Thermal Conductivity of Cylindrical Wall given Temperature Difference Calculator

✖Heat Flow Rate is the amount of heat that is transferred per unit of time in some material, usually measured in watt. Heat is the flow of thermal energy driven by thermal non-equilibrium.ⓘ Heat Flow Rate [Q]			+10% -10%
✖Radius 2 is the radius of the second concentric circle or circle.ⓘ Radius 2 [r₂]			+10% -10%
✖Radius 1 is the distance from the center of the concentric circles to any point on the first/smallest concentric circle or the radius of the first circle.ⓘ Radius 1 [r₁]			+10% -10%
✖Length of Cylinder is the vertical height of the Cylinder.ⓘ Length of Cylinder [l_cyl]			+10% -10%
✖Inner Surface Temperature is the temperature at the inner surface of the wall either plane wall or cylindrical wall or spherical wall, etc.ⓘ Inner Surface Temperature [T_i]			+10% -10%
✖Outer surface temperature is the temperature at the outer surface of the wall (either plane wall or cylindrical wall or spherical wall, etc).ⓘ Outer Surface Temperature [T_o]			+10% -10%

✖Thermal Conductivity is rate of heat passes through specified material, expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance.ⓘ Thermal Conductivity of Cylindrical Wall given Temperature Difference [k]

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Thermal Conductivity of Cylindrical Wall given Temperature Difference

Formula

`"k" = ("Q"*ln("r"_{"2"}/"r"_{"1"}))/(2*pi*"l"_{"cyl"}*("T"_{"i"}-"T"_{"o"}))`

Example

`"26.93747W/(m*K)"=("125W"*ln("12m"/"0.8m"))/(2*pi*"0.4m"*("305K"-"300K"))`

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Thermal Conductivity of Cylindrical Wall given Temperature Difference Solution

STEP 0: Pre-Calculation Summary

Formula Used

Thermal Conductivity = (Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Length of Cylinder*(Inner Surface Temperature-Outer Surface Temperature))
k = (Q*ln(r₂/r₁))/(2*pi*l_cyl*(T_i-T_o))
This formula uses 1 Constants, 1 Functions, 7 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Functions Used

ln - The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function., ln(Number)

Variables Used

Thermal Conductivity - (Measured in Watt per Meter per K) - Thermal Conductivity is rate of heat passes through specified material, expressed as amount of heat flows per unit time through a unit area with a temperature gradient of one degree per unit distance.
Heat Flow Rate - (Measured in Watt) - Heat Flow Rate is the amount of heat that is transferred per unit of time in some material, usually measured in watt. Heat is the flow of thermal energy driven by thermal non-equilibrium.
Radius 2 - (Measured in Meter) - Radius 2 is the radius of the second concentric circle or circle.
Radius 1 - (Measured in Meter) - Radius 1 is the distance from the center of the concentric circles to any point on the first/smallest concentric circle or the radius of the first circle.
Length of Cylinder - (Measured in Meter) - Length of Cylinder is the vertical height of the Cylinder.
Inner Surface Temperature - (Measured in Kelvin) - Inner Surface Temperature is the temperature at the inner surface of the wall either plane wall or cylindrical wall or spherical wall, etc.
Outer Surface Temperature - (Measured in Kelvin) - Outer surface temperature is the temperature at the outer surface of the wall (either plane wall or cylindrical wall or spherical wall, etc).

STEP 1: Convert Input(s) to Base Unit

Heat Flow Rate: 125 Watt --> 125 Watt No Conversion Required
Radius 2: 12 Meter --> 12 Meter No Conversion Required
Radius 1: 0.8 Meter --> 0.8 Meter No Conversion Required
Length of Cylinder: 0.4 Meter --> 0.4 Meter No Conversion Required
Inner Surface Temperature: 305 Kelvin --> 305 Kelvin No Conversion Required
Outer Surface Temperature: 300 Kelvin --> 300 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

k = (Q*ln(r₂/r₁))/(2*pi*l_cyl*(T_i-T_o)) --> (125*ln(12/0.8))/(2*pi*0.4*(305-300))

Evaluating ... ...

