Constant using Line Losses (1-Phase 2-Wire US) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖Voltage Underground AC is defined as the amount of work or force required to start the conduction of current within a line.ⓘ Voltage Underground AC [V_ac]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%

✖Constant Underground AC is defined as the constant of line of a Overhead supply system.ⓘ Constant using Line Losses (1-Phase 2-Wire US) [K]

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Constant using Line Losses (1-Phase 2-Wire US)

Formula

`"K" = (4*"ρ"*("P"*"V"_{"ac"})^2)/("P"_{"loss"}*("V"_{"m"})^2)`

Example

`"0.623946"=(4*"0.000017Ω*m"*("300W"*"120V")^2)/("2.67W"*("230V")^2)`

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Constant using Line Losses (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2)
K = (4*ρ*(P*V_ac)^2)/(P_loss*(V_m)^2)
This formula uses 6 Variables

Variables Used

Constant Underground AC - Constant Underground AC is defined as the constant of line of a Overhead supply system.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Voltage Underground AC - (Measured in Volt) - Voltage Underground AC is defined as the amount of work or force required to start the conduction of current within a line.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Voltage Underground AC: 120 Volt --> 120 Volt No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

K = (4*ρ*(P*V_ac)^2)/(P_loss*(V_m)^2) --> (4*1.7E-05*(300*120)^2)/(2.67*(230)^2)

Evaluating ... ...

K = 0.623945965463775

STEP 3: Convert Result to Output's Unit

0.623945965463775 --> No Conversion Required

FINAL ANSWER

0.623945965463775 ≈ 0.623946 <-- Constant Underground AC

(Calculation completed in 00.004 seconds)

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< 23 Wire Parameters Calculators

Area of X-Section using Line Losses (1-Phase 2-Wire US)

Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Area of X-Section (1-Phase 2-Wire US)

Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Length using Area of X-Section (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)

Length using Line Losses (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)

Volume of Conductor Material using Line Losses (1-Phase 2-Wire US)

Go Volume Of Conductor = 8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)

Constant using Resistance (1-Phase 2-Wire US)

Go Constant Underground AC = (4*Power Transmitted*Length of Underground AC Wire*Resistance Underground AC*Area of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2))

Length of Wire using Constant (1-Phase 2-Wire US)

Go Length of Underground AC Wire = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Power Transmitted)^2))

Constant using Load Current (1-Phase 2-Wire US)

Go Constant Underground AC = 2*(Current Underground AC^2)*(cos(Phase Difference)^2)*Resistivity*(Length of Underground AC Wire^2)/Line Losses

Constant (1-Phase 2-Wire US)

Go Constant Underground AC = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)

Constant using Line Losses (1-Phase 2-Wire US)

Go Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2)

Length using Load Current (1-Phase 2-Wire US)

Go Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)

Area of X-Section using Load Current (1-Phase 2-Wire US)

Go Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses)

Volume of Conductor Material using Load Current (1-Phase 2-Wire US)

Go Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)

Constant using Area of X-Section (1-Phase 2-Wire US)

Go Constant Underground AC = Area of Underground AC Wire*Length of Underground AC Wire*(cos(Phase Difference))^2

Area of X-Section using Constant (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Constant Underground AC/Length of Underground AC Wire*(cos(Phase Difference))^2

Length using Resistance (1-Phase 2-Wire US)

Go Length of Underground AC Wire = (Resistance Underground AC*Area of Underground AC Wire)/(Resistivity)

Area of X-Section using Resistance (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/Resistance Underground AC

Constant using Volume of Conductor Material (1-Phase 2-Wire US)

Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference))^2/2

Volume of Conductor Material using Constant (1-Phase 2-Wire US)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2

Voltage of Conductor Material (1-Phase 2-Wire US)

Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2

Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)

Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)

Length using Volume of Conductor Material (1-Phase 2-Wire US)

Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)

Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)

Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Constant using Line Losses (1-Phase 2-Wire US) Formula

Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2)
K = (4*ρ*(P*V_ac)^2)/(P_loss*(V_m)^2)

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Constant using Line Losses (1-Phase 2-Wire US)?

Constant using Line Losses (1-Phase 2-Wire US) calculator uses Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2) to calculate the Constant Underground AC, The Constant using Line Losses (1-Phase 2-Wire US) formula is defined as the total constant of a single-phase two-wire overhead system. it is represented by K. Constant Underground AC is denoted by K symbol.

How to calculate Constant using Line Losses (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Constant using Line Losses (1-Phase 2-Wire US), enter Resistivity (ρ), Power Transmitted (P), Voltage Underground AC (V_ac), Line Losses (P_loss) & Maximum Voltage Underground AC (V_m) and hit the calculate button. Here is how the Constant using Line Losses (1-Phase 2-Wire US) calculation can be explained with given input values -> 0.623946 = (4*1.7E-05*(300*120)^2)/(2.67*(230)^2).

FAQ

What is Constant using Line Losses (1-Phase 2-Wire US)?

The Constant using Line Losses (1-Phase 2-Wire US) formula is defined as the total constant of a single-phase two-wire overhead system. it is represented by K and is represented as K = (4*ρ*(P*V_ac)^2)/(P_loss*(V_m)^2) or Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2). Resistivity is the measure of how strongly a material opposes the flow of current through them, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Voltage Underground AC is defined as the amount of work or force required to start the conduction of current within a line, Line Losses is defined as the total losses occurring in an Underground AC line when in use & Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

How to calculate Constant using Line Losses (1-Phase 2-Wire US)?

The Constant using Line Losses (1-Phase 2-Wire US) formula is defined as the total constant of a single-phase two-wire overhead system. it is represented by K is calculated using Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2). To calculate Constant using Line Losses (1-Phase 2-Wire US), you need Resistivity (ρ), Power Transmitted (P), Voltage Underground AC (V_ac), Line Losses (P_loss) & Maximum Voltage Underground AC (V_m). With our tool, you need to enter the respective value for Resistivity, Power Transmitted, Voltage Underground AC, Line Losses & Maximum Voltage Underground AC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Constant Underground AC?

In this formula, Constant Underground AC uses Resistivity, Power Transmitted, Voltage Underground AC, Line Losses & Maximum Voltage Underground AC. We can use 5 other way(s) to calculate the same, which is/are as follows -

Constant Underground AC = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)
Constant Underground AC = Area of Underground AC Wire*Length of Underground AC Wire*(cos(Phase Difference))^2
Constant Underground AC = Volume Of Conductor*(cos(Phase Difference))^2/2
Constant Underground AC = 2*(Current Underground AC^2)*(cos(Phase Difference)^2)*Resistivity*(Length of Underground AC Wire^2)/Line Losses
Constant Underground AC = (4*Power Transmitted*Length of Underground AC Wire*Resistance Underground AC*Area of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2))

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