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Area of a Rhombus when diagonals are given Solution

STEP 0: Pre-Calculation Summary
Formula Used
area = (Diagonal A*Diagonal B)/2
A = (da*db)/2
This formula uses 2 Variables
Variables Used
Diagonal A - Diagonal A is a straight line joining two opposite corners of a square, rectangle, or another straight-sided shape. (Measured in Meter)
Diagonal B - Diagonal B is a straight line joining two opposite corners of a square, rectangle, or another straight-sided shape. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Diagonal A: 5 Meter --> 5 Meter No Conversion Required
Diagonal B: 7 Meter --> 7 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
A = (da*db)/2 --> (5*7)/2
Evaluating ... ...
A = 17.5
STEP 3: Convert Result to Output's Unit
17.5 Square Meter --> No Conversion Required
FINAL ANSWER
17.5 Square Meter <-- Area
(Calculation completed in 00.016 seconds)

11 Other formulas that you can solve using the same Inputs

Lateral side(height) of right trapezoid given diagonals, bases and angle A between diagonals
side_c = ((Diagonal A*Diagonal B)/(Base A+Base B))*sin(Angle A) Go
Lateral side(height) of right trapezoid given diagonals, bases and angle B between diagonals
side_c = ((Diagonal A*Diagonal B)/(Base A+Base B))*sin(Angle B) Go
Perimeter of a parallelogram when side a and diagonals are given
perimeter = 2*Side A+sqrt(2*(Diagonal A)^2+2*(Diagonal B)^2-4*(Side A)^2) Go
Midline of right trapezoid given diagonals, height and angle B between diagonals
midline_of_trapezoid = ((Diagonal A*Diagonal B)/(2*Height))*sin(Angle B) Go
Midline of right trapezoid given diagonals, height and angle A between diagonals
midline_of_trapezoid = ((Diagonal A*Diagonal B)/2*Height)*sin(Angle A) Go
Area of a Rhombus when side and diagonals are given
area = (1/2)*(Diagonal A)*(sqrt(4*Side^2-(Diagonal A)^2)) Go
Largest Diagonal of parallelogram from smallest diagonal
diagonal_a = sqrt(2*Side A^2+2*Side B^2-Diagonal B^2) Go
Smallest Diagonal of parallelogram from largest diagonal
diagonal_b = sqrt(Side A^2+Side B^2-Diagonal A^2) Go
Diagonal of a parallelogram when the area, other diagonal and angle between diagonals are given
diagonal_b = (2*Area)/(Diagonal A*sin(Theta)) Go
Diagonal of a parallelogram when the area, diagonal, and angles between diagonals are given
diagonal_a = (2*Area)/(Diagonal B*sin(Theta)) Go
Side of a Rhombus
side = (sqrt(Diagonal A^2+Diagonal B^2))/2 Go

11 Other formulas that calculate the same Output

Area of a Triangle when sides are given
area = sqrt((Side A+Side B+Side C)*(Side B+Side C-Side A)*(Side A-Side B+Side C)*(Side A+Side B-Side C))/4 Go
Area of a Rhombus when side and diagonals are given
area = (1/2)*(Diagonal A)*(sqrt(4*Side^2-(Diagonal A)^2)) Go
Area of a Rectangle when breadth and diagonal are given
area = Breadth*(sqrt((Diagonal)^2-(Breadth)^2)) Go
Area of a Rectangle when length and diagonal are given
area = Length*(sqrt((Diagonal)^2-(Length)^2)) Go
Area of a Trapezoid
area = ((Base A+Base B)/2)*Height Go
Area of a Hexagon
area = (3/2)*sqrt(3)*Side^2 Go
Area of a Triangle when base and height are given
area = 1/2*Base*Height Go
Area of a Rectangle when length and breadth are given
area = Length*Breadth Go
Area of a Parallelogram when base and height are given
area = Base*Height Go
Area of a Square when diagonal is given
area = 1/2*(Diagonal)^2 Go
Area of a Square when side is given
area = (Side A)^2 Go

Area of a Rhombus when diagonals are given Formula

area = (Diagonal A*Diagonal B)/2
A = (da*db)/2

How to Calculate Area of a Rhombus when diagonals are given?

Area of a Rhombus when diagonals are given calculator uses area = (Diagonal A*Diagonal B)/2 to calculate the Area, The area of a rhombus when diagonals are given can be defined as the amount of space enclosed by a rhombus in a two-dimensional space with given diagonals. Area and is denoted by A symbol.

How to calculate Area of a Rhombus when diagonals are given using this online calculator? To use this online calculator for Area of a Rhombus when diagonals are given, enter Diagonal A (da) and Diagonal B (db) and hit the calculate button. Here is how the Area of a Rhombus when diagonals are given calculation can be explained with given input values -> 17.5 = (5*7)/2.

FAQ

What is Area of a Rhombus when diagonals are given?
The area of a rhombus when diagonals are given can be defined as the amount of space enclosed by a rhombus in a two-dimensional space with given diagonals and is represented as A = (da*db)/2 or area = (Diagonal A*Diagonal B)/2. Diagonal A is a straight line joining two opposite corners of a square, rectangle, or another straight-sided shape and Diagonal B is a straight line joining two opposite corners of a square, rectangle, or another straight-sided shape.
How to calculate Area of a Rhombus when diagonals are given?
The area of a rhombus when diagonals are given can be defined as the amount of space enclosed by a rhombus in a two-dimensional space with given diagonals is calculated using area = (Diagonal A*Diagonal B)/2. To calculate Area of a Rhombus when diagonals are given, you need Diagonal A (da) and Diagonal B (db). With our tool, you need to enter the respective value for Diagonal A and Diagonal B and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Area?
In this formula, Area uses Diagonal A and Diagonal B. We can use 11 other way(s) to calculate the same, which is/are as follows -
  • area = 1/2*Base*Height
  • area = sqrt((Side A+Side B+Side C)*(Side B+Side C-Side A)*(Side A-Side B+Side C)*(Side A+Side B-Side C))/4
  • area = Length*Breadth
  • area = Length*(sqrt((Diagonal)^2-(Length)^2))
  • area = Breadth*(sqrt((Diagonal)^2-(Breadth)^2))
  • area = (Side A)^2
  • area = 1/2*(Diagonal)^2
  • area = (1/2)*(Diagonal A)*(sqrt(4*Side^2-(Diagonal A)^2))
  • area = Base*Height
  • area = ((Base A+Base B)/2)*Height
  • area = (3/2)*sqrt(3)*Side^2
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