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Absolute viscosity in terms of loss of liquid head Solution

STEP 0: Pre-Calculation Summary
Formula Used
absolute_viscosity_of_oil = Loss of liquid head*2*[g]*Density*(Outside diameter of seal ring)^2/(64*Velocity)
μ = hμ*2*[g]*ρ*(d1)^2/(64*v)
This formula uses 1 Constants, 4 Variables
Constants Used
[g] - Gravitational acceleration on Earth Value Taken As 9.80665 Meter/Second²
Variables Used
Loss of liquid head - Loss of liquid head is a measure of the reduction in the total head of the fluid as it moves through a fluid system. Head loss is unavoidable in real fluids. (Measured in Meter)
Density - The density of a material shows the denseness of that material in a specific given area. This is taken as mass per unit volume of a given object. (Measured in Kilogram per Meter³)
Outside diameter of seal ring - Outside diameter of seal ring is any straight line segment that passes through the center of the ring and whose endpoints lie on the ring. (Measured in Meter)
Velocity - Velocity, in physics, is a vector quantity (it has both magnitude and direction), and is the time rate of change of position (of an object). (Measured in Meter per Second)
STEP 1: Convert Input(s) to Base Unit
Loss of liquid head: 1 Meter --> 1 Meter No Conversion Required
Density: 997 Kilogram per Meter³ --> 997 Kilogram per Meter³ No Conversion Required
Outside diameter of seal ring: 12 Meter --> 12 Meter No Conversion Required
Velocity: 60 Meter per Second --> 60 Meter per Second No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
μ = hμ*2*[g]*ρ*(d1)^2/(64*v) --> 1*2*[g]*997*(12)^2/(64*60)
Evaluating ... ...
μ = 733.29225375
STEP 3: Convert Result to Output's Unit
733.29225375 Pascal Second -->733.29225375 Newton Second per Meter² (Check conversion here)
FINAL ANSWER
733.29225375 Newton Second per Meter² <-- Absolute Viscosity of Oil
(Calculation completed in 00.005 seconds)

10+ Straight cut sealings Calculators

Radius in terms of leakage velocity
radius = sqrt((Velocity*8*Incremental length in the direction of Velocity*Viscosity of oil)/(Change in pressure)) Go
Outer diameter of seal ring in terms of loss of liquid head
outside_diameter_of_seal_ring = sqrt((64*Viscosity of oil*Velocity)/(2*[g]*Density*Loss of liquid head)) Go
Change in pressure in terms of leakage velocity
change_in_pressure = (Velocity*8*(Incremental length in the direction of Velocity)*Viscosity of oil)/((Radius)^2) Go
Absolute viscosity in terms of loss of liquid head
absolute_viscosity_of_oil = Loss of liquid head*2*[g]*Density*(Outside diameter of seal ring)^2/(64*Velocity) Go
Absolute viscosity in terms of leakage velocity
viscosity_of_oil = (Change in pressure)*(Radius)^2/(8*Incremental length in the direction of Velocity*Velocity) Go
Density of liquid in terms of loss of liquid head
density = (64*Viscosity of oil*Velocity)/(2*[g]*Loss of liquid head*(Outside diameter of seal ring)^2) Go
Loss of liquid head
loss_of_liquid_head = (64*Viscosity of oil*Velocity)/(2*[g]*Density*(Outside diameter of seal ring)^2) Go
Leakage velocity
velocity = (Change in pressure)*(Radius)^2/(8*(Incremental length in the direction of velocity)*Viscosity of oil) Go
Incremental length in direction of velocity terms of leakage velocity
incremental_length_in_direction_of_velocity = (Change in pressure)*(Radius)^2/(8*(Velocity)*Viscosity of oil) Go
Incremental length in direction of velocity
incremental_length_in_direction_of_velocity = (Change in pressure)*(Radius)^2/(8*(Velocity)*Viscosity of oil) Go

Absolute viscosity in terms of loss of liquid head Formula

absolute_viscosity_of_oil = Loss of liquid head*2*[g]*Density*(Outside diameter of seal ring)^2/(64*Velocity)
μ = hμ*2*[g]*ρ*(d1)^2/(64*v)

What is Absolute viscosity?

