Area of X-Section using Load Current (1-Phase 2-Wire US) Calculator

✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Underground AC [I]			+10% -10%
✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of X-Section using Load Current (1-Phase 2-Wire US) [A]

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Formula

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Area of X-Section using Load Current (1-Phase 2-Wire US)

Formula

`"A" = 2*("I")^2*"ρ"*"L"/("P"_{"loss"})`

Example

`"0.024755m²"=2*("9A")^2*"0.000017Ω*m"*"24m"/("2.67W")`

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Area of X-Section using Load Current (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses)
A = 2*(I)^2*ρ*L/(P_loss)
This formula uses 5 Variables

Variables Used

Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.

STEP 1: Convert Input(s) to Base Unit

Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

A = 2*(I)^2*ρ*L/(P_loss) --> 2*(9)^2*1.7E-05*24/(2.67)

Evaluating ... ...

A = 0.0247550561797753

STEP 3: Convert Result to Output's Unit

0.0247550561797753 Square Meter --> No Conversion Required

FINAL ANSWER

0.0247550561797753 ≈ 0.024755 Square Meter <-- Area of Underground AC Wire

(Calculation completed in 00.004 seconds)

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< 23 Wire Parameters Calculators

Area of X-Section using Line Losses (1-Phase 2-Wire US)

Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Area of X-Section (1-Phase 2-Wire US)

Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Length using Area of X-Section (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)

Length using Line Losses (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)

Volume of Conductor Material using Line Losses (1-Phase 2-Wire US)

Go Volume Of Conductor = 8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Constant using Resistance (1-Phase 2-Wire US)

Go Constant Underground AC = (4*Power Transmitted*Length of Underground AC Wire*Resistance Underground AC*Area of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2))

Length of Wire using Constant (1-Phase 2-Wire US)

Go Length of Underground AC Wire = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Power Transmitted)^2))

Constant using Load Current (1-Phase 2-Wire US)

Go Constant Underground AC = 2*(Current Underground AC^2)*(cos(Phase Difference)^2)*Resistivity*(Length of Underground AC Wire^2)/Line Losses

Constant (1-Phase 2-Wire US)

Go Constant Underground AC = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)

Constant using Line Losses (1-Phase 2-Wire US)

Go Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2)

Length using Load Current (1-Phase 2-Wire US)

Go Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)

Area of X-Section using Load Current (1-Phase 2-Wire US)

Go Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses)

Volume of Conductor Material using Load Current (1-Phase 2-Wire US)

Go Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)

Constant using Area of X-Section (1-Phase 2-Wire US)

Go Constant Underground AC = Area of Underground AC Wire*Length of Underground AC Wire*(cos(Phase Difference))^2

Area of X-Section using Constant (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Constant Underground AC/Length of Underground AC Wire*(cos(Phase Difference))^2

Length using Resistance (1-Phase 2-Wire US)

Go Length of Underground AC Wire = (Resistance Underground AC*Area of Underground AC Wire)/(Resistivity)

Area of X-Section using Resistance (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/Resistance Underground AC

Constant using Volume of Conductor Material (1-Phase 2-Wire US)

Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference))^2/2

Volume of Conductor Material using Constant (1-Phase 2-Wire US)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2

Voltage of Conductor Material (1-Phase 2-Wire US)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2

Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)

Length using Volume of Conductor Material (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)

Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)

Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Area of X-Section using Load Current (1-Phase 2-Wire US) Formula

Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses)
A = 2*(I)^2*ρ*L/(P_loss)

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Area of X-Section using Load Current (1-Phase 2-Wire US)?

Area of X-Section using Load Current (1-Phase 2-Wire US) calculator uses Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses) to calculate the Area of Underground AC Wire, The Area of X-Section using Load Current (1-Phase 2-Wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to calculate Area of X-Section using Load Current (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Area of X-Section using Load Current (1-Phase 2-Wire US), enter Current Underground AC (I), Resistivity (ρ), Length of Underground AC Wire (L) & Line Losses (P_loss) and hit the calculate button. Here is how the Area of X-Section using Load Current (1-Phase 2-Wire US) calculation can be explained with given input values -> 0.024755 = 2*(9)^2*1.7E-05*24/(2.67).

FAQ

What is Area of X-Section using Load Current (1-Phase 2-Wire US)?

The Area of X-Section using Load Current (1-Phase 2-Wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier and is represented as A = 2*(I)^2*ρ*L/(P_loss) or Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses). Current Underground AC is defined as the current flowing through the overhead ac supply wire, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end & Line Losses is defined as the total losses occurring in an Underground AC line when in use.

How to calculate Area of X-Section using Load Current (1-Phase 2-Wire US)?

The Area of X-Section using Load Current (1-Phase 2-Wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier is calculated using Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses). To calculate Area of X-Section using Load Current (1-Phase 2-Wire US), you need Current Underground AC (I), Resistivity (ρ), Length of Underground AC Wire (L) & Line Losses (P_loss). With our tool, you need to enter the respective value for Current Underground AC, Resistivity, Length of Underground AC Wire & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Area of Underground AC Wire?

In this formula, Area of Underground AC Wire uses Current Underground AC, Resistivity, Length of Underground AC Wire & Line Losses. We can use 5 other way(s) to calculate the same, which is/are as follows -

Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/Resistance Underground AC
Area of Underground AC Wire = Constant Underground AC/Length of Underground AC Wire*(cos(Phase Difference))^2

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