Tide-generating attractive Force Potential for Sun Solution

STEP 0: Pre-Calculation Summary
Formula Used
Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2))
Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2))
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Attractive Force Potentials for Sun - The Attractive Force Potentials for sun per unit mass of the Sun.
Universal Constant - Universal Constant in terms of Radius of the Earth and Acceleration of Gravity.
Mass of the Sun - (Measured in Kilogram) - Mass of the Sun [1.989 × 10^30 kg] about 333,000 times the mass of the Earth.
Distance of point - (Measured in Meter) - Distance of point located on the Surface of the Earth to the center of the Sun or the Moon.
Distance - (Measured in Meter) - Distance from center of Earth to center of Sun. if the average radius of the Earth's orbit is 93 million miles (150 million km) then the radius of the Sun's counter orbit is about 280 miles (450 km).
Mean Radius of the Earth - (Measured in Meter) - Mean Radius of the Earth [6,371 km] in terms of Attractive Force Potentials per unit Mass for the Moon.
Angle made by the distance of point - (Measured in Radian) - Angle made by the distance of point located on the Surface of the Earth to the center of the Moon or Sun.
STEP 1: Convert Input(s) to Base Unit
Universal Constant: 2 --> No Conversion Required
Mass of the Sun: 1.989E+30 Kilogram --> 1.989E+30 Kilogram No Conversion Required
Distance of point: 256 Kilometer --> 256000 Meter (Check conversion here)
Distance: 150000000 Kilometer --> 150000000000 Meter (Check conversion here)
Mean Radius of the Earth: 6371 Kilometer --> 6371000 Meter (Check conversion here)
Angle made by the distance of point: 12.5 Degree --> 0.21816615649925 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2)) --> (2*1.989E+30)*((1/256000)-(1/150000000000)-(6371000*cos(0.21816615649925)/150000000000^2))
Evaluating ... ...
Vs = 1.55390359789003E+25
STEP 3: Convert Result to Output's Unit
1.55390359789003E+25 --> No Conversion Required
FINAL ANSWER
1.55390359789003E+25 1.6E+25 <-- Attractive Force Potentials for Sun
(Calculation completed in 00.004 seconds)

Credits

Created by Mithila Muthamma PA
Coorg Institute of Technology (CIT), Coorg
Mithila Muthamma PA has created this Calculator and 2000+ more calculators!
Verified by M Naveen
National Institute of Technology (NIT), Warangal
M Naveen has verified this Calculator and 900+ more calculators!

13 Attractive Force Potentials Calculators

Moon's Tide-generating attractive Force Potential
Go Attractive Force Potentials for Moon = Universal Constant*Mass of the Moon*((1/Distance of point)-(1/Distance from center of Earth to center of Moon)-([Earth-R]*cos(Angle made by the distance of point)/Distance from center of Earth to center of Moon^2))
Tide-generating attractive Force Potential for Sun
Go Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2))
Mean radius of earth given attractive force potentials per unit mass for moon
Go Mean Radius of the Earth = sqrt((Attractive Force Potentials for Moon*Distance from center of Earth to center of Moon^3)/(Universal Constant*Mass of the Moon*Harmonic Polynomial Expansion Terms for Moon))
Attractive Force Potentials per unit Mass for Moon given Harmonic Polynomial Expansion
Go Attractive Force Potentials for Moon = (Universal Constant*Mass of the Moon)*(Mean Radius of the Earth^2/Distance from center of Earth to center of Moon^3)*Harmonic Polynomial Expansion Terms for Moon
Distance from center of earth to center of moon given attractive force potentials
Go Distance from center of Earth to center of Moon = (Mean Radius of the Earth^2*Universal Constant*[Moon-M]*Harmonic Polynomial Expansion Terms for Moon/Attractive Force Potentials for Moon)^(1/3)
Mean radius of earth given attractive force potentials per unit mass for Sun
Go Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun))
Attractive Force Potentials per unit Mass for Sun given Harmonic Polynomial Expansion
Go Attractive Force Potentials for Sun = Universal Constant*Mass of the Sun*(Mean Radius of the Earth^2/Distance^3)*Harmonic Polynomial Expansion Terms for Sun
Mass of Moon given attractive force potentials with harmonic polynomial expansion
Go Mass of the Moon = (Attractive Force Potentials for Moon*Distance from center of Earth to center of Moon^3)/([Earth-R]^2*Universal Constant*Harmonic Polynomial Expansion Terms for Moon)
Mass of Sun given attractive force potentials with harmonic polynomial expansion
Go Mass of the Sun = (Attractive Force Potentials for Sun*Distance^3)/([Earth-R]^2*Universal Constant*Harmonic Polynomial Expansion Terms for Sun)
Attractive Force Potentials per unit Mass for Moon
Go Attractive Force Potentials for Moon = (Universal Constant*Mass of the Moon)/Distance of point
Mass of Moon for Given Attractive Force Potentials
Go Mass of the Moon = (Attractive Force Potentials for Moon*Distance of point)/Universal Constant
Attractive Force Potentials per unit Mass for Sun
Go Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point
Mass of Sun for Given Attractive Force Potentials
Go Mass of the Sun = (Attractive Force Potentials for Sun*Distance of point)/Universal Constant

