Enthalpy of Activation Given Slope of line Calculator

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✖The slope of Line B/w Ln K and 1/T is defined as when the Lnk (rate constant) is plotted versus the inverse of the temperature (kelvin), the slope is a straight line.ⓘ Slope of Line B/w Ln K and 1/T [m_slope]

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✖Enthalpy of activation is approximately equal to the activation energy; the conversion of one into the other depends on the molecularity.ⓘ Enthalpy of Activation Given Slope of line [H_Activation]

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Formula

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Enthalpy of Activation Given Slope of line

Formula

`"H"_{"Activation"} = -("m"_{"slope"}*2.303*"[Molar-g]")`

Example

`"13.53784J/mol"=-("-0.707K"*2.303*"[Molar-g]")`

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Enthalpy of Activation Given Slope of line Solution

STEP 0: Pre-Calculation Summary

Formula Used

Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g])
H_Activation = -(m_slope*2.303*[Molar-g])
This formula uses 1 Constants, 2 Variables

Constants Used

[Molar-g] - Molar gas constant Value Taken As 8.3145

Variables Used

Enthalpy of Activation - (Measured in Joule Per Mole) - Enthalpy of activation is approximately equal to the activation energy; the conversion of one into the other depends on the molecularity.
Slope of Line B/w Ln K and 1/T - (Measured in Kelvin) - The slope of Line B/w Ln K and 1/T is defined as when the Lnk (rate constant) is plotted versus the inverse of the temperature (kelvin), the slope is a straight line.

STEP 1: Convert Input(s) to Base Unit

Slope of Line B/w Ln K and 1/T: -0.707 Kelvin --> -0.707 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

H_Activation = -(m_slope*2.303*[Molar-g]) --> -((-0.707)*2.303*[Molar-g])

Evaluating ... ...

H_Activation = 13.5378435045

STEP 3: Convert Result to Output's Unit

13.5378435045 Joule Per Mole --> No Conversion Required

FINAL ANSWER

13.5378435045 ≈ 13.53784 Joule Per Mole <-- Enthalpy of Activation

(Calculation completed in 00.004 seconds)

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< 5 Transition State Theory Calculators

Rate Constant of Reaction by Erying Equation

Go Rate Constant = ([BoltZ]*Temperature*exp(Entropy of Activation/[Molar-g])*exp(-Enthalpy of Activation/[Molar-g]*Temperature))/[hP]

Entropy of Activation

Go Entropy of Activation = ([Molar-g]*ln(Pre-Exponential Factor))-[Molar-g]*ln([Molar-g]*Temperature)/[Avaga-no]*[hP]

Enthalpy of Activation

Go Enthalpy of Activation = (Activation Energy-(Change in No of Moles of Gas from Rct to AC*[Molar-g]*Temperature))

Thermodynamic Equilibrium Constant

Go Thermodynamic Equillibrium Constant = e^(Change in Free Energy/([Molar-g]*Temperature))

Enthalpy of Activation Given Slope of line

Go Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g])

Enthalpy of Activation Given Slope of line Formula

Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g])
H_Activation = -(m_slope*2.303*[Molar-g])

What is the Transition State Theory ?

Transition state theory (TST) explains the reaction rates of elementary chemical reactions. The theory assumes a special type of chemical equilibrium (quasi-equilibrium) between reactants and activated transition state complexes.

How to Calculate Enthalpy of Activation Given Slope of line?

Enthalpy of Activation Given Slope of line calculator uses Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g]) to calculate the Enthalpy of Activation, Enthalpy of Activation Given Slope of line B/w Ln(k/T) and 1/T is defined as the enthalpy change that appears in the thermodynamic form of the rate equation obtained from conventional transition state theory. This equation is only correct for a first order reaction, for which the rate constant has the dimension reciprocal time. Enthalpy of Activation is denoted by H_Activation symbol.

How to calculate Enthalpy of Activation Given Slope of line using this online calculator? To use this online calculator for Enthalpy of Activation Given Slope of line, enter Slope of Line B/w Ln K and 1/T (m_slope) and hit the calculate button. Here is how the Enthalpy of Activation Given Slope of line calculation can be explained with given input values -> 13.53784 = -((-0.707)*2.303*[Molar-g]).

FAQ

What is Enthalpy of Activation Given Slope of line?

Enthalpy of Activation Given Slope of line B/w Ln(k/T) and 1/T is defined as the enthalpy change that appears in the thermodynamic form of the rate equation obtained from conventional transition state theory. This equation is only correct for a first order reaction, for which the rate constant has the dimension reciprocal time and is represented as H_Activation = -(m_slope*2.303*[Molar-g]) or Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g]). The slope of Line B/w Ln K and 1/T is defined as when the Lnk (rate constant) is plotted versus the inverse of the temperature (kelvin), the slope is a straight line.

How to calculate Enthalpy of Activation Given Slope of line?

Enthalpy of Activation Given Slope of line B/w Ln(k/T) and 1/T is defined as the enthalpy change that appears in the thermodynamic form of the rate equation obtained from conventional transition state theory. This equation is only correct for a first order reaction, for which the rate constant has the dimension reciprocal time is calculated using Enthalpy of Activation = -(Slope of Line B/w Ln K and 1/T*2.303*[Molar-g]). To calculate Enthalpy of Activation Given Slope of line, you need Slope of Line B/w Ln K and 1/T (m_slope). With our tool, you need to enter the respective value for Slope of Line B/w Ln K and 1/T and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Enthalpy of Activation?

In this formula, Enthalpy of Activation uses Slope of Line B/w Ln K and 1/T. We can use 1 other way(s) to calculate the same, which is/are as follows -

Enthalpy of Activation = (Activation Energy-(Change in No of Moles of Gas from Rct to AC*[Molar-g]*Temperature))

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