(L)^2/((Vm*cos(Φ))^2*V) or Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Overhead AC Wire)^2/((Maximum Voltage Overhead AC*cos(Phase Difference))^2*Volume of Conductor). Power Transmitted is defined as the product of current and voltage phasor in a overhead ac line at the receiving end, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Overhead AC Wire is the total length of the wire from one end to other end, Maximum Voltage Overhead AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit & Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.
How to calculate Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS)?
The Line Losses using Volume of Conductor Material (two-phase three-wire OS) formula is defined as the loss of electric energy due to the heating of line wires by the current is calculated using Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Overhead AC Wire)^2/((Maximum Voltage Overhead AC*cos(Phase Difference))^2*Volume of Conductor). To calculate Line Losses using Volume of Conductor Material (Two-Phase Three-Wire OS), you need Power Transmitted (P), Resistivity (ρ), Length of Overhead AC Wire (L), Maximum Voltage Overhead AC (Vm), Phase Difference (Φ) & Volume of Conductor (V). With our tool, you need to enter the respective value for Power Transmitted, Resistivity, Length of Overhead AC Wire, Maximum Voltage Overhead AC, Phase Difference & Volume of Conductor and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Line Losses?
In this formula, Line Losses uses Power Transmitted, Resistivity, Length of Overhead AC Wire, Maximum Voltage Overhead AC, Phase Difference & Volume of Conductor. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Line Losses = (((Current Overhead AC)^2)*Resistance Overhead AC)*(2+sqrt(2))
  • Line Losses = (Length of Overhead AC Wire*Resistivity*(Power Transmitted^2)*(2+sqrt(2)))/(2*Area of Overhead AC Wire*(Maximum Voltage Overhead AC^2)*((cos(Phase Difference))^2))
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