Time of Emptying Tank through Orifice at Bottom Solution

STEP 0: Pre-Calculation Summary
Formula Used
Total Time Taken = (2*Area of Tank*((sqrt(Initial Height of Liquid))-(sqrt(Final Height of Liquid))))/(Coefficient of Discharge*Area of Orifice*sqrt(2*9.81))
ttotal = (2*AT*((sqrt(Hi))-(sqrt(Hf))))/(Cd*a*sqrt(2*9.81))
This formula uses 1 Functions, 6 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Total Time Taken - (Measured in Second) - Total Time Taken is the total time taken by the body to cover that space.
Area of Tank - (Measured in Square Meter) - The Area of tank is a variable from the concept of emptying the tank through orifice.
Initial Height of Liquid - (Measured in Meter) - The Initial height of liquid is a variable from the tank emptying through an orifice at its bottom.
Final Height of Liquid - (Measured in Meter) - The Final height of liquid is a variable from the tank emptying through an orifice at its bottom.
Coefficient of Discharge - The Coefficient of Discharge or efflux coefficient is the ratio of the actual discharge to the theoretical discharge.
Area of Orifice - (Measured in Square Meter) - The Area of Orifice is often a pipe or tube of varying cross-sectional area, and it can be used to direct or modify the flow of a fluid (liquid or gas).
STEP 1: Convert Input(s) to Base Unit
Area of Tank: 1144 Square Meter --> 1144 Square Meter No Conversion Required
Initial Height of Liquid: 24 Meter --> 24 Meter No Conversion Required
Final Height of Liquid: 20.1 Meter --> 20.1 Meter No Conversion Required
Coefficient of Discharge: 0.87 --> No Conversion Required
Area of Orifice: 9.1 Square Meter --> 9.1 Square Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ttotal = (2*AT*((sqrt(Hi))-(sqrt(Hf))))/(Cd*a*sqrt(2*9.81)) --> (2*1144*((sqrt(24))-(sqrt(20.1))))/(0.87*9.1*sqrt(2*9.81))
Evaluating ... ...
ttotal = 27.1207693880146
STEP 3: Convert Result to Output's Unit
27.1207693880146 Second --> No Conversion Required
FINAL ANSWER
27.1207693880146 27.12077 Second <-- Total Time Taken
(Calculation completed in 00.020 seconds)

Credits

Created by Maiarutselvan V
PSG College of Technology (PSGCT), Coimbatore
Maiarutselvan V has created this Calculator and 300+ more calculators!
Vallurupalli Nageswara Rao Vignana Jyothi Institute of Engineering and Technology (VNRVJIET), Hyderabad
Sai Venkata Phanindra Chary Arendra has verified this Calculator and 300+ more calculators!

8 Velocity and Time Calculators

Time of Emptying Hemispherical Tank
Go Total Time Taken = (pi*(((4/3)*Hemispherical Tank Radius*((Initial Height of Liquid^1.5)-(Final Height of Liquid^1.5)))-(0.4*((Initial Height of Liquid^(5/2))-(Final Height of Liquid)^(5/2)))))/(Coefficient of Discharge*Area of Orifice*(sqrt(2*9.81)))
Time of Emptying Circular Horizontal Tank
Go Total Time Taken = (4*Length*((((2*Radius 1)-Final Height of Liquid)^(3/2))-((2*Radius 1)-Initial Height of Liquid)^(3/2)))/(3*Coefficient of Discharge*Area of Orifice*(sqrt(2*9.81)))
Time of Emptying Tank through Orifice at Bottom
Go Total Time Taken = (2*Area of Tank*((sqrt(Initial Height of Liquid))-(sqrt(Final Height of Liquid))))/(Coefficient of Discharge*Area of Orifice*sqrt(2*9.81))
Velocity of liquid at C-C for Hc, Ha, and H
Go Velocity of Liquid Inlet = sqrt(2*9.81*(Atmospheric Pressure Head+Constant Head-Absolute Pressure Head))
Coefficient of velocity for horizontal and vertical distance
Go Coefficient of Velocity = Horizontal Distance/(sqrt(4*Vertical Distance*Head of the Liquid))
Coefficient of Velocity given Head Loss
Go Coefficient of Velocity = sqrt(1-(Head Loss/Head of the Liquid))
Coefficient of velocity
Go Coefficient of Velocity = Actual Velocity/Theoretical Velocity
Theoretical velocity
Go Velocity = sqrt(2*9.81*Pelton Head)

Time of Emptying Tank through Orifice at Bottom Formula

Total Time Taken = (2*Area of Tank*((sqrt(Initial Height of Liquid))-(sqrt(Final Height of Liquid))))/(Coefficient of Discharge*Area of Orifice*sqrt(2*9.81))
ttotal = (2*AT*((sqrt(Hi))-(sqrt(Hf))))/(Cd*a*sqrt(2*9.81))

What is coefficient of discharge?

