What is a Truncated Cuboctahedron?
In geometry, the Truncated Cuboctahedron is an Archimedean solid, named by Kepler as a truncation of a cuboctahedron. It has 26 faces which include 12 square faces, 8 regular hexagonal faces, 6 regular octagonal faces, 48 vertices and 72 edges. And each vertex are identical in such a way that, at each vertex one square, one hexagon and one octagon joins. Since each of its faces has point symmetry (equivalently, 180° rotational symmetry), the Truncated Cuboctahedron is a zonohedron. The Truncated Cuboctahedron can tessellate with the octagonal prism.
How to Calculate Total Surface Area of Truncated Cuboctahedron given Midsphere Radius?
Total Surface Area of Truncated Cuboctahedron given Midsphere Radius calculator uses Total Surface Area of Truncated Cuboctahedron = 12*(2+sqrt(2)+sqrt(3))*((2*Midsphere Radius of Truncated Cuboctahedron)/(sqrt(12+(6*sqrt(2)))))^2 to calculate the Total Surface Area of Truncated Cuboctahedron, Total Surface Area of Truncated Cuboctahedron given Midsphere Radius formula is defined as the total quantity of plane enclosed by the entire surface of the Truncated Cuboctahedron, and calculated using the midsphere radius of the Truncated Cuboctahedron. Total Surface Area of Truncated Cuboctahedron is denoted by TSA symbol.
How to calculate Total Surface Area of Truncated Cuboctahedron given Midsphere Radius using this online calculator? To use this online calculator for Total Surface Area of Truncated Cuboctahedron given Midsphere Radius, enter Midsphere Radius of Truncated Cuboctahedron (rm) and hit the calculate button. Here is how the Total Surface Area of Truncated Cuboctahedron given Midsphere Radius calculation can be explained with given input values -> 5836.289 = 12*(2+sqrt(2)+sqrt(3))*((2*22)/(sqrt(12+(6*sqrt(2)))))^2.