Absolute viscosity is the tangential force per unit area required to move one horizontal plane with respect to an other plane - at an unit velocity - when maintaining an unit distance apart in the fluid.

How to Calculate Absolute viscosity in terms of loss of liquid head?

Absolute viscosity in terms of loss of liquid head calculator uses absolute_viscosity_of_oil = Loss of liquid head*2*[g]*Density*(Outside diameter of seal ring)^2/(64*Velocity) to calculate the Absolute Viscosity of Oil, The Absolute viscosity in terms of loss of liquid head formula is defined as the viscous or laminar flow. Absolute Viscosity of Oil is denoted by μ symbol.

How to calculate Absolute viscosity in terms of loss of liquid head using this online calculator? To use this online calculator for Absolute viscosity in terms of loss of liquid head, enter Loss of liquid head (hμ), Density (ρ), Outside diameter of seal ring (d1) & Velocity (v) and hit the calculate button. Here is how the Absolute viscosity in terms of loss of liquid head calculation can be explained with given input values -> 733.2923 = 1*2*[g]*997*(12)^2/(64*60).

FAQ

What is Absolute viscosity in terms of loss of liquid head?
The Absolute viscosity in terms of loss of liquid head formula is defined as the viscous or laminar flow and is represented as μ = hμ*2*[g]*ρ*(d1)^2/(64*v) or absolute_viscosity_of_oil = Loss of liquid head*2*[g]*Density*(Outside diameter of seal ring)^2/(64*Velocity). Loss of liquid head is a measure of the reduction in the total head of the fluid as it moves through a fluid system. Head loss is unavoidable in real fluids, The density of a material shows the denseness of that material in a specific given area. This is taken as mass per unit volume of a given object, Outside diameter of seal ring is any straight line segment that passes through the center of the ring and whose endpoints lie on the ring & Velocity, in physics, is a vector quantity (it has both magnitude and direction), and is the time rate of change of position (of an object).
How to calculate Absolute viscosity in terms of loss of liquid head?
The Absolute viscosity in terms of loss of liquid head formula is defined as the viscous or laminar flow is calculated using absolute_viscosity_of_oil = Loss of liquid head*2*[g]*Density*(Outside diameter of seal ring)^2/(64*Velocity). To calculate Absolute viscosity in terms of loss of liquid head, you need Loss of liquid head (hμ), Density (ρ), Outside diameter of seal ring (d1) & Velocity (v). With our tool, you need to enter the respective value for Loss of liquid head, Density, Outside diameter of seal ring & Velocity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Absolute Viscosity of Oil?
In this formula, Absolute Viscosity of Oil uses Loss of liquid head, Density, Outside diameter of seal ring & Velocity. We can use 10 other way(s) to calculate the same, which is/are as follows -
  • loss_of_liquid_head = (64*Viscosity of oil*Velocity)/(2*[g]*Density*(Outside diameter of seal ring)^2)
  • absolute_viscosity_of_oil = Loss of liquid head*2*[g]*Density*(Outside diameter of seal ring)^2/(64*Velocity)
  • outside_diameter_of_seal_ring = sqrt((64*Viscosity of oil*Velocity)/(2*[g]*Density*Loss of liquid head))
  • density = (64*Viscosity of oil*Velocity)/(2*[g]*Loss of liquid head*(Outside diameter of seal ring)^2)
  • velocity = (Change in pressure)*(Radius)^2/(8*(Incremental length in the direction of velocity)*Viscosity of oil)
  • incremental_length_in_direction_of_velocity = (Change in pressure)*(Radius)^2/(8*(Velocity)*Viscosity of oil)
  • change_in_pressure = (Velocity*8*(Incremental length in the direction of Velocity)*Viscosity of oil)/((Radius)^2)
  • radius = sqrt((Velocity*8*Incremental length in the direction of Velocity*Viscosity of oil)/(Change in pressure))
  • incremental_length_in_direction_of_velocity = (Change in pressure)*(Radius)^2/(8*(Velocity)*Viscosity of oil)
  • viscosity_of_oil = (Change in pressure)*(Radius)^2/(8*Incremental length in the direction of Velocity*Velocity)
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