k = 26.9374734779011

STEP 3: Convert Result to Output's Unit

26.9374734779011 Watt per Meter per K --> No Conversion Required

FINAL ANSWER

26.9374734779011 ≈ 26.93747 Watt per Meter per K <-- Thermal Conductivity

(Calculation completed in 00.004 seconds)

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Home » Physics » Heat and Mass Transfer » Conduction » Conduction in Cylinder » Thermal Conductivity of Cylindrical Wall given Temperature Difference

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Created by Sai Venkata Phanindra Chary Arendra

Vallurupalli Nageswara Rao Vignana Jyothi Institute of Engineering and Technology (VNRVJIET), Hyderabad

Sai Venkata Phanindra Chary Arendra has created this Calculator and 100+ more calculators!

Verified by Vinay Mishra

Indian Institute for Aeronautical Engineering and Information Technology (IIAEIT), Pune

Vinay Mishra has verified this Calculator and 100+ more calculators!

< 14 Conduction in Cylinder Calculators

Heat Flow Rate through Cylindrical Composite Wall of 3 Layers

Go Heat Flow Rate = (Inner Surface Temperature-Outer Surface Temperature)/((ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity 1*Length of Cylinder)+(ln(Radius 3/Radius 2))/(2*pi*Thermal Conductivity 2*Length of Cylinder)+(ln(Radius 4/Radius 3))/(2*pi*Thermal Conductivity 3*Length of Cylinder))

Total Thermal Resistance of 3 Cylindrical Resistances Connected in Series

Go Thermal Resistance = (ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity 1*Length of Cylinder)+(ln(Radius 3/Radius 2))/(2*pi*Thermal Conductivity 2*Length of Cylinder)+(ln(Radius 4/Radius 3))/(2*pi*Thermal Conductivity 3*Length of Cylinder)

Total Thermal Resistance of Cylindrical Wall with Convection on Both Sides

Go Thermal Resistance = 1/(2*pi*Radius 1*Length of Cylinder*Inside Convection Heat Transfer Coefficient)+(ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity*Length of Cylinder)+1/(2*pi*Radius 2*Length of Cylinder*External Convection Heat Transfer Coefficient)

Heat Flow Rate through Cylindrical Composite Wall of 2 Layers

Outer Surface Temperature of Cylindrical Composite Wall of 2 Layers

Go Outer Surface Temperature = Inner Surface Temperature-Heat Flow Rate*((ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity 1*Length of Cylinder)+(ln(Radius 3/Radius 2))/(2*pi*Thermal Conductivity 2*Length of Cylinder))

Total Thermal Resistance of 2 Cylindrical Resistances Connected in Series

Go Thermal Resistance = (ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity 1*Length of Cylinder)+(ln(Radius 3/Radius 2))/(2*pi*Thermal Conductivity 2*Length of Cylinder)

Heat Flow Rate through Cylindrical Wall

Go Heat Flow Rate = (Inner Surface Temperature-Outer Surface Temperature)/((ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity*Length of Cylinder))

Thermal Conductivity of Cylindrical Wall given Temperature Difference

Go Thermal Conductivity = (Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Length of Cylinder*(Inner Surface Temperature-Outer Surface Temperature))

Length of Cylindrical Wall for given Heat Flow Rate

Go Length of Cylinder = (Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity*(Inner Surface Temperature-Outer Surface Temperature))

Outer Surface Temperature of Cylindrical Wall given Heat Flow Rate

Go Outer Surface Temperature = Inner Surface Temperature-(Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity*Length of Cylinder)

Inner Surface Temperature of Cylindrical Wall in Conduction

Go Inner Surface Temperature = Outer Surface Temperature+(Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Thermal Conductivity*Length of Cylinder)

Thickness of Cylindrical Wall to Maintain given Temperature Difference

Go Thickness = Radius 1*(e^(((Inner Surface Temperature-Outer Surface Temperature)*2*pi*Thermal Conductivity*Length of Cylinder)/Heat Flow Rate)-1)

