Volume of Conductor Material using Resistance (2 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)
V = ((2+sqrt(2))^2*(P^2)*R*A*L)/(Ploss*(Vm^2)*(cos(Φ))^2)
This formula uses 2 Functions, 8 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistance Underground AC - (Measured in Ohm) - Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistance Underground AC: 5 Ohm --> 5 Ohm No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = ((2+sqrt(2))^2*(P^2)*R*A*L)/(Ploss*(Vm^2)*(cos(Φ))^2) --> ((2+sqrt(2))^2*(300^2)*5*1.28*24)/(2.67*(230^2)*(cos(0.5235987755982))^2)
Evaluating ... ...
V = 1521.20202435975
STEP 3: Convert Result to Output's Unit
1521.20202435975 Cubic Meter --> No Conversion Required
FINAL ANSWER
1521.20202435975 1521.202 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.019 seconds)

Credits

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17 Wire Parameters Calculators

Volume of Conductor Material using Resistance (2 Phase 3 Wire US)
Go Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)
Angle of Pf using Line Losses (2-Phase 3-Wire US)
Go Phase Difference = acos((2+(sqrt(2)*Power Transmitted/Maximum Voltage Underground AC))*(sqrt(Resistivity*Length of Underground AC Wire/Line Losses*Area of Underground AC Wire)))
Length using Volume of Conductor Material (2 Phase 3 Wire US)
Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))
Volume of Conductor Material (2 Phase 3 Wire US)
Go Volume Of Conductor = ((2+sqrt(2))^2)*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Area of X-Section using Line Losses (2-Phase 3-Wire US)
Go Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Length using Line Losses (2-Phase 3-Wire US)
Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted^2)*Resistivity)
Line Losses using Volume of Conductor Material (2 Phase 3 Wire US)
Go Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)
Volume of Conductor Material using Area and Length(2 Phase 3 Wire US)
Go Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire)
Volume of Conductor Material using Load Current (2 Phase 3 Wire US)
Go Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
Angle using Current in Neutral Wire (2-Phase 3-Wire US)
Go Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))
Length using Resistance of Natural Wire (2-Phase 3-Wire US)
Go Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity)
Area using Resistance of Natural Wire (2-Phase 3-Wire US)
Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/(sqrt(2)*Resistance Underground AC)
Angle using Current in Each Outer (2-Phase 3-Wire US)
Go Phase Difference = acos(Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))
Angle of PF using Volume of Conductor Material (2 Phase 3 Wire US)
Go Phase Difference = acos(sqrt((2.914)*Constant Underground AC/Volume Of Conductor))
Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)
Go Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)
Constant using Volume of Conductor Material (2 Phase 3 Wire US)
Go Constant Underground AC = Volume Of Conductor*((cos(Phase Difference))^2)/(2.914)
Volume of Conductor Material using Constant(2 Phase 3 Wire US)
Go Volume Of Conductor = 2.194*Constant Underground AC/(cos(Phase Difference)^2)

Volume of Conductor Material using Resistance (2 Phase 3 Wire US) Formula

Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)
V = ((2+sqrt(2))^2*(P^2)*R*A*L)/(Ploss*(Vm^2)*(cos(Φ))^2)

What is the volume of conductor material in 2-phase 3-wire underground system?

The volume of conductor material required in this system is 2.914/cos2θ times that of 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Resistance (2 Phase 3 Wire US)?

Volume of Conductor Material using Resistance (2 Phase 3 Wire US) calculator uses Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2) to calculate the Volume Of Conductor, The Volume of Conductor Material using Resistance (2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Resistance (2 Phase 3 Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Resistance (2 Phase 3 Wire US), enter Power Transmitted (P), Resistance Underground AC (R), Area of Underground AC Wire (A), Length of Underground AC Wire (L), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ) and hit the calculate button. Here is how the Volume of Conductor Material using Resistance (2 Phase 3 Wire US) calculation can be explained with given input values -> 1521.202 = ((2+sqrt(2))^2*(300^2)*5*1.28*24)/(2.67*(230^2)*(cos(0.5235987755982))^2).

FAQ

What is Volume of Conductor Material using Resistance (2 Phase 3 Wire US)?
The Volume of Conductor Material using Resistance (2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system and is represented as V = ((2+sqrt(2))^2*(P^2)*R*A*L)/(Ploss*(Vm^2)*(cos(Φ))^2) or Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistance Underground AC is defined as the property of the wire or line that opposes the flow of current through it, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Length of Underground AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Volume of Conductor Material using Resistance (2 Phase 3 Wire US)?
The Volume of Conductor Material using Resistance (2 phase 3 wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a 2-phase 3-wire underground system is calculated using Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2). To calculate Volume of Conductor Material using Resistance (2 Phase 3 Wire US), you need Power Transmitted (P), Resistance Underground AC (R), Area of Underground AC Wire (A), Length of Underground AC Wire (L), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ). With our tool, you need to enter the respective value for Power Transmitted, Resistance Underground AC, Area of Underground AC Wire, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Power Transmitted, Resistance Underground AC, Area of Underground AC Wire, Length of Underground AC Wire, Line Losses, Maximum Voltage Underground AC & Phase Difference. We can use 4 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire)
  • Volume Of Conductor = 2.194*Constant Underground AC/(cos(Phase Difference)^2)
  • Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
  • Volume Of Conductor = ((2+sqrt(2))^2)*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
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