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## Enthalpy of Activation Given Slope of line Solution

STEP 0: Pre-Calculation Summary
Formula Used
Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g])
Δ++H° = -(m*2.303*[Molar-g])
This formula uses 1 Constants, 1 Variables
Constants Used
[Molar-g] - Molar gas constant Value Taken As 8.3145 Joule/Kelvin Mole
Variables Used
Slope of Line B/w Ln K and 1/T - The slope of Line B/w Ln K and 1/T is defined as when the Lnk (rate constant) is plotted versus the inverse of the temperature (kelvin), the slope is a straight line. (Measured in Kelvin)
STEP 1: Convert Input(s) to Base Unit
Slope of Line B/w Ln K and 1/T: -0.707 Kelvin --> -0.707 Kelvin No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Δ++H° = -(m*2.303*[Molar-g]) --> -((-0.707)*2.303*[Molar-g])
Evaluating ... ...
Δ++H° = 13.5378435045
STEP 3: Convert Result to Output's Unit
13.5378435045 Joule Per Mole --> No Conversion Required
13.5378435045 Joule Per Mole <-- Enthalpy of Activation
(Calculation completed in 00.003 seconds)

## < 2 Transition State Theory Calculators

Entropy of Activation
Entropy of Activation = ([Molar-g]*ln(Pre-Exponential Factor))-[Molar-g]*ln([Molar-g]*Temperature)/[Avaga-no]*[hP] Go
Enthalpy of Activation Given Slope of line
Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g]) Go

### Enthalpy of Activation Given Slope of line Formula

Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g])
Δ++H° = -(m*2.303*[Molar-g])

## What is the Transition State Theory ?

Transition state theory (TST) explains the reaction rates of elementary chemical reactions. The theory assumes a special type of chemical equilibrium (quasi-equilibrium) between reactants and activated transition state complexes.

## How to Calculate Enthalpy of Activation Given Slope of line?

Enthalpy of Activation Given Slope of line calculator uses Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g]) to calculate the Enthalpy of Activation, Enthalpy of Activation Given Slope of line B/w Ln(k/T) and 1/T is defined as the enthalpy change that appears in the thermodynamic form of the rate equation obtained from conventional transition state theory. This equation is only correct for a first order reaction, for which the rate constant has the dimension reciprocal time. Enthalpy of Activation is denoted by Δ++H° symbol.

How to calculate Enthalpy of Activation Given Slope of line using this online calculator? To use this online calculator for Enthalpy of Activation Given Slope of line, enter Slope of Line B/w Ln K and 1/T (m) and hit the calculate button. Here is how the Enthalpy of Activation Given Slope of line calculation can be explained with given input values -> 13.53784 = -((-0.707)*2.303*[Molar-g]).

### FAQ

What is Enthalpy of Activation Given Slope of line?
Enthalpy of Activation Given Slope of line B/w Ln(k/T) and 1/T is defined as the enthalpy change that appears in the thermodynamic form of the rate equation obtained from conventional transition state theory. This equation is only correct for a first order reaction, for which the rate constant has the dimension reciprocal time and is represented as Δ++H° = -(m*2.303*[Molar-g]) or Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g]). The slope of Line B/w Ln K and 1/T is defined as when the Lnk (rate constant) is plotted versus the inverse of the temperature (kelvin), the slope is a straight line.
How to calculate Enthalpy of Activation Given Slope of line?
Enthalpy of Activation Given Slope of line B/w Ln(k/T) and 1/T is defined as the enthalpy change that appears in the thermodynamic form of the rate equation obtained from conventional transition state theory. This equation is only correct for a first order reaction, for which the rate constant has the dimension reciprocal time is calculated using Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g]). To calculate Enthalpy of Activation Given Slope of line, you need Slope of Line B/w Ln K and 1/T (m). With our tool, you need to enter the respective value for Slope of Line B/w Ln K and 1/T and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well. Let Others Know