Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
A = 4*ρ*L*(P^2)/(Ploss*((Vm*cos(Φ))^2))
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
STEP 1: Convert Input(s) to Base Unit
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
A = 4*ρ*L*(P^2)/(Ploss*((Vm*cos(Φ))^2)) --> 4*1.7E-05*24*(300^2)/(2.67*((230*cos(0.5235987755982))^2))
Evaluating ... ...
A = 0.0013865465899195
STEP 3: Convert Result to Output's Unit
0.0013865465899195 Square Meter --> No Conversion Required
FINAL ANSWER
0.0013865465899195 0.001387 Square Meter <-- Area of Underground AC Wire
(Calculation completed in 00.004 seconds)

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14 Wire Parameters Calculators

Volume of Conductor Material using Resistance (1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = (8*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)
Angle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Phase Difference = acos(sqrt(4*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))))
Line Losses using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Line Losses = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Area of Underground AC Wire*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)
Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)
Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = 8*Resistivity*(Power Transmitted^2)*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))
Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)
Go Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))
Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)
Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))
Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)
Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))
Volume of Conductor Material using Load Current (1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = 16*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses
Volume of Conductor Material using Constant(1-Phase 2-Wire Mid-Point Earthed)
Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference)^2)
Length using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)
Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
Area using Volume of Conductor Material (1-Phase 2-Wire Mid-Point Earthed)
Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
Volume of Conductor Material using Area and Length(1-Phase 2-Wire Mid-Point US)
Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
A = 4*ρ*L*(P^2)/(Ploss*((Vm*cos(Φ))^2))

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) calculator uses Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)) to calculate the Area of Underground AC Wire, The Area Of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to calculate Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), enter Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ) and hit the calculate button. Here is how the Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 0.001387 = 4*1.7E-05*24*(300^2)/(2.67*((230*cos(0.5235987755982))^2)).

FAQ

What is Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?
The Area Of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier and is represented as A = 4*ρ*L*(P^2)/(Ploss*((Vm*cos(Φ))^2)) or Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)). Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
How to calculate Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)?
The Area Of X-Section (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier is calculated using Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)). To calculate Area of X-Section (1-Phase 2-Wire Mid-Point Earthed), you need Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Line Losses (Ploss), Maximum Voltage Underground AC (Vm) & Phase Difference (Φ). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Power Transmitted, Line Losses, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Area of Underground AC Wire?
In this formula, Area of Underground AC Wire uses Resistivity, Length of Underground AC Wire, Power Transmitted, Line Losses, Maximum Voltage Underground AC & Phase Difference. We can use 2 other way(s) to calculate the same, which is/are as follows -
  • Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))
  • Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
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