Compression Work Calculator

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Air Refrigeration Systems

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✖Mass of air is both a property of air and a measure of its resistance to acceleration when a net force is applied.ⓘ Mass of Air [ma]			+10% -10%
✖Specific Heat Capacity at Constant Pressure means the amount of heat that is required to raise the temperature of a unit mass of gas by 1 degree at constant pressure.ⓘ Specific Heat Capacity at Constant Pressure [C_p]			+10% -10%
✖Actual End Temp of Isentropic Compression is greater than the ideal temperature.ⓘ Actual End Temp of Isentropic Compression [Tt^']			+10% -10%
✖Actual temperature of Rammed Air is equal to the ideal temperature of Rammed Air.ⓘ Actual temperature of Rammed Air [T2^']			+10% -10%

✖Work Done per min is when a force that is applied to an object moves that object.ⓘ Compression Work [W_{per min}]

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Formula

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Compression Work

Formula

`"W"_{"per min"} = "ma"*"C"_{"p"}*("Tt"^{"'"}-"T2"^{"'"})`

Example

`"9286.2kJ/min"="120kg/min"*"1.005kJ/kg*K"*("350K"-"273K")`

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Compression Work Solution

STEP 0: Pre-Calculation Summary

Formula Used

Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air)
W_{per min} = ma*C_p*(Tt^'-T2^')
This formula uses 5 Variables

Variables Used

Work Done per min - (Measured in Watt) - Work Done per min is when a force that is applied to an object moves that object.
Mass of Air - (Measured in Kilogram per Second) - Mass of air is both a property of air and a measure of its resistance to acceleration when a net force is applied.
Specific Heat Capacity at Constant Pressure - (Measured in Joule per Kilogram per K) - Specific Heat Capacity at Constant Pressure means the amount of heat that is required to raise the temperature of a unit mass of gas by 1 degree at constant pressure.
Actual End Temp of Isentropic Compression - (Measured in Kelvin) - Actual End Temp of Isentropic Compression is greater than the ideal temperature.
Actual temperature of Rammed Air - (Measured in Kelvin) - Actual temperature of Rammed Air is equal to the ideal temperature of Rammed Air.

STEP 1: Convert Input(s) to Base Unit

Mass of Air: 120 Kilogram per Minute --> 2 Kilogram per Second (Check conversion here)
Specific Heat Capacity at Constant Pressure: 1.005 Kilojoule per Kilogram per K --> 1005 Joule per Kilogram per K (Check conversion here)
Actual End Temp of Isentropic Compression: 350 Kelvin --> 350 Kelvin No Conversion Required
Actual temperature of Rammed Air: 273 Kelvin --> 273 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

W_{per min} = ma*C_p*(Tt^'-T2^') --> 2*1005*(350-273)

Evaluating ... ...

W_{per min} = 154770

STEP 3: Convert Result to Output's Unit

154770 Watt -->9286.19999999998 Kilojoule per Minute (Check conversion here)

FINAL ANSWER

9286.19999999998 ≈ 9286.2 Kilojoule per Minute <-- Work Done per min

(Calculation completed in 00.004 seconds)

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< 17 Air Refrigeration Systems Calculators

Power required to maintain pressure inside cabin excluding ram work

Go Input Power = ((Mass of Air*Specific Heat Capacity at Constant Pressure*Actual temperature of Rammed Air)/(Compressor Efficiency))*((Cabin Pressure/Pressure of Rammed Air)^((Heat Capacity Ratio-1)/Heat Capacity Ratio)-1)

Power Required to Maintain Pressure inside Cabin including Ram Work

Go Input Power = ((Mass of Air*Specific Heat Capacity at Constant Pressure*Ambient Air Temperature)/(Compressor Efficiency))*((Cabin Pressure/Atmospheric Pressure)^((Heat Capacity Ratio-1)/Heat Capacity Ratio)-1)

C.O.P. of simple air evaporative cycle

Go Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air))

C.O.P. of simple air cycle

Go Actual Coefficient of Performance = (Inside temperature of cabin-Actual temperature at end of isentropic expansion)/(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air)

Mass of air to produce Q tonnes of refrigeration given exit temperature of cooling turbine

Go Mass of Air = (210*Tonnage of Refrigeration in TR)/(Specific Heat Capacity at Constant Pressure*(Temperature at End of Isentropic Expansion-Actual exit Temperature of cooling turbine))

