Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity Solution

STEP 0: Pre-Calculation Summary
Formula Used
Maximum Height = Average Vertical Velocity*Time Interval
hmax = vver*tpr
This formula uses 3 Variables
Variables Used
Maximum Height - (Measured in Meter) - Maximum Height is denoted as the largest distance an object covers in vertical direction in a projectile motion.
Average Vertical Velocity - (Measured in Meter per Second) - Average Vertical Velocity is the average of vertical component of the initial velocity of a projectile and vertical component of final velocity.
Time Interval - (Measured in Second) - Time interval is what a clock reads, it is a scalar quantity.
STEP 1: Convert Input(s) to Base Unit
Average Vertical Velocity: 5.5 Meter per Second --> 5.5 Meter per Second No Conversion Required
Time Interval: 4.25 Second --> 4.25 Second No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
hmax = vver*tpr --> 5.5*4.25
Evaluating ... ...
hmax = 23.375
STEP 3: Convert Result to Output's Unit
23.375 Meter --> No Conversion Required
FINAL ANSWER
23.375 Meter <-- Maximum Height
(Calculation completed in 00.004 seconds)

Credits

Created by Chilvera Bhanu Teja
Institute of Aeronautical Engineering (IARE), Hyderabad
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Verified by Rajat Vishwakarma
University Institute of Technology RGPV (UIT - RGPV), Bhopal
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14 Projectile Motion Calculators

Direction of Projectile at given Height above Point of Projection
Go Direction of Motion of a Particle = atan((sqrt((Initial Velocity of Projectile Motion^2*(sin(Angle of Projection))^2)-2*[g]*Height))/(Initial Velocity of Projectile Motion*cos(Angle of Projection)))
Maximum Height of Projectile on Horizontal Plane
Go Maximum Height = (Initial Velocity of Projectile Motion^2*sin(Angle of Projection)^2)/(2*[g])
Horizontal Range of Projectile
Go Horizontal Range = (Initial Velocity of Projectile Motion^2*sin(2*Angle of Projection))/[g]
Initial Velocity of Particle given Time of Flight of Projectile
Go Initial Velocity of Projectile Motion = ([g]*Time Interval)/(2*sin(Angle of Projection))
Time of Flight of Projectile on Horizontal Plane
Go Time Interval = (2*Initial Velocity of Projectile Motion*sin(Angle of Projection))/[g]
Velocity of Projectile at given Height above Point of Projection
Go Velocity of Projectile = sqrt(Initial Velocity of Projectile Motion^2-2*[g]*Height)
Horizontal Component of Velocity of Particle Projected Upwards from Point at Angle
Go Horizontal Component of Velocity = Initial Velocity of Projectile Motion*cos(Angle of Projection)
Initial Velocity of Particle given Horizontal Component of Velocity
Go Initial Velocity of Projectile Motion = Horizontal Component of Velocity/cos(Angle of Projection)
Vertical Component of Velocity of Particle Projected Upwards from Point at Angle
Go Vertical Component of Velocity = Initial Velocity of Projectile Motion*sin(Angle of Projection)
Initial Velocity of Particle given Vertical Component of Velocity
Go Initial Velocity of Projectile Motion = Vertical Component of Velocity/sin(Angle of Projection)
Initial Velocity given Maximum Horizontal Range of Projectile
Go Initial Velocity of Projectile Motion = sqrt(Maximum Horizontal Range*[g])
Horizontal Range of Projectile given Horizontal Velocity and Time of Flight
Go Horizontal Range = Horizontal Component of Velocity*Time Interval
Maximum Horizontal Range of Projectile
Go Horizontal Range = Initial Velocity of Projectile Motion^2/[g]
Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity
Go Maximum Height = Average Vertical Velocity*Time Interval

Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity Formula

Maximum Height = Average Vertical Velocity*Time Interval
hmax = vver*tpr

What is projectile motion?

When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such a particle is called a projectile and the motion is called projectile motion.

How to Calculate Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity?

Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity calculator uses Maximum Height = Average Vertical Velocity*Time Interval to calculate the Maximum Height, The Maximum height of projectile on horizontal plane given average vertical velocity formula is defined as the product of average vertical velocity and time taken to reach maximum height. Maximum Height is denoted by hmax symbol.

How to calculate Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity using this online calculator? To use this online calculator for Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity, enter Average Vertical Velocity (vver) & Time Interval (tpr) and hit the calculate button. Here is how the Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity calculation can be explained with given input values -> 51 = 5.5*4.25.

FAQ

What is Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity?
The Maximum height of projectile on horizontal plane given average vertical velocity formula is defined as the product of average vertical velocity and time taken to reach maximum height and is represented as hmax = vver*tpr or Maximum Height = Average Vertical Velocity*Time Interval. Average Vertical Velocity is the average of vertical component of the initial velocity of a projectile and vertical component of final velocity & Time interval is what a clock reads, it is a scalar quantity.
How to calculate Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity?
The Maximum height of projectile on horizontal plane given average vertical velocity formula is defined as the product of average vertical velocity and time taken to reach maximum height is calculated using Maximum Height = Average Vertical Velocity*Time Interval. To calculate Maximum Height of Projectile on Horizontal Plane given Average Vertical Velocity, you need Average Vertical Velocity (vver) & Time Interval (tpr). With our tool, you need to enter the respective value for Average Vertical Velocity & Time Interval and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Maximum Height?
In this formula, Maximum Height uses Average Vertical Velocity & Time Interval. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Maximum Height = (Initial Velocity of Projectile Motion^2*sin(Angle of Projection)^2)/(2*[g])
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