Volume of Conductor Material using Resistance (DC Two-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2))
V = (4*(P^2)*R1*A*l)/(Pline*(Vm^2))
This formula uses 7 Variables
Variables Used
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistance underground DC - (Measured in Ohm) - Resistance underground DC is defined as the time rate of flow of charge through a cross-sectional area.
Area of underground dc wire - (Measured in Square Meter) - The Area of underground dc wire is the amount of two-dimensional space taken up by an object.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.
Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Maximum Voltage - (Measured in Volt) - Maximum Voltage the highest voltage rating for electrical devices.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistance underground DC: 5 Ohm --> 5 Ohm No Conversion Required
Area of underground dc wire: 0.32 Square Meter --> 0.32 Square Meter No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
V = (4*(P^2)*R1*A*l)/(Pline*(Vm^2)) --> (4*(300^2)*5*0.32*3.2)/(0.6*(60^2))
Evaluating ... ...
V = 853.333333333333
STEP 3: Convert Result to Output's Unit
853.333333333333 Cubic Meter --> No Conversion Required
FINAL ANSWER
853.333333333333 853.3333 Cubic Meter <-- Volume Of Conductor
(Calculation completed in 00.004 seconds)

Credits

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Vishwakarma Government Engineering College (VGEC), Ahmedabad
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10+ Wire Parameters Calculators

Volume of Conductor Material using Resistance (DC Two-Wire US)
Go Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2))
Length using Area of X-Section (DC Two-Wire US)
Go Length of Wire DC = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*Resistivity*(Power Transmitted^2))
Area of X-Section (DC Two-Wire US)
Go Area of underground dc wire = 2*(Power Transmitted^2)*Resistivity*Length of Wire DC/(Line Losses*(Maximum Voltage^2))
Line Losses (DC Two-Wire US)
Go Line Losses = 2*(Power Transmitted^2)*Resistivity*Length of Wire DC/((Maximum Voltage^2)*Area of underground dc wire)
Volume of Conductor Material (DC Two-Wire US)
Go Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
Line Losses using Area of X-Section(DC Two-Wire US)
Go Line Losses = 2*(Current underground DC^2)*Resistivity*Length of Wire DC/(Area of underground dc wire)
Length using Line Losses (DC Two-Wire US)
Go Length of Wire DC = Area of underground dc wire*Line Losses/(2*Resistivity*(Current underground DC^2))
Volume of Conductor Material using Load Current (DC Two-Wire US)
Go Volume Of Conductor = 4*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses
Line Losses using Resistance (DC Two-Wire US)
Go Line Losses = 2*(Power Transmitted^2)*Resistance underground DC/((Maximum Voltage^2))
Volume of Conductor Material using Area and Length(DC Two-Wire US)
Go Volume Of Conductor = Area of underground dc wire*Length of Wire DC*2

Volume of Conductor Material using Resistance (DC Two-Wire US) Formula

Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2))
V = (4*(P^2)*R1*A*l)/(Pline*(Vm^2))

What is the volume of conductor material in DC Two-Wire underground system?

The volume of conductor material required in this system is 1 times that of a 2-wire d.c.system with the one conductor earthed.

How to Calculate Volume of Conductor Material using Resistance (DC Two-Wire US)?

Volume of Conductor Material using Resistance (DC Two-Wire US) calculator uses Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2)) to calculate the Volume Of Conductor, The Volume of Conductor Material using Resistance (DC Two-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC Two-Wire underground system. Volume Of Conductor is denoted by V symbol.

How to calculate Volume of Conductor Material using Resistance (DC Two-Wire US) using this online calculator? To use this online calculator for Volume of Conductor Material using Resistance (DC Two-Wire US), enter Power Transmitted (P), Resistance underground DC (R1), Area of underground dc wire (A), Length of Wire DC (l), Line Losses (Pline) & Maximum Voltage (Vm) and hit the calculate button. Here is how the Volume of Conductor Material using Resistance (DC Two-Wire US) calculation can be explained with given input values -> 853.3333 = (4*(300^2)*5*0.32*3.2)/(0.6*(60^2)).

FAQ

What is Volume of Conductor Material using Resistance (DC Two-Wire US)?
The Volume of Conductor Material using Resistance (DC Two-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC Two-Wire underground system and is represented as V = (4*(P^2)*R1*A*l)/(Pline*(Vm^2)) or Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2)). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Resistance underground DC is defined as the time rate of flow of charge through a cross-sectional area, The Area of underground dc wire is the amount of two-dimensional space taken up by an object, Length of Wire DC is the measurement or extent of something from end to end, Line Losses is defined as the losses that are produced in the line & Maximum Voltage the highest voltage rating for electrical devices.
How to calculate Volume of Conductor Material using Resistance (DC Two-Wire US)?
The Volume of Conductor Material using Resistance (DC Two-Wire US) formula is defined as the 3-dimensional space enclosed by a conductor material of a DC Two-Wire underground system is calculated using Volume Of Conductor = (4*(Power Transmitted^2)*Resistance underground DC*Area of underground dc wire*Length of Wire DC)/(Line Losses*(Maximum Voltage^2)). To calculate Volume of Conductor Material using Resistance (DC Two-Wire US), you need Power Transmitted (P), Resistance underground DC (R1), Area of underground dc wire (A), Length of Wire DC (l), Line Losses (Pline) & Maximum Voltage (Vm). With our tool, you need to enter the respective value for Power Transmitted, Resistance underground DC, Area of underground dc wire, Length of Wire DC, Line Losses & Maximum Voltage and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Volume Of Conductor?
In this formula, Volume Of Conductor uses Power Transmitted, Resistance underground DC, Area of underground dc wire, Length of Wire DC, Line Losses & Maximum Voltage. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Volume Of Conductor = Area of underground dc wire*Length of Wire DC*2
  • Volume Of Conductor = 4*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses
  • Volume Of Conductor = 4*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
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