Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US) Calculator

✖Volume Of Conductor the 3-dimensional space enclosed by a conductor material.ⓘ Volume Of Conductor [V]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US) [A]

⎘ Copy

👎

Formula

✖

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)

Formula

`"A" = "V"/((2+sqrt(2))*"L")`

Example

`"0.732233m²"="60m³"/((2+sqrt(2))*"24m")`

Calculator

LaTeX

Reset

👍

Download Power System Formula PDF PDF Image

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)
A = V/((2+sqrt(2))*L)
This formula uses 1 Functions, 3 Variables

Functions Used

sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.

STEP 1: Convert Input(s) to Base Unit

Volume Of Conductor: 60 Cubic Meter --> 60 Cubic Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

A = V/((2+sqrt(2))*L) --> 60/((2+sqrt(2))*24)

Evaluating ... ...

A = 0.732233047033631

STEP 3: Convert Result to Output's Unit

0.732233047033631 Square Meter --> No Conversion Required

FINAL ANSWER

0.732233047033631 ≈ 0.732233 Square Meter <-- Area of Underground AC Wire

(Calculation completed in 00.004 seconds)

You are here -

Home » Engineering » Electrical » Power System » Underground AC Supply » 2-Φ 3-Wire System » Wire Parameters » Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)

Credits

Created by Urvi Rathod

Vishwakarma Government Engineering College (VGEC), Ahmedabad

Urvi Rathod has created this Calculator and 1500+ more calculators!

Verified by Shobhit Dimri

Bipin Tripathi Kumaon Institute of Technology (BTKIT), Dwarahat

Shobhit Dimri has verified this Calculator and 100+ more calculators!

< 17 Wire Parameters Calculators

Volume of Conductor Material using Resistance (2 Phase 3 Wire US)

Go Volume Of Conductor = ((2+sqrt(2))^2*(Power Transmitted^2)*Resistance Underground AC*Area of Underground AC Wire*Length of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference))^2)

Angle of Pf using Line Losses (2-Phase 3-Wire US)

Go Phase Difference = acos((2+(sqrt(2)*Power Transmitted/Maximum Voltage Underground AC))*(sqrt(Resistivity*Length of Underground AC Wire/Line Losses*Area of Underground AC Wire)))

Length using Volume of Conductor Material (2 Phase 3 Wire US)

Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))

Volume of Conductor Material (2 Phase 3 Wire US)

Go Volume Of Conductor = ((2+sqrt(2))^2)*(Power Transmitted^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses*(Maximum Voltage Underground AC^2)*(cos(Phase Difference)^2))

Area of X-Section using Line Losses (2-Phase 3-Wire US)

Go Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Length using Line Losses (2-Phase 3-Wire US)

Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/((2+sqrt(2))*(Power Transmitted^2)*Resistivity)

Line Losses using Volume of Conductor Material (2 Phase 3 Wire US)

Go Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)

Volume of Conductor Material using Area and Length(2 Phase 3 Wire US)

Go Volume Of Conductor = (2*Area of Underground AC Wire*Length of Underground AC Wire)+(sqrt(2)*Area of Underground AC Wire*Length of Underground AC Wire)

Volume of Conductor Material using Load Current (2 Phase 3 Wire US)

Go Volume Of Conductor = (2+sqrt(2))^2*Resistivity*(Length of Underground AC Wire^2)*(Current Underground AC^2)/Line Losses

Angle using Current in Neutral Wire (2-Phase 3-Wire US)

Go Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))

Length using Resistance of Natural Wire (2-Phase 3-Wire US)

Go Length of Underground AC Wire = (Resistance Underground AC*sqrt(2)*Area of Underground AC Wire)/(Resistivity)

Area using Resistance of Natural Wire (2-Phase 3-Wire US)

Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/(sqrt(2)*Resistance Underground AC)

Angle using Current in Each Outer (2-Phase 3-Wire US)

Go Phase Difference = acos(Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC))

Angle of PF using Volume of Conductor Material (2 Phase 3 Wire US)

Go Phase Difference = acos(sqrt((2.914)*Constant Underground AC/Volume Of Conductor))

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)

Go Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)

Constant using Volume of Conductor Material (2 Phase 3 Wire US)

Go Constant Underground AC = Volume Of Conductor*((cos(Phase Difference))^2)/(2.914)

Volume of Conductor Material using Constant(2 Phase 3 Wire US)

Go Volume Of Conductor = 2.194*Constant Underground AC/(cos(Phase Difference)^2)

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US) Formula

Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)
A = V/((2+sqrt(2))*L)

What is the value of maximum voltage and volume of conductor material in 2-phase 3-wire system?

The volume of conductor material required in this system is 2.914/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m/√2 so that r.m.s. value of voltage between them is v_m/2.

How to Calculate Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)?

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US) calculator uses Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire) to calculate the Area of Underground AC Wire, The Area of X section using Volume of Conductor Material (2 phase 3 wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to calculate Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US) using this online calculator? To use this online calculator for Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US), enter Volume Of Conductor (V) & Length of Underground AC Wire (L) and hit the calculate button. Here is how the Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US) calculation can be explained with given input values -> 0.732233 = 60/((2+sqrt(2))*24).

FAQ

What is Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)?

The Area of X section using Volume of Conductor Material (2 phase 3 wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier and is represented as A = V/((2+sqrt(2))*L) or Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire). Volume Of Conductor the 3-dimensional space enclosed by a conductor material & Length of Underground AC Wire is the total length of the wire from one end to other end.

How to calculate Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)?

The Area of X section using Volume of Conductor Material (2 phase 3 wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier is calculated using Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire). To calculate Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US), you need Volume Of Conductor (V) & Length of Underground AC Wire (L). With our tool, you need to enter the respective value for Volume Of Conductor & Length of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Area of Underground AC Wire?

In this formula, Area of Underground AC Wire uses Volume Of Conductor & Length of Underground AC Wire. We can use 2 other way(s) to calculate the same, which is/are as follows -

Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/(sqrt(2)*Resistance Underground AC)

Home

FREE PDFs

🔍 Search