Mass of air to produce Q tonnes of refrigeration

Go Mass of Air = (210*Tonnage of Refrigeration in TR)/(Specific Heat Capacity at Constant Pressure*(Inside temperature of cabin-Actual temperature at end of isentropic expansion))

Expansion Work

Go Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Temperature at the end of cooling process-Actual temperature at end of isentropic expansion)

Refrigeration Effect Produced

Go Refrigeration Effect Produced = Mass of Air*Specific Heat Capacity at Constant Pressure*(Inside temperature of cabin-Actual temperature at end of isentropic expansion)

Heat rejected during cooling process

Go Heat Rejected = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Temperature at the end of cooling process)

Compression Work

Go Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air)

Power Required for Refrigeration System

Go Input Power = (Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air))/60

Temperature Ratio at Start and End of Ramming Process

Go Temperature Ratio = 1+(Velocity^2*(Heat Capacity Ratio-1))/(2*Heat Capacity Ratio*[R]*Initial Temperature)

Ram Efficiency

Go Ram Efficiency = (Stagnation Pressure of System-Initial Pressure of System)/(Final Pressure of System-Initial Pressure of System)

Local Sonic or Acoustic Velocity at Ambient Air Conditions

Go Sonic Velocity = (Heat Capacity Ratio*[R]*Initial Temperature/Molecular Weight)^0.5

Initial Mass of Evaporant Required to be Carried for given Flight Time

Go Mass = (Rate of Heat Removal*Time in Minutes)/Latent Heat of Vaporization

COP of Air Cycle for given Input Power and Tonnage of Refrigeration

Go Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Input Power*60)

COP of Air Cycle given Input Power

Go Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Input Power*60)

Compression Work Formula

Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air)
W_{per min} = ma*C_p*(Tt^'-T2^')

How does a compressor work in a refrigeration system?

The compressor constricts the refrigerant vapor, raising its pressure and temperature, and pushes it into the coils of the condenser on the outside of the refrigerator. The refrigerant absorbs the heat inside the fridge when it flows through the evaporator coils, cooling down the air inside the fridge.

How to Calculate Compression Work?

Compression Work calculator uses Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air) to calculate the Work Done per min, The compression work formula is defined as the product of the mass of air, constant pressure heat capacity, and the difference in actual temperatures at the end of ramming and isentropic compression processes. Work Done per min is denoted by W_{per min} symbol.

How to calculate Compression Work using this online calculator? To use this online calculator for Compression Work, enter Mass of Air (ma), Specific Heat Capacity at Constant Pressure (C_p), Actual End Temp of Isentropic Compression (Tt^') & Actual temperature of Rammed Air (T2^') and hit the calculate button. Here is how the Compression Work calculation can be explained with given input values -> 557.172 = 2*1005*(350-273).

FAQ

What is Compression Work?

The compression work formula is defined as the product of the mass of air, constant pressure heat capacity, and the difference in actual temperatures at the end of ramming and isentropic compression processes and is represented as W_{per min} = ma*C_p*(Tt^'-T2^') or Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air). Mass of air is both a property of air and a measure of its resistance to acceleration when a net force is applied, Specific Heat Capacity at Constant Pressure means the amount of heat that is required to raise the temperature of a unit mass of gas by 1 degree at constant pressure, Actual End Temp of Isentropic Compression is greater than the ideal temperature & Actual temperature of Rammed Air is equal to the ideal temperature of Rammed Air.

How to calculate Compression Work?

The compression work formula is defined as the product of the mass of air, constant pressure heat capacity, and the difference in actual temperatures at the end of ramming and isentropic compression processes is calculated using Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual temperature of Rammed Air). To calculate Compression Work, you need Mass of Air (ma), Specific Heat Capacity at Constant Pressure (C_p), Actual End Temp of Isentropic Compression (Tt^') & Actual temperature of Rammed Air (T2^'). With our tool, you need to enter the respective value for Mass of Air, Specific Heat Capacity at Constant Pressure, Actual End Temp of Isentropic Compression & Actual temperature of Rammed Air and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Work Done per min?

In this formula, Work Done per min uses Mass of Air, Specific Heat Capacity at Constant Pressure, Actual End Temp of Isentropic Compression & Actual temperature of Rammed Air. We can use 1 other way(s) to calculate the same, which is/are as follows -

Work Done per min = Mass of Air*Specific Heat Capacity at Constant Pressure*(Temperature at the end of cooling process-Actual temperature at end of isentropic expansion)

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