Maximum velocity to avoid overturning of vehicle along level circular path Calculator

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General Principal to Dynamics

Engineering Mechanics

Friction

Properties of Planes and Solids

Types of Motion

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Principal Parameters

Laws of Motion

✖Radius of circular path is measure of radius of curved road path.ⓘ Radius of Circular Path [r]			+10% -10%
✖Distance between center lines of two wheels is the length in meters between the center lines of two wheels.ⓘ Distance between Center Lines of two Wheels [d_w]			+10% -10%
✖Gauge of track is the distance between the rails of the track.ⓘ Gauge of Track [G]			+10% -10%

✖Velocity is a vector quantity (it has both magnitude and direction) and is the rate of change of the position of an object with respect to time.ⓘ Maximum velocity to avoid overturning of vehicle along level circular path [v]

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Formula

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Maximum velocity to avoid overturning of vehicle along level circular path

Formula

`"v" = sqrt(("[g]"*"r"*"d"_{"w"})/(2*"G"))`

Example

`"60.64234m/s"=sqrt(("[g]"*"100m"*"1.5m")/(2*"0.2m"))`

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Maximum velocity to avoid overturning of vehicle along level circular path Solution

STEP 0: Pre-Calculation Summary

Formula Used

Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track))
v = sqrt(([g]*r*d_w)/(2*G))
This formula uses 1 Constants, 1 Functions, 4 Variables

Constants Used

[g] - Gravitational acceleration on Earth Value Taken As 9.80665

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Velocity - (Measured in Meter per Second) - Velocity is a vector quantity (it has both magnitude and direction) and is the rate of change of the position of an object with respect to time.
Radius of Circular Path - (Measured in Meter) - Radius of circular path is measure of radius of curved road path.
Distance between Center Lines of two Wheels - (Measured in Meter) - Distance between center lines of two wheels is the length in meters between the center lines of two wheels.
Gauge of Track - (Measured in Meter) - Gauge of track is the distance between the rails of the track.

STEP 1: Convert Input(s) to Base Unit

Radius of Circular Path: 100 Meter --> 100 Meter No Conversion Required
Distance between Center Lines of two Wheels: 1.5 Meter --> 1.5 Meter No Conversion Required
Gauge of Track: 0.2 Meter --> 0.2 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

v = sqrt(([g]*r*d_w)/(2*G)) --> sqrt(([g]*100*1.5)/(2*0.2))

Evaluating ... ...

v = 60.6423428802021

STEP 3: Convert Result to Output's Unit

60.6423428802021 Meter per Second --> No Conversion Required

FINAL ANSWER

60.6423428802021 ≈ 60.64234 Meter per Second <-- Velocity

(Calculation completed in 00.004 seconds)

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Institute of Aeronautical Engineering (IARE), Hyderabad

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University Institute of Technology RGPV (UIT - RGPV), Bhopal

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< 5 Principal Parameters Calculators

Maximum velocity to avoid overturning of vehicle along level circular path

Go Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track))

Force of attraction between two masses separated by distance

Go Gravitational Force of Attraction = ([G.]*Mass of First Particle*Mass of Second Particle)/(Distance between two Masses^2)

Maximum velocity to avoid skidding away of vehicle along level circular path

Go Velocity = sqrt(Coefficient of Friction between Wheels and Ground*[g]*Radius of Circular Path)

Superelevation in railways

Go Superelevation = (Gauge of Track*(Velocity^2))/([g]*Radius of Circular Path)

Angle of banking

Go Angle of Banking = atan((Velocity^2)/([g]*Radius of Circular Path))

Maximum velocity to avoid overturning of vehicle along level circular path Formula

Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track))
v = sqrt(([g]*r*d_w)/(2*G))

What is overturning of a vehicle?

Overturning occurs on the roads when the trucks try to change directions, take sharp turns. Overturning occurs, more after, in case of vehicles which have greater height or whose center of gravity are much high up from the surface of roads.

How to Calculate Maximum velocity to avoid overturning of vehicle along level circular path?

Maximum velocity to avoid overturning of vehicle along level circular path calculator uses Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track)) to calculate the Velocity, The Maximum velocity to avoid overturning of vehicle along level circular path formula is defined as the square root of the ratio of the product of acceleration due to gravity, the radius of the circular path, and distance between center lines of wheels to the height of location of center of gravity. Velocity is denoted by v symbol.

How to calculate Maximum velocity to avoid overturning of vehicle along level circular path using this online calculator? To use this online calculator for Maximum velocity to avoid overturning of vehicle along level circular path, enter Radius of Circular Path (r), Distance between Center Lines of two Wheels (d_w) & Gauge of Track (G) and hit the calculate button. Here is how the Maximum velocity to avoid overturning of vehicle along level circular path calculation can be explained with given input values -> 12.78453 = sqrt(([g]*100*1.5)/(2*0.2)).

FAQ

What is Maximum velocity to avoid overturning of vehicle along level circular path?

The Maximum velocity to avoid overturning of vehicle along level circular path formula is defined as the square root of the ratio of the product of acceleration due to gravity, the radius of the circular path, and distance between center lines of wheels to the height of location of center of gravity and is represented as v = sqrt(([g]*r*d_w)/(2*G)) or Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track)). Radius of circular path is measure of radius of curved road path, Distance between center lines of two wheels is the length in meters between the center lines of two wheels & Gauge of track is the distance between the rails of the track.

How to calculate Maximum velocity to avoid overturning of vehicle along level circular path?

The Maximum velocity to avoid overturning of vehicle along level circular path formula is defined as the square root of the ratio of the product of acceleration due to gravity, the radius of the circular path, and distance between center lines of wheels to the height of location of center of gravity is calculated using Velocity = sqrt(([g]*Radius of Circular Path*Distance between Center Lines of two Wheels)/(2*Gauge of Track)). To calculate Maximum velocity to avoid overturning of vehicle along level circular path, you need Radius of Circular Path (r), Distance between Center Lines of two Wheels (d_w) & Gauge of Track (G). With our tool, you need to enter the respective value for Radius of Circular Path, Distance between Center Lines of two Wheels & Gauge of Track and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Velocity?

In this formula, Velocity uses Radius of Circular Path, Distance between Center Lines of two Wheels & Gauge of Track. We can use 1 other way(s) to calculate the same, which is/are as follows -

Velocity = sqrt(Coefficient of Friction between Wheels and Ground*[g]*Radius of Circular Path)

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