Thermal Resistance for Radial Heat Conduction in Cylinders

Go Thermal Resistance = ln(Outer Radius/Inner Radius)/(2*pi*Thermal Conductivity*Length of Cylinder)

Convection Resistance for Cylindrical Layer

Go Thermal Resistance = 1/(Convection heat transfer*2*pi*Cylinder Radius*Length of Cylinder)

Thermal Conductivity of Cylindrical Wall given Temperature Difference Formula

Thermal Conductivity = (Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Length of Cylinder*(Inner Surface Temperature-Outer Surface Temperature))
k = (Q*ln(r₂/r₁))/(2*pi*l_cyl*(T_i-T_o))

What is thermal conductivity

Thermal conductivity can be defined as the rate at which heat is transferred by conduction through a unit cross-section area of a material when a temperature gradient exists perpendicular to the area.

How to Calculate Thermal Conductivity of Cylindrical Wall given Temperature Difference?

Thermal Conductivity of Cylindrical Wall given Temperature Difference calculator uses Thermal Conductivity = (Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Length of Cylinder*(Inner Surface Temperature-Outer Surface Temperature)) to calculate the Thermal Conductivity, The Thermal Conductivity of Cylindrical Wall given Temperature Difference formula is defined as the thermal conductivity of the material of the cylindrical wall required to maintain inner and outer surfaces at given temperatures when the heat flows through it in the radial direction. Thermal Conductivity is denoted by k symbol.

How to calculate Thermal Conductivity of Cylindrical Wall given Temperature Difference using this online calculator? To use this online calculator for Thermal Conductivity of Cylindrical Wall given Temperature Difference, enter Heat Flow Rate (Q), Radius 2 (r₂), Radius 1 (r₁), Length of Cylinder (l_cyl), Inner Surface Temperature (T_i) & Outer Surface Temperature (T_o) and hit the calculate button. Here is how the Thermal Conductivity of Cylindrical Wall given Temperature Difference calculation can be explained with given input values -> 26.93747 = (125*ln(12/0.8))/(2*pi*0.4*(305-300)).

FAQ

What is Thermal Conductivity of Cylindrical Wall given Temperature Difference?

The Thermal Conductivity of Cylindrical Wall given Temperature Difference formula is defined as the thermal conductivity of the material of the cylindrical wall required to maintain inner and outer surfaces at given temperatures when the heat flows through it in the radial direction and is represented as k = (Q*ln(r₂/r₁))/(2*pi*l_cyl*(T_i-T_o)) or Thermal Conductivity = (Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Length of Cylinder*(Inner Surface Temperature-Outer Surface Temperature)). Heat Flow Rate is the amount of heat that is transferred per unit of time in some material, usually measured in watt. Heat is the flow of thermal energy driven by thermal non-equilibrium, Radius 2 is the radius of the second concentric circle or circle, Radius 1 is the distance from the center of the concentric circles to any point on the first/smallest concentric circle or the radius of the first circle, Length of Cylinder is the vertical height of the Cylinder, Inner Surface Temperature is the temperature at the inner surface of the wall either plane wall or cylindrical wall or spherical wall, etc & Outer surface temperature is the temperature at the outer surface of the wall (either plane wall or cylindrical wall or spherical wall, etc).

How to calculate Thermal Conductivity of Cylindrical Wall given Temperature Difference?

The Thermal Conductivity of Cylindrical Wall given Temperature Difference formula is defined as the thermal conductivity of the material of the cylindrical wall required to maintain inner and outer surfaces at given temperatures when the heat flows through it in the radial direction is calculated using Thermal Conductivity = (Heat Flow Rate*ln(Radius 2/Radius 1))/(2*pi*Length of Cylinder*(Inner Surface Temperature-Outer Surface Temperature)). To calculate Thermal Conductivity of Cylindrical Wall given Temperature Difference, you need Heat Flow Rate (Q), Radius 2 (r₂), Radius 1 (r₁), Length of Cylinder (l_cyl), Inner Surface Temperature (T_i) & Outer Surface Temperature (T_o). With our tool, you need to enter the respective value for Heat Flow Rate, Radius 2, Radius 1, Length of Cylinder, Inner Surface Temperature & Outer Surface Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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