Tide-generating attractive Force Potential for Sun Formula

Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2))
Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2))

What do you mean by Tidal Force?

The Tidal Force is a gravitational effect that stretches a body along the line towards the center of mass of another body due to a gradient (difference in strength) in gravitational field from the other body; it is responsible for diverse phenomena, including tides, tidal locking, breaking apart of celestial bodies.

How to Calculate Tide-generating attractive Force Potential for Sun?

Tide-generating attractive Force Potential for Sun calculator uses Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2)) to calculate the Attractive Force Potentials for Sun, The Tide-generating attractive Force Potential for Sun at earth's surface is result from combination of force of gravitation exerted by moon (and sun) upon earth; and centrifugal forces produced by revolutions of earth and moon (and earth and sun) around their common center-of-gravity. Attractive Force Potentials for Sun is denoted by Vs symbol.

How to calculate Tide-generating attractive Force Potential for Sun using this online calculator? To use this online calculator for Tide-generating attractive Force Potential for Sun, enter Universal Constant (f), Mass of the Sun (Msun), Distance of point (rS/MX), Distance (rs), Mean Radius of the Earth (RM) & Angle made by the distance of point m/s) and hit the calculate button. Here is how the Tide-generating attractive Force Potential for Sun calculation can be explained with given input values -> 1.6E+25 = (2*1.989E+30)*((1/256000)-(1/150000000000)-(6371000*cos(0.21816615649925)/150000000000^2)).

FAQ

What is Tide-generating attractive Force Potential for Sun?
The Tide-generating attractive Force Potential for Sun at earth's surface is result from combination of force of gravitation exerted by moon (and sun) upon earth; and centrifugal forces produced by revolutions of earth and moon (and earth and sun) around their common center-of-gravity and is represented as Vs = (f*Msun)*((1/rS/MX)-(1/rs)-(RM*cos(θm/s)/rs^2)) or Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2)). Universal Constant in terms of Radius of the Earth and Acceleration of Gravity, Mass of the Sun [1.989 × 10^30 kg] about 333,000 times the mass of the Earth, Distance of point located on the Surface of the Earth to the center of the Sun or the Moon, Distance from center of Earth to center of Sun. if the average radius of the Earth's orbit is 93 million miles (150 million km) then the radius of the Sun's counter orbit is about 280 miles (450 km), Mean Radius of the Earth [6,371 km] in terms of Attractive Force Potentials per unit Mass for the Moon & Angle made by the distance of point located on the Surface of the Earth to the center of the Moon or Sun.
How to calculate Tide-generating attractive Force Potential for Sun?
The Tide-generating attractive Force Potential for Sun at earth's surface is result from combination of force of gravitation exerted by moon (and sun) upon earth; and centrifugal forces produced by revolutions of earth and moon (and earth and sun) around their common center-of-gravity is calculated using Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2)). To calculate Tide-generating attractive Force Potential for Sun, you need Universal Constant (f), Mass of the Sun (Msun), Distance of point (rS/MX), Distance (rs), Mean Radius of the Earth (RM) & Angle made by the distance of point m/s). With our tool, you need to enter the respective value for Universal Constant, Mass of the Sun, Distance of point, Distance, Mean Radius of the Earth & Angle made by the distance of point and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Attractive Force Potentials for Sun?
In this formula, Attractive Force Potentials for Sun uses Universal Constant, Mass of the Sun, Distance of point, Distance, Mean Radius of the Earth & Angle made by the distance of point. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point
  • Attractive Force Potentials for Sun = Universal Constant*Mass of the Sun*(Mean Radius of the Earth^2/Distance^3)*Harmonic Polynomial Expansion Terms for Sun
Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!