Angle of Dip Calculator

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✖Horizontal Component of Earth's Magnetic Field Vector is denoted by the symbol B_H.ⓘ Horizontal Component of Earth's Magnetic Field [B_H]			+10% -10%
✖Net Earth's Magnetic Field is the total Earth's Magnetic Field Vector.ⓘ Net Earth's Magnetic Field [B_net]			+10% -10%

✖Angle of Dip is the angle that the earth's magnetic field total vector makes with respect to the horizontal plane and is positive for vectors below the plane.ⓘ Angle of Dip [δ]

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Formula

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Angle of Dip

Formula

`"δ" = arccos("B"_{"H"}/"B"_{"net"})`

Example

`"60°"=arccos("0.00002Wb/m²"/"0.00004Wb/m²")`

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Download Magnetic Field due to Current Formulas PDF

Angle of Dip Solution

STEP 0: Pre-Calculation Summary

Formula Used

Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field)
δ = arccos(B_H/B_net)
This formula uses 2 Functions, 3 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
arccos - Arccosine function, is the inverse function of the cosine function.It is the function that takes a ratio as an input and returns the angle whose cosine is equal to that ratio., arccos(Number)

Variables Used

Angle of Dip - (Measured in Radian) - Angle of Dip is the angle that the earth's magnetic field total vector makes with respect to the horizontal plane and is positive for vectors below the plane.
Horizontal Component of Earth's Magnetic Field - (Measured in Tesla) - Horizontal Component of Earth's Magnetic Field Vector is denoted by the symbol B_H.
Net Earth's Magnetic Field - (Measured in Tesla) - Net Earth's Magnetic Field is the total Earth's Magnetic Field Vector.

STEP 1: Convert Input(s) to Base Unit

Horizontal Component of Earth's Magnetic Field: 2E-05 Weber per Square Meter --> 2E-05 Tesla (Check conversion here)
Net Earth's Magnetic Field: 4E-05 Weber per Square Meter --> 4E-05 Tesla (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

δ = arccos(B_H/B_net) --> arccos(2E-05/4E-05)

Evaluating ... ...

δ = 1.0471975511966

STEP 3: Convert Result to Output's Unit

1.0471975511966 Radian -->60.0000000000113 Degree (Check conversion here)

FINAL ANSWER

60.0000000000113 ≈ 60 Degree <-- Angle of Dip

(Calculation completed in 00.004 seconds)

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Credits

Created by Venkata Sai Prasanna Aradhyula

Birla Institute of Technology & Science (BITS), Hyderabad

Venkata Sai Prasanna Aradhyula has created this Calculator and 10+ more calculators!

Verified by Mona Gladys

St Joseph's College (SJC), Bengaluru

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< 15 Magnetic Field due to Current Calculators

Magnetic Field due to Straight Conductor

Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(4*pi*Perpendicular Distance)*(cos(Theta 1)-cos(Theta 2))

Magnetic Field for Tangent Galvanometer

Go Horizontal Component of Earth's Magnetic Field = ([Permeability-vacuum]*Number of Turns of Coil*Electric Current)/(2*Radius of Ring*tan(Angle of Deflection of Galvanometer))

Force between Parallel Wires

Go Magnetic Force per Unit Length = ([Permeability-vacuum]*Electric Current in Conductor 1*Electric Current in Conductor 2)/(2*pi*Perpendicular Distance)

Current in Moving Coil Galvanometer

Go Electric Current = (Spring Constant*Angle of Deflection of Galvanometer)/(Number of Turns of Coil*Cross-Sectional Area*Magnetic Field)

Magnetic Field on Axis of Ring

Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Radius of Ring^2)/(2*(Radius of Ring^2+Perpendicular Distance^2)^(3/2))

Time Period of Magnetometer

Go Time Period of Magnetometer = 2*pi*sqrt(Moment of Inertia/(Magnetic Moment*Horizontal Component of Earth's Magnetic Field))

Magnetic Field at Center of Arc

Go Field at Center of Arc = ([Permeability-vacuum]*Electric Current*Angle Obtained by Arc at Center)/(4*pi*Radius of Ring)

Field of Bar Magnet at Equatorial position

Go Field at Equitorial Position of Bar Magnet = ([Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)

Field of Bar Magnet at Axial position

Go Field at Axial Position of Bar Magnet = (2*[Permeability-vacuum]*Magnetic Moment)/(4*pi*Distance from Center to Point^3)

Field Inside Solenoid

Go Magnetic Field = ([Permeability-vacuum]*Electric Current*Number of Turns)/Length of Solonoid

Magnetic Field Due to Infinite Straight Wire

Go Magnetic Field = ([Permeability-vacuum]*Electric Current)/(2*pi*Perpendicular Distance)

Electric Current for Tangent Galvanometer

Go Electric Current = Reduction Factor of Tangent Galvanometer*tan(Angle of Deflection of Galvanometer)

Angle of Dip

Go Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field)

Magnetic Field at Center of Ring

Go Field at Center of Ring = ([Permeability-vacuum]*Electric Current)/(2*Radius of Ring)

Magnetic Permeability

Go Magnetic Permeability of Medium = Magnetic Field/Magnetic Field Intensity

Angle of Dip Formula

Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field)
δ = arccos(B_H/B_net)

What is the angle of dip?

The Angle of Dip formula is defined as the angle that the earth's magnetic field total vector makes with respect to the horizontal plane and is positive for vectors below the plane.

How to Calculate Angle of Dip?

Angle of Dip calculator uses Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field) to calculate the Angle of Dip, The angle of dip δ is calculated by using B_H = B*cosδ where B_H is the Horizontal component of the earth's magnetic field and B is the earth's magnetic field. Angle of Dip is denoted by δ symbol.

How to calculate Angle of Dip using this online calculator? To use this online calculator for Angle of Dip, enter Horizontal Component of Earth's Magnetic Field (B_H) & Net Earth's Magnetic Field (B_net) and hit the calculate button. Here is how the Angle of Dip calculation can be explained with given input values -> 3437.747 = arccos(2E-05/4E-05).

FAQ

What is Angle of Dip?

The angle of dip δ is calculated by using B_H = B*cosδ where B_H is the Horizontal component of the earth's magnetic field and B is the earth's magnetic field and is represented as δ = arccos(B_H/B_net) or Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field). Horizontal Component of Earth's Magnetic Field Vector is denoted by the symbol B_H & Net Earth's Magnetic Field is the total Earth's Magnetic Field Vector.

How to calculate Angle of Dip?

The angle of dip δ is calculated by using B_H = B*cosδ where B_H is the Horizontal component of the earth's magnetic field and B is the earth's magnetic field is calculated using Angle of Dip = arccos(Horizontal Component of Earth's Magnetic Field/Net Earth's Magnetic Field). To calculate Angle of Dip, you need Horizontal Component of Earth's Magnetic Field (B_H) & Net Earth's Magnetic Field (B_net). With our tool, you need to enter the respective value for Horizontal Component of Earth's Magnetic Field & Net Earth's Magnetic Field and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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