## Conjugate Axis of Hyperbola Solution

STEP 0: Pre-Calculation Summary
Formula Used
Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola
2b = 2*b
This formula uses 2 Variables
Variables Used
Conjugate Axis of Hyperbola - (Measured in Meter) - Conjugate Axis of Hyperbola is the line through the center and perpendicular to transverse axis with length of the chord of the circle passing through the foci and touches the Hyperbola at vertex.
Semi Conjugate Axis of Hyperbola - (Measured in Meter) - Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola.
STEP 1: Convert Input(s) to Base Unit
Semi Conjugate Axis of Hyperbola: 12 Meter --> 12 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
2b = 2*b --> 2*12
Evaluating ... ...
2b = 24
STEP 3: Convert Result to Output's Unit
24 Meter --> No Conversion Required
24 Meter <-- Conjugate Axis of Hyperbola
(Calculation completed in 00.004 seconds)
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## < 12 Conjugate Axis of Hyperbola Calculators

Semi Conjugate Axis of Hyperbola given Latus Rectum and Focal Parameter
Semi Conjugate Axis of Hyperbola = (Latus Rectum of Hyperbola*Focal Parameter of Hyperbola)/sqrt(Latus Rectum of Hyperbola^2-(2*Focal Parameter of Hyperbola)^2)
Semi Conjugate Axis of Hyperbola given Eccentricity and Focal Parameter
Semi Conjugate Axis of Hyperbola = (Eccentricity of Hyperbola/sqrt(Eccentricity of Hyperbola^2-1))*Focal Parameter of Hyperbola
Semi Conjugate Axis of Hyperbola given Linear Eccentricity
Semi Conjugate Axis of Hyperbola = sqrt(Linear Eccentricity of Hyperbola^2-Semi Transverse Axis of Hyperbola^2)
Semi Conjugate Axis of Hyperbola given Eccentricity and Linear Eccentricity
Semi Conjugate Axis of Hyperbola = Linear Eccentricity of Hyperbola*sqrt(1-1/Eccentricity of Hyperbola^2)
Semi Conjugate Axis of Hyperbola given Latus Rectum and Eccentricity
Semi Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola)^2/(Eccentricity of Hyperbola^2-1))/2
Semi Conjugate Axis of Hyperbola given Eccentricity
Semi Conjugate Axis of Hyperbola = Semi Transverse Axis of Hyperbola*sqrt(Eccentricity of Hyperbola^2-1)
Semi Conjugate Axis of Hyperbola given Latus Rectum
Semi Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola*Semi Transverse Axis of Hyperbola)/2)
Semi Conjugate Axis of Hyperbola given Linear Eccentricity and Focal Parameter
Semi Conjugate Axis of Hyperbola = sqrt(Focal Parameter of Hyperbola*Linear Eccentricity of Hyperbola)
Conjugate Axis of Hyperbola given Eccentricity and Linear Eccentricity
Conjugate Axis of Hyperbola = 2*Linear Eccentricity of Hyperbola*sqrt(1-1/Eccentricity of Hyperbola^2)
Conjugate Axis of Hyperbola given Latus Rectum and Eccentricity
Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola)^2/(Eccentricity of Hyperbola^2-1))
Semi Conjugate Axis of Hyperbola
Semi Conjugate Axis of Hyperbola = Conjugate Axis of Hyperbola/2
Conjugate Axis of Hyperbola
Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola

## < 6 Axis of Hyperbola Calculators

Semi Transverse Axis of Hyperbola given Focal Parameter
Semi Transverse Axis of Hyperbola = Semi Conjugate Axis of Hyperbola/Focal Parameter of Hyperbola*sqrt(Semi Conjugate Axis of Hyperbola^2-Focal Parameter of Hyperbola^2)
Semi Transverse Axis of Hyperbola given Linear Eccentricity
Semi Transverse Axis of Hyperbola = sqrt(Linear Eccentricity of Hyperbola^2-Semi Conjugate Axis of Hyperbola^2)
Semi Conjugate Axis of Hyperbola given Eccentricity
Semi Conjugate Axis of Hyperbola = Semi Transverse Axis of Hyperbola*sqrt(Eccentricity of Hyperbola^2-1)
Semi Conjugate Axis of Hyperbola given Latus Rectum
Semi Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola*Semi Transverse Axis of Hyperbola)/2)
Transverse Axis of Hyperbola
Transverse Axis of Hyperbola = 2*Semi Transverse Axis of Hyperbola
Conjugate Axis of Hyperbola
Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola

## Conjugate Axis of Hyperbola Formula

Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola
2b = 2*b

## What is Hyperbola?

A Hyperbola is a type of conic section, which is a geometric figure that results from intersecting a cone with a plane. A Hyperbola is defined as the set of all points in a plane, the difference of whose distances from two fixed points (called the foci) is constant. In other words, a Hyperbola is the locus of points where the difference between the distances to two fixed points is a constant value. The standard form of the equation for a Hyperbola is: (x - h)²/a² - (y - k)²/b² = 1

## What is Conjugate Axis of the Hyperbola and how is it calculated?

The conjugate axis of Hyperbola is the line perpendicular to the transverse axis and has the co-vertices as its endpoints. It is calculated by the equation c = 2b where c is the length of the conjugate axis of the Hyperbola and b is the semi conjugate axis of the Hyperbola.

## How to Calculate Conjugate Axis of Hyperbola?

Conjugate Axis of Hyperbola calculator uses Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola to calculate the Conjugate Axis of Hyperbola, Conjugate Axis of Hyperbola formula is defined as the line through the center and perpendicular to transverse axis with length of the chord of the circle passing through the foci and touches the Hyperbola at vertex. Conjugate Axis of Hyperbola is denoted by 2b symbol.

How to calculate Conjugate Axis of Hyperbola using this online calculator? To use this online calculator for Conjugate Axis of Hyperbola, enter Semi Conjugate Axis of Hyperbola (b) and hit the calculate button. Here is how the Conjugate Axis of Hyperbola calculation can be explained with given input values -> 24 = 2*12.

### FAQ

What is Conjugate Axis of Hyperbola?
Conjugate Axis of Hyperbola formula is defined as the line through the center and perpendicular to transverse axis with length of the chord of the circle passing through the foci and touches the Hyperbola at vertex and is represented as 2b = 2*b or Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola. Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola.
How to calculate Conjugate Axis of Hyperbola?
Conjugate Axis of Hyperbola formula is defined as the line through the center and perpendicular to transverse axis with length of the chord of the circle passing through the foci and touches the Hyperbola at vertex is calculated using Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola. To calculate Conjugate Axis of Hyperbola, you need Semi Conjugate Axis of Hyperbola (b). With our tool, you need to enter the respective value for Semi Conjugate Axis of Hyperbola and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Conjugate Axis of Hyperbola?
In this formula, Conjugate Axis of Hyperbola uses Semi Conjugate Axis of Hyperbola. We can use 2 other way(s) to calculate the same, which is/are as follows -
• Conjugate Axis of Hyperbola = sqrt((Latus Rectum of Hyperbola)^2/(Eccentricity of Hyperbola^2-1))
• Conjugate Axis of Hyperbola = 2*Linear Eccentricity of Hyperbola*sqrt(1-1/Eccentricity of Hyperbola^2) Let Others Know