Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume of Conductor = (2*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC*cos(Phase Difference)^2)
V = (2*ρ*P^2*L^2)/(Ploss*Vm*cos(Φ)^2)
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Volume of Conductor - (Measured in Cubic Meter) - Volume of Conductor is the total volume of the material used to make the conductor of an overhead ac line.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Power Transmitted - (Measured in Watt) - Power Transmitted is defined as the product of current and voltage phasor in a overhead ac line at the receiving end.
Length of Overhead AC Wire - (Measured in Meter) - Length of Overhead AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Overhead AC line when in use.
Maximum Voltage Overhead AC - (Measured in Volt) - Maximum Voltage Overhead AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 890 Watt --> 890 Watt No Conversion Required
Length of Overhead AC Wire: 10.63 Meter --> 10.63 Meter No Conversion Required
Line Losses: 8.23 Watt --> 8.23 Watt No Conversion Required
Maximum Voltage Overhead AC: 62 Volt --> 62 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (2*ρ*P^2*L^2)/(Ploss*Vm*cos(Φ)^2) --> (2*1.7E-05*890^2*10.63^2)/(8.23*62*cos(0.5235987755982)^2)
Evaluating ... ...
V = 7.95193225064346
STEP 3: Convert Result to Output's Unit
7.95193225064346 Cubic Meter --> No Conversion Required
FINAL ANSWER
7.95193225064346 7.951932 Cubic Meter <-- Volume of Conductor
(Calculation completed in 00.004 seconds)

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12 Wire Parameters Calculators

Length of Wire using Area of X-Section(Single Phase Two Wire Mid-Point Earthed OS)
Go Length of Overhead AC Wire = (Area of Overhead AC Wire*Maximum Voltage Overhead AC^2*Line Losses*cos(Phase Difference)^2)/(Resistivity*Power Transmitted^2)
Line Losses using Area of X-Section(Single Phase Two Wire Mid-Point Earthed OS)
Go Line Losses = (Length of Overhead AC Wire*Resistivity*Power Transmitted^2)/(Area of Overhead AC Wire*Maximum Voltage Overhead AC^2*cos(Phase Difference)^2)
Area of X-Section using Line Losses (Single Phase Two Wire Mid-Point OS)
Go Area of Overhead AC Wire = (Resistivity*Length of Overhead AC Wire*Power Transmitted^2)/(Line Losses*(Maximum Voltage Overhead AC*cos(Phase Difference))^2)
Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS)
Go Volume of Conductor = (2*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC*cos(Phase Difference)^2)
Area of X-Section(Single Phase Two Wire Mid-Point Earthed)
Go Area of Overhead AC Wire = (Power Transmitted^2*Resistivity*Length of Overhead AC Wire)/(((cos(Phase Difference))^2)*Line Losses*Voltage Overhead AC^2)
Constant using Load Current (Single Phase Two Wire Mid-Point OS)
Go Constant Overhead AC = (8*Current Overhead AC^2*cos(Phase Difference)^2*Resistivity*Length of Overhead AC Wire^2)/Line Losses
Constant using Line Losses (Single Phase Two Wire Mid-Point OS)
Go Constant Overhead AC = (4*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC^2)
Constant (Single Phase Two Wire Mid-Point Earthed)
Go Constant Overhead AC = (4*Power Transmitted^2*Resistivity*Length of Overhead AC Wire)/(Line Losses*Voltage Overhead AC^2)
Length using Load Current (Single Phase Two-Wire Mid-Point OS)
Go Length of Overhead AC Wire = (Line Losses*Area of Overhead AC Wire)/(2*(Current Overhead AC)^2*Resistivity)
Volume of Conductor Material using Load Current (Single Phase Two Wire Mid-Point OS)
Go Volume of Conductor = (4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses)
Area of X-Section using Load Current (Single Phase Two Wire Mid-Point OS)
Go Area of Overhead AC Wire = (2*Current Overhead AC^2*Resistivity*Length of Overhead AC Wire)/(Line Losses)
Line Losses using Load Current (Single Phase Two Wire Mid-Point OS)
Go Line Losses = 2*Current Overhead AC^2*Resistance Overhead AC

Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS) Formula

Volume of Conductor = (2*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC*cos(Phase Difference)^2)
V = (2*ρ*P^2*L^2)/(Ploss*Vm*cos(Φ)^2)

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 1/2cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is 2vm so that r.m.s. value of voltage between them is √2vm.

How to Calculate Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS)?

Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS) calculator uses Volume of Conductor = (2*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC*cos(Phase Difference)^2) to calculate the Volume of Conductor, The Volume of Conductor Material using Line Losses (single Phase two Wire Mid-Point OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire mid-point earthed overhead system. Volume of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS) using this online calculator? To use this online calculator for Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS), enter Resistivity (ρ), Power Transmitted (P), Length of Overhead AC Wire (L), Line Losses (Ploss), Maximum Voltage Overhead AC (Vm) & Phase Difference (Φ) and hit the calculate button. Here is how the Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS) calculation can be explained with given input values -> 7.951932 = (2*1.7E-05*890^2*10.63^2)/(8.23*62*cos(0.5235987755982)^2).

FAQ

What is Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS)?
The Volume of Conductor Material using Line Losses (single Phase two Wire Mid-Point OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire mid-point earthed overhead system and is represented as V = (2*ρ*P^2*L^2)/(Ploss*Vm*cos(Φ)^2) or Volume of Conductor = (2*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC*cos(Phase Difference)^2). Resistivity is the measure of how strongly a material opposes the flow of current through them, Power Transmitted is defined as the product of current and voltage phasor in a overhead ac line at the receiving end, Length of Overhead AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Overhead AC line when in use, Maximum Voltage Overhead AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS)?
The Volume of Conductor Material using Line Losses (single Phase two Wire Mid-Point OS) formula is defined as the 3-dimensional space enclosed by a conductor material of a single-phase two-wire mid-point earthed overhead system is calculated using Volume of Conductor = (2*Resistivity*Power Transmitted^2*Length of Overhead AC Wire^2)/(Line Losses*Maximum Voltage Overhead AC*cos(Phase Difference)^2). To calculate Volume of Conductor Material using Line Losses (Single Phase Two Wire Mid-Point OS), you need Resistivity (ρ), Power Transmitted (P), Length of Overhead AC Wire (L), Line Losses (Ploss), Maximum Voltage Overhead AC (Vm) & Phase Difference (Φ). With our tool, you need to enter the respective value for Resistivity, Power Transmitted, Length of Overhead AC Wire, Line Losses, Maximum Voltage Overhead AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume of Conductor?
In this formula, Volume of Conductor uses Resistivity, Power Transmitted, Length of Overhead AC Wire, Line Losses, Maximum Voltage Overhead AC & Phase Difference. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Volume of Conductor = (4*(Current Overhead AC^2)*Resistivity*(Length of Overhead AC Wire^2))/(Line Losses)
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