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Height of one pyramid of Regular Bipyramid given volume Solution

STEP 0: Pre-Calculation Summary
Formula Used
height_2 = ((2/3)*Base vertices*(Side A^2))/(Volume*4*tan(pi/Base vertices))
h2 = ((2/3)*n*(Sa^2))/(V*4*tan(pi/n))
This formula uses 1 Constants, 1 Functions, 3 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Functions Used
tan - Trigonometric tangent function, tan(Angle)
Variables Used
Base vertices - Base vertices is the number of base vertices of Regular Bipyramid. (Measured in Hundred)
Side A - Side A is an upright or sloping surface of a structure or object that is not the top or bottom and generally not the front or back. (Measured in Meter)
Volume - Volume is the amount of space that a substance or object occupies or that is enclosed within a container. (Measured in Cubic Meter)
STEP 1: Convert Input(s) to Base Unit
Base vertices: 4 Hundred --> 4 Hundred No Conversion Required
Side A: 8 Meter --> 8 Meter No Conversion Required
Volume: 63 Cubic Meter --> 63 Cubic Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
h2 = ((2/3)*n*(Sa^2))/(V*4*tan(pi/n)) --> ((2/3)*4*(8^2))/(63*4*tan(pi/4))
Evaluating ... ...
h2 = 0.677248677248677
STEP 3: Convert Result to Output's Unit
0.677248677248677 Meter -->67.7248677248677 Centimeter (Check conversion here)
FINAL ANSWER
67.7248677248677 Centimeter <-- Height of column2
(Calculation completed in 00.016 seconds)

7 Edge length and Height of Regular Bipyramid Calculators

Total height of Regular Bipyramid given surface area
height_1 = 4*(sqrt(((Surface Area Polyhedron/(Side A*Base vertices))^2)-((1/4)*(Side A^2)*((cot(pi/Base vertices))^2)))) Go
Height of one pyramid of Regular Bipyramid given surface area
height_2 = sqrt(((Surface Area Polyhedron/(Base vertices*Side A))^2)-((1/4)*(Side A^2)*((cot(pi/Base vertices))^2))) Go
Edge length n gon of Regular Bipyramid given volume
side_a = sqrt((Volume*4*(tan(pi/Base vertices))*Height of column2)/((2/3)*Base vertices)) Go
Total height of Regular Bipyramid given volume
height_1 = 2*((2/3)*Base vertices*(Side A^2))/(4*Volume*(tan(pi/Base vertices))) Go
Height of one pyramid of Regular Bipyramid given volume
height_2 = ((2/3)*Base vertices*(Side A^2))/(Volume*4*tan(pi/Base vertices)) Go
Total height of Regular Bipyramid given height of one pyramid
height_1 = 2*Height of column2 Go
Height of one pyramid of Regular Bipyramid given total height
height_2 = Height of column1/2 Go

Height of one pyramid of Regular Bipyramid given volume Formula

height_2 = ((2/3)*Base vertices*(Side A^2))/(Volume*4*tan(pi/Base vertices))
h2 = ((2/3)*n*(Sa^2))/(V*4*tan(pi/n))

What is a Regular Bipyramid?

A n-gonal bipyramid or dipyramid is a polyhedron formed by joining an n-gonal pyramid and its mirror image base-to-base. An n-gonal bipyramid has 2n triangle faces, 3n edges, and 2 + n vertices.

How to Calculate Height of one pyramid of Regular Bipyramid given volume?

Height of one pyramid of Regular Bipyramid given volume calculator uses height_2 = ((2/3)*Base vertices*(Side A^2))/(Volume*4*tan(pi/Base vertices)) to calculate the Height of column2, Height of one pyramid of Regular Bipyramid given volume formula is defined as the measurement of one pyramid from head to foot or from base to top. Height of column2 and is denoted by h2 symbol.

How to calculate Height of one pyramid of Regular Bipyramid given volume using this online calculator? To use this online calculator for Height of one pyramid of Regular Bipyramid given volume, enter Base vertices (n), Side A (Sa) & Volume (V) and hit the calculate button. Here is how the Height of one pyramid of Regular Bipyramid given volume calculation can be explained with given input values -> 67.72487 = ((2/3)*4*(8^2))/(63*4*tan(pi/4)).

FAQ

What is Height of one pyramid of Regular Bipyramid given volume?
Height of one pyramid of Regular Bipyramid given volume formula is defined as the measurement of one pyramid from head to foot or from base to top and is represented as h2 = ((2/3)*n*(Sa^2))/(V*4*tan(pi/n)) or height_2 = ((2/3)*Base vertices*(Side A^2))/(Volume*4*tan(pi/Base vertices)). Base vertices is the number of base vertices of Regular Bipyramid, Side A is an upright or sloping surface of a structure or object that is not the top or bottom and generally not the front or back & Volume is the amount of space that a substance or object occupies or that is enclosed within a container.
How to calculate Height of one pyramid of Regular Bipyramid given volume?
Height of one pyramid of Regular Bipyramid given volume formula is defined as the measurement of one pyramid from head to foot or from base to top is calculated using height_2 = ((2/3)*Base vertices*(Side A^2))/(Volume*4*tan(pi/Base vertices)). To calculate Height of one pyramid of Regular Bipyramid given volume, you need Base vertices (n), Side A (Sa) & Volume (V). With our tool, you need to enter the respective value for Base vertices, Side A & Volume and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Height of column2?
In this formula, Height of column2 uses Base vertices, Side A & Volume. We can use 7 other way(s) to calculate the same, which is/are as follows -
  • height_1 = 2*Height of column2
  • height_2 = Height of column1/2
  • height_2 = sqrt(((Surface Area Polyhedron/(Base vertices*Side A))^2)-((1/4)*(Side A^2)*((cot(pi/Base vertices))^2)))
  • height_2 = ((2/3)*Base vertices*(Side A^2))/(Volume*4*tan(pi/Base vertices))
  • height_1 = 4*(sqrt(((Surface Area Polyhedron/(Side A*Base vertices))^2)-((1/4)*(Side A^2)*((cot(pi/Base vertices))^2))))
  • height_1 = 2*((2/3)*Base vertices*(Side A^2))/(4*Volume*(tan(pi/Base vertices)))
  • side_a = sqrt((Volume*4*(tan(pi/Base vertices))*Height of column2)/((2/3)*Base vertices))
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