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Area of pentagon of Truncated Rhombohedron given volume Solution

STEP 0: Pre-Calculation Summary
Formula Used
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*Volume)/(5*(sqrt(sqrt(5)-2))))^(2/3))
A5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*V)/(5*(sqrt(sqrt(5)-2))))^(2/3))
This formula uses 1 Functions, 1 Variables
Functions Used
sqrt - Squre root function, sqrt(Number)
Variables Used
Volume - Volume is the amount of space that a substance or object occupies or that is enclosed within a container. (Measured in Cubic Meter)
STEP 1: Convert Input(s) to Base Unit
Volume: 63 Cubic Meter --> 63 Cubic Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
A5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*V)/(5*(sqrt(sqrt(5)-2))))^(2/3)) --> ((sqrt(5+(2*sqrt(5))))/4)*(((3*63)/(5*(sqrt(sqrt(5)-2))))^(2/3))
Evaluating ... ...
A5 = 14.0220919369919
STEP 3: Convert Result to Output's Unit
14.0220919369919 Square Meter --> No Conversion Required
FINAL ANSWER
14.0220919369919 Square Meter <-- Area 5
(Calculation completed in 00.000 seconds)

7 Area of pentagon of Truncated Rhombohedron Calculators

Area of pentagon of Truncated Rhombohedron given surface to volume ratio
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*((((3*(sqrt(5+(2*sqrt(5)))))+(5*sqrt(3))-(2*sqrt(15)))/(2*(5/3)*(sqrt(sqrt(5)-2))*Surface to Volume Ratio))^2) Go
Area of pentagon of Truncated Rhombohedron given surface area
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*((2*Surface Area Polyhedron)/((3*(sqrt(5+(2*sqrt(5)))))+(5*sqrt(3))-(2*sqrt(15)))) Go
Area of pentagon of Truncated Rhombohedron given circumradius
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((4*Circumradius)/(sqrt(14-(2*sqrt(5)))))^2) Go
Area of pentagon of Truncated Rhombohedron given volume
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*Volume)/(5*(sqrt(sqrt(5)-2))))^(2/3)) Go
Area of pentagon of Truncated Rhombohedron given edge length of triangle
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*((Side C/(sqrt(5-(2*sqrt(5)))))^2) Go
Area of pentagon of Truncated Rhombohedron given edge length
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((2*Side B)/(3-sqrt(5)))^2) Go
Area of pentagon of Truncated Rhombohedron given edge length of rhombohedron
area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(Side A^2) Go

Area of pentagon of Truncated Rhombohedron given volume Formula

area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*Volume)/(5*(sqrt(sqrt(5)-2))))^(2/3))
A5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*V)/(5*(sqrt(sqrt(5)-2))))^(2/3))

What is Truncated Rhombohedron?

The truncated rhombohedron is a convex , octahedral polyhedron. It is made up of six equal, irregular, but axially symmetrical pentagons and two equilateral triangles . It has twelve corners; three faces meet at each corner (a triangle and two pentagons or three pentagons). All corner points lie on the same sphere . Opposite faces are parallel . In the stitch, the body stands on a triangular surface , the pentagons virtually form the surface . The number of edges is eighteen

How to Calculate Area of pentagon of Truncated Rhombohedron given volume?

Area of pentagon of Truncated Rhombohedron given volume calculator uses area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*Volume)/(5*(sqrt(sqrt(5)-2))))^(2/3)) to calculate the Area 5, Area of pentagon of Truncated Rhombohedron given volume formula is defined as amount of space occupied by pentagon of Truncated Rhombohedron in given plane. Area 5 and is denoted by A5 symbol.

How to calculate Area of pentagon of Truncated Rhombohedron given volume using this online calculator? To use this online calculator for Area of pentagon of Truncated Rhombohedron given volume, enter Volume (V) and hit the calculate button. Here is how the Area of pentagon of Truncated Rhombohedron given volume calculation can be explained with given input values -> 14.02209 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*63)/(5*(sqrt(sqrt(5)-2))))^(2/3)).

FAQ

What is Area of pentagon of Truncated Rhombohedron given volume?
Area of pentagon of Truncated Rhombohedron given volume formula is defined as amount of space occupied by pentagon of Truncated Rhombohedron in given plane and is represented as A5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*V)/(5*(sqrt(sqrt(5)-2))))^(2/3)) or area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*Volume)/(5*(sqrt(sqrt(5)-2))))^(2/3)). Volume is the amount of space that a substance or object occupies or that is enclosed within a container.
How to calculate Area of pentagon of Truncated Rhombohedron given volume?
Area of pentagon of Truncated Rhombohedron given volume formula is defined as amount of space occupied by pentagon of Truncated Rhombohedron in given plane is calculated using area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*Volume)/(5*(sqrt(sqrt(5)-2))))^(2/3)). To calculate Area of pentagon of Truncated Rhombohedron given volume, you need Volume (V). With our tool, you need to enter the respective value for Volume and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Area 5?
In this formula, Area 5 uses Volume. We can use 7 other way(s) to calculate the same, which is/are as follows -
  • area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(Side A^2)
  • area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((2*Side B)/(3-sqrt(5)))^2)
  • area_5 = ((sqrt(5+(2*sqrt(5))))/4)*((Side C/(sqrt(5-(2*sqrt(5)))))^2)
  • area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((4*Circumradius)/(sqrt(14-(2*sqrt(5)))))^2)
  • area_5 = ((sqrt(5+(2*sqrt(5))))/4)*((2*Surface Area Polyhedron)/((3*(sqrt(5+(2*sqrt(5)))))+(5*sqrt(3))-(2*sqrt(15))))
  • area_5 = ((sqrt(5+(2*sqrt(5))))/4)*(((3*Volume)/(5*(sqrt(sqrt(5)-2))))^(2/3))
  • area_5 = ((sqrt(5+(2*sqrt(5))))/4)*((((3*(sqrt(5+(2*sqrt(5)))))+(5*sqrt(3))-(2*sqrt(15)))/(2*(5/3)*(sqrt(sqrt(5)-2))*Surface to Volume Ratio))^2)
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