Activation Energy given Slope of Line between Log K and Temp Inverse Solution

STEP 0: Pre-Calculation Summary
Formula Used
Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T
Ea = -2.303*[R]*m
This formula uses 1 Constants, 2 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324
Variables Used
Activation Energy - (Measured in Joule Per Mole) - Activation Energy is the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation.
Slope of Line Between Log K and 1/T - (Measured in Kelvin) - Slope of line Between Log K and 1/T is defined as the graph between logk versus 1/T is a straight line. The graph between logk versus 1/T is a straight line.
STEP 1: Convert Input(s) to Base Unit
Slope of Line Between Log K and 1/T: -345 Kelvin --> -345 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Ea = -2.303*[R]*m --> -2.303*[R]*(-345)
Evaluating ... ...
Ea = 6606.13155631438
STEP 3: Convert Result to Output's Unit
6606.13155631438 Joule Per Mole --> No Conversion Required
FINAL ANSWER
6606.13155631438 6606.132 Joule Per Mole <-- Activation Energy
(Calculation completed in 00.004 seconds)

Credits

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National Institute Of Technology Warangal (NITW), Warangal
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6 Temperature Coefficient Calculators

Rate Constant at Temperature 2
Go Rate Constant at Temperature 2 = ((Rate Constant at Temperature 1)*(Temperature Coefficient)^((Temperature 2-Temperature 1)/10))
Temperature Coefficient using Activation Energy
Go Temperature Coefficient = e^(Enthalpy of Activation*((1/Temperature 1)-(1/Temperature 2)))
Fraction of Total No. of Molecules Undergoing Chemical Reaction
Go Fraction of Total No. of Effective Collision = (Rate Constant/Pre-Exponential Factor)
Temperature Coefficient using Rate Constant
Go Temperature Coefficient = Rate Constant at (T+10)°C/Rate Constant at T° C
Activation Energy given Slope of Line between Log K and Temp Inverse
Go Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T
Activation Energy given Slope of Line between LnK and Temperature Inverse
Go Activation Energy = -(Slope of Line B/w Ln K and 1/T*[R])

Activation Energy given Slope of Line between Log K and Temp Inverse Formula

Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T
Ea = -2.303*[R]*m

What is Activation Energy ?

Activation Energy, is the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo a chemical transformation or physical transport.

How to Calculate Activation Energy given Slope of Line between Log K and Temp Inverse?

Activation Energy given Slope of Line between Log K and Temp Inverse calculator uses Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T to calculate the Activation Energy, Activation Energy given Slope of Line between Log K and Temp Inverse has defined that the graph between LogK versus 1/T is a straight line. The plot between Log K vs 1/T will give slope −Ea/2.303R. Activation Energy is denoted by Ea symbol.

How to calculate Activation Energy given Slope of Line between Log K and Temp Inverse using this online calculator? To use this online calculator for Activation Energy given Slope of Line between Log K and Temp Inverse, enter Slope of Line Between Log K and 1/T (m) and hit the calculate button. Here is how the Activation Energy given Slope of Line between Log K and Temp Inverse calculation can be explained with given input values -> 6606.132 = -2.303*[R]*(-345).

FAQ

What is Activation Energy given Slope of Line between Log K and Temp Inverse?
Activation Energy given Slope of Line between Log K and Temp Inverse has defined that the graph between LogK versus 1/T is a straight line. The plot between Log K vs 1/T will give slope −Ea/2.303R and is represented as Ea = -2.303*[R]*m or Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T. Slope of line Between Log K and 1/T is defined as the graph between logk versus 1/T is a straight line. The graph between logk versus 1/T is a straight line.
How to calculate Activation Energy given Slope of Line between Log K and Temp Inverse?
Activation Energy given Slope of Line between Log K and Temp Inverse has defined that the graph between LogK versus 1/T is a straight line. The plot between Log K vs 1/T will give slope −Ea/2.303R is calculated using Activation Energy = -2.303*[R]*Slope of Line Between Log K and 1/T. To calculate Activation Energy given Slope of Line between Log K and Temp Inverse, you need Slope of Line Between Log K and 1/T (m). With our tool, you need to enter the respective value for Slope of Line Between Log K and 1/T and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Activation Energy?
In this formula, Activation Energy uses Slope of Line Between Log K and 1/T. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Activation Energy = -(Slope of Line B/w Ln K and 1/T*[R])
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