The coefficient of discharge is defined as the ratio of the actual discharge from an orifice to the theoretical discharge from the orifice.

What is an orifice?

The orifice is defined as the small opening on the side or bottom of a tank through which any kind of fluid is flowing. The opening can be circular, triangular, or rectangular in cross-section and they are named on the basis of shape accordingly.

How to Calculate Time of Emptying Tank through Orifice at Bottom?

Time of Emptying Tank through Orifice at Bottom calculator uses Total Time Taken = (2*Area of Tank*((sqrt(Initial Height of Liquid))-(sqrt(Final Height of Liquid))))/(Coefficient of Discharge*Area of Orifice*sqrt(2*9.81)) to calculate the Total Time Taken, The Time of Emptying Tank through Orifice at Bottom, when considering a tank containing some liquid up to a height of H 1. Let an orifice is fitted at the bottom of the tank. It is required to find the time for the liquid surface to fall from the height H1 to H2. Total Time Taken is denoted by ttotal symbol.

How to calculate Time of Emptying Tank through Orifice at Bottom using this online calculator? To use this online calculator for Time of Emptying Tank through Orifice at Bottom, enter Area of Tank (AT), Initial Height of Liquid (Hi), Final Height of Liquid (Hf), Coefficient of Discharge (Cd) & Area of Orifice (a) and hit the calculate button. Here is how the Time of Emptying Tank through Orifice at Bottom calculation can be explained with given input values -> 27.84932 = (2*1144*((sqrt(24))-(sqrt(20.1))))/(0.87*9.1*sqrt(2*9.81)).

FAQ

What is Time of Emptying Tank through Orifice at Bottom?
The Time of Emptying Tank through Orifice at Bottom, when considering a tank containing some liquid up to a height of H 1. Let an orifice is fitted at the bottom of the tank. It is required to find the time for the liquid surface to fall from the height H1 to H2 and is represented as ttotal = (2*AT*((sqrt(Hi))-(sqrt(Hf))))/(Cd*a*sqrt(2*9.81)) or Total Time Taken = (2*Area of Tank*((sqrt(Initial Height of Liquid))-(sqrt(Final Height of Liquid))))/(Coefficient of Discharge*Area of Orifice*sqrt(2*9.81)). The Area of tank is a variable from the concept of emptying the tank through orifice, The Initial height of liquid is a variable from the tank emptying through an orifice at its bottom, The Final height of liquid is a variable from the tank emptying through an orifice at its bottom, The Coefficient of Discharge or efflux coefficient is the ratio of the actual discharge to the theoretical discharge & The Area of Orifice is often a pipe or tube of varying cross-sectional area, and it can be used to direct or modify the flow of a fluid (liquid or gas).
How to calculate Time of Emptying Tank through Orifice at Bottom?
The Time of Emptying Tank through Orifice at Bottom, when considering a tank containing some liquid up to a height of H 1. Let an orifice is fitted at the bottom of the tank. It is required to find the time for the liquid surface to fall from the height H1 to H2 is calculated using Total Time Taken = (2*Area of Tank*((sqrt(Initial Height of Liquid))-(sqrt(Final Height of Liquid))))/(Coefficient of Discharge*Area of Orifice*sqrt(2*9.81)). To calculate Time of Emptying Tank through Orifice at Bottom, you need Area of Tank (AT), Initial Height of Liquid (Hi), Final Height of Liquid (Hf), Coefficient of Discharge (Cd) & Area of Orifice (a). With our tool, you need to enter the respective value for Area of Tank, Initial Height of Liquid, Final Height of Liquid, Coefficient of Discharge & Area of Orifice and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Total Time Taken?
In this formula, Total Time Taken uses Area of Tank, Initial Height of Liquid, Final Height of Liquid, Coefficient of Discharge & Area of Orifice. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Total Time Taken = (pi*(((4/3)*Hemispherical Tank Radius*((Initial Height of Liquid^1.5)-(Final Height of Liquid^1.5)))-(0.4*((Initial Height of Liquid^(5/2))-(Final Height of Liquid)^(5/2)))))/(Coefficient of Discharge*Area of Orifice*(sqrt(2*9.81)))
  • Total Time Taken = (4*Length*((((2*Radius 1)-Final Height of Liquid)^(3/2))-((2*Radius 1)-Initial Height of Liquid)^(3/2)))/(3*Coefficient of Discharge*Area of Orifice*(sqrt(2*9.81)))
Let Others Know
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!