Time in Hours given Time at 1st and 2nd Instance since Pumping Started Calculator

✖Discharge is the rate of flow of a liquid.ⓘ Discharge [Q]			+10% -10%
✖Time of Drawdown (t2) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level.ⓘ Time of Drawdown (t2) in Wells [t_2sec]			+10% -10%
✖Time of Drawdown (t1) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level.ⓘ Time of Drawdown (t1) in Wells [t1]			+10% -10%
✖Difference in Drawdowns at the two wells.ⓘ Difference in Drawdowns [Δs]			+10% -10%

✖Time in Hours can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time in Hours given Time at 1st and 2nd Instance since Pumping Started [t_hour]

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Formula

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Time in Hours given Time at 1st and 2nd Instance since Pumping Started

Formula

`"t"_{"hour"} = (2.303*"Q"*log(("t"_{"2sec"}/"t1"),10))/(4*pi*"Δs")`

Example

`"0.154613h"=(2.303*"1.01m³/s"*log(("62s"/"58.7s"),10))/(4*pi*"0.014m")`

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Time in Hours given Time at 1st and 2nd Instance since Pumping Started Solution

STEP 0: Pre-Calculation Summary

Formula Used

Time in Hours = (2.303*Discharge*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Difference in Drawdowns)
t_hour = (2.303*Q*log((t_2sec/t1),10))/(4*pi*Δs)
This formula uses 1 Constants, 1 Functions, 5 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Functions Used

log - Logarithmic function is an inverse function to exponentiation., log(Base, Number)

Variables Used

Time in Hours - (Measured in Second) - Time in Hours can be defined as the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Discharge - (Measured in Cubic Meter per Second) - Discharge is the rate of flow of a liquid.
Time of Drawdown (t2) in Wells - (Measured in Second) - Time of Drawdown (t2) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level.
Time of Drawdown (t1) in Wells - (Measured in Second) - Time of Drawdown (t1) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level.
Difference in Drawdowns - (Measured in Meter) - Difference in Drawdowns at the two wells.

STEP 1: Convert Input(s) to Base Unit

Discharge: 1.01 Cubic Meter per Second --> 1.01 Cubic Meter per Second No Conversion Required
Time of Drawdown (t2) in Wells: 62 Second --> 62 Second No Conversion Required
Time of Drawdown (t1) in Wells: 58.7 Second --> 58.7 Second No Conversion Required
Difference in Drawdowns: 0.014 Meter --> 0.014 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

t_hour = (2.303*Q*log((t_2sec/t1),10))/(4*pi*Δs) --> (2.303*1.01*log((62/58.7),10))/(4*pi*0.014)

Evaluating ... ...

t_hour = 556.606390179623

STEP 3: Convert Result to Output's Unit

556.606390179623 Second -->0.154612886161006 Hour (Check conversion here)

FINAL ANSWER

0.154612886161006 ≈ 0.154613 Hour <-- Time in Hours

(Calculation completed in 00.004 seconds)

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Home » Engineering » Civil » Environmental Engineering » Water Resources : Ground Water » Unsteady Flow » Time of Flow » Time in Hours given Time at 1st and 2nd Instance since Pumping Started

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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< 5 Time of Flow Calculators

Time in Hours given Time at 1st and 2nd Instance since Pumping Started

Go Time in Hours = (2.303*Discharge*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Difference in Drawdowns)

Time at 1st Instance since Pumping Started given Discharge

Go Time of Drawdown (t1) in Wells = Time of Drawdown/10^(Difference in Drawdowns/((2.303*Discharge)/(4*pi*Time in Seconds)))

Time at 2nd Instance since Pumping Started given Discharge

Go Time of Drawdown = Time of Drawdown (t1) in Wells*10^(Difference in Drawdowns/((2.303*Discharge)/(4*pi*Time in Seconds)))

Time given Formation Constant S

Go Time in Days = Formation Constant S/((4*Well Function Constant*Formation Constant T)/(Radial Distance)^2)

Time in Days given Radial Distance

Go Time in Days = Formation Constant S/((2.25*Formation Constant T)/(Radial Distance)^2)

Time in Hours given Time at 1st and 2nd Instance since Pumping Started Formula

Time in Hours = (2.303*Discharge*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Difference in Drawdowns)
t_hour = (2.303*Q*log((t_2sec/t1),10))/(4*pi*Δs)

What is Drawdown?

A drawdown is a peak-to-trough decline during a specific period for an investment, trading account, or fund. A drawdown is usually quoted as the percentage between the peak and the subsequent trough.

How to Calculate Time in Hours given Time at 1st and 2nd Instance since Pumping Started?

Time in Hours given Time at 1st and 2nd Instance since Pumping Started calculator uses Time in Hours = (2.303*Discharge*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Difference in Drawdowns) to calculate the Time in Hours, The Time in Hours given Time at 1st and 2nd Instance since Pumping Started is defined as the value of time in hours when we have prior information of other parameters used. Time in Hours is denoted by t_hour symbol.

How to calculate Time in Hours given Time at 1st and 2nd Instance since Pumping Started using this online calculator? To use this online calculator for Time in Hours given Time at 1st and 2nd Instance since Pumping Started, enter Discharge (Q), Time of Drawdown (t2) in Wells (t_2sec), Time of Drawdown (t1) in Wells (t1) & Difference in Drawdowns (Δs) and hit the calculate button. Here is how the Time in Hours given Time at 1st and 2nd Instance since Pumping Started calculation can be explained with given input values -> 4.3E-5 = (2.303*1.01*log((62/58.7),10))/(4*pi*0.014).

FAQ

What is Time in Hours given Time at 1st and 2nd Instance since Pumping Started?

The Time in Hours given Time at 1st and 2nd Instance since Pumping Started is defined as the value of time in hours when we have prior information of other parameters used and is represented as t_hour = (2.303*Q*log((t_2sec/t1),10))/(4*pi*Δs) or Time in Hours = (2.303*Discharge*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Difference in Drawdowns). Discharge is the rate of flow of a liquid, Time of Drawdown (t2) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level, Time of Drawdown (t1) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level & Difference in Drawdowns at the two wells.

How to calculate Time in Hours given Time at 1st and 2nd Instance since Pumping Started?

The Time in Hours given Time at 1st and 2nd Instance since Pumping Started is defined as the value of time in hours when we have prior information of other parameters used is calculated using Time in Hours = (2.303*Discharge*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Difference in Drawdowns). To calculate Time in Hours given Time at 1st and 2nd Instance since Pumping Started, you need Discharge (Q), Time of Drawdown (t2) in Wells (t_2sec), Time of Drawdown (t1) in Wells (t1) & Difference in Drawdowns (Δs). With our tool, you need to enter the respective value for Discharge, Time of Drawdown (t2) in Wells, Time of Drawdown (t1) in Wells & Difference in Drawdowns and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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