Natural Free Oscillating Period of Basin Calculator

✖Length of the basin is the longest dimension of a basin parallel to its principal drainage channel.ⓘ Length of The Basin [l_B]			+10% -10%
✖Number of nodes along the Axis of a Basin where Basin axis is the lowest point on the basement surface.ⓘ Number of nodes along the Axis of a Basin [N]			+10% -10%
✖Water depth means the depth as measured from the water level to the bottom of the considered water body.ⓘ Water Depth [D]			+10% -10%

✖Natural Free Oscillating Period of a Basin have a period equal to the natural resonant period of the basin which is determined by the basin's geometry and depth.ⓘ Natural Free Oscillating Period of Basin [T_n]

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Formula

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Natural Free Oscillating Period of Basin

Formula

`"T"_{"n"} = (2*"l"_{"B"})/("N"*sqrt("[g]"*"D"))`

Example

`"5.50004s"=(2*"38.782m")/("1.3"*sqrt("[g]"*"12m"))`

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Natural Free Oscillating Period of Basin Solution

STEP 0: Pre-Calculation Summary

Formula Used

Natural Free Oscillating Period of a Basin = (2*Length of The Basin)/(Number of nodes along the Axis of a Basin*sqrt([g]*Water Depth))
T_n = (2*l_B)/(N*sqrt([g]*D))
This formula uses 1 Constants, 1 Functions, 4 Variables

Constants Used

[g] - Gravitational acceleration on Earth Value Taken As 9.80665

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Natural Free Oscillating Period of a Basin - (Measured in Second) - Natural Free Oscillating Period of a Basin have a period equal to the natural resonant period of the basin which is determined by the basin's geometry and depth.
Length of The Basin - (Measured in Meter) - Length of the basin is the longest dimension of a basin parallel to its principal drainage channel.
Number of nodes along the Axis of a Basin - Number of nodes along the Axis of a Basin where Basin axis is the lowest point on the basement surface.
Water Depth - (Measured in Meter) - Water depth means the depth as measured from the water level to the bottom of the considered water body.

STEP 1: Convert Input(s) to Base Unit

Length of The Basin: 38.782 Meter --> 38.782 Meter No Conversion Required
Number of nodes along the Axis of a Basin: 1.3 --> No Conversion Required
Water Depth: 12 Meter --> 12 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

T_n = (2*l_B)/(N*sqrt([g]*D)) --> (2*38.782)/(1.3*sqrt([g]*12))

Evaluating ... ...

T_n = 5.50004046326743

STEP 3: Convert Result to Output's Unit

5.50004046326743 Second --> No Conversion Required

FINAL ANSWER

5.50004046326743 ≈ 5.50004 Second <-- Natural Free Oscillating Period of a Basin

(Calculation completed in 00.004 seconds)

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Created by Mithila Muthamma PA

Coorg Institute of Technology (CIT), Coorg

Mithila Muthamma PA has created this Calculator and 2000+ more calculators!

Verified by Chandana P Dev

NSS College of Engineering (NSSCE), Palakkad

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< 4 Seiches Calculators

Number of Nodes along axis of Basin given Natural Free Oscillating Period of Basin

Go Number of nodes along the Axis of a Basin = (2*Length of The Basin)/(Natural Free Oscillating Period of a Basin*sqrt([g]*Water Depth))

Natural Free Oscillating Period of Basin

Go Natural Free Oscillating Period of a Basin = (2*Length of The Basin)/(Number of nodes along the Axis of a Basin*sqrt([g]*Water Depth))

Length of Basin given Natural Free Oscillating Period of Basin

Go Length of The Basin = (Natural Free Oscillating Period of a Basin*Number of nodes along the Axis of a Basin*sqrt([g]*Water Depth))/2

Water Depth given Natural Free Oscillating Period of Basin

Go Water Depth = ((2*Length of The Basin/(Natural Free Oscillating Period of a Basin*Number of nodes along the Axis of a Basin))^2)/[g]

Natural Free Oscillating Period of Basin Formula

Natural Free Oscillating Period of a Basin = (2*Length of The Basin)/(Number of nodes along the Axis of a Basin*sqrt([g]*Water Depth))
T_n = (2*l_B)/(N*sqrt([g]*D))

What is Seiches?

Seiches are standing waves or oscillations of the free surface of a body of water in a closed or semiclosed basin. These oscillations are of relatively long period, extending from minutes in harbors and bays to over 10 hr in the Great Lakes. Any external perturbation to the lake or embayment can force an oscillation. In harbors, the forcing can be the result of short waves and wave groups at the harbor entrance. Examples include 30- to 400-sec wave-forced oscillations in the Los Angeles-Long Beach harbor (Seabergh 1985).

How to Calculate Natural Free Oscillating Period of Basin?

Natural Free Oscillating Period of Basin calculator uses Natural Free Oscillating Period of a Basin = (2*Length of The Basin)/(Number of nodes along the Axis of a Basin*sqrt([g]*Water Depth)) to calculate the Natural Free Oscillating Period of a Basin, The Natural Free Oscillating Period of Basin formula is defined as the one-dimensional case of closed rectangular basin with vertical walls and uniform depth. Natural Free Oscillating Period of a Basin is denoted by T_n symbol.

How to calculate Natural Free Oscillating Period of Basin using this online calculator? To use this online calculator for Natural Free Oscillating Period of Basin, enter Length of The Basin (l_B), Number of nodes along the Axis of a Basin (N) & Water Depth (D) and hit the calculate button. Here is how the Natural Free Oscillating Period of Basin calculation can be explained with given input values -> 5.50004 = (2*38.782)/(1.3*sqrt([g]*12)).

FAQ

What is Natural Free Oscillating Period of Basin?

The Natural Free Oscillating Period of Basin formula is defined as the one-dimensional case of closed rectangular basin with vertical walls and uniform depth and is represented as T_n = (2*l_B)/(N*sqrt([g]*D)) or Natural Free Oscillating Period of a Basin = (2*Length of The Basin)/(Number of nodes along the Axis of a Basin*sqrt([g]*Water Depth)). Length of the basin is the longest dimension of a basin parallel to its principal drainage channel, Number of nodes along the Axis of a Basin where Basin axis is the lowest point on the basement surface & Water depth means the depth as measured from the water level to the bottom of the considered water body.

How to calculate Natural Free Oscillating Period of Basin?

The Natural Free Oscillating Period of Basin formula is defined as the one-dimensional case of closed rectangular basin with vertical walls and uniform depth is calculated using Natural Free Oscillating Period of a Basin = (2*Length of The Basin)/(Number of nodes along the Axis of a Basin*sqrt([g]*Water Depth)). To calculate Natural Free Oscillating Period of Basin, you need Length of The Basin (l_B), Number of nodes along the Axis of a Basin (N) & Water Depth (D). With our tool, you need to enter the respective value for Length of The Basin, Number of nodes along the Axis of a Basin & Water Depth and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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