Helmholtz Free Entropy given Classical and Electric Part Calculator

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✖The Classical helmholtz free entropy expresses the effect of electrostatic forces in an electrolyte on its classical thermodynamic state.ⓘ Classical Helmholtz Free Entropy [Φ_k]			+10% -10%
✖The Electric helmholtz free entropy is used to express the effect of electrostatic forces in an electrolyte on its electric thermodynamic state.ⓘ Electric Helmholtz Free Entropy [Φ_e]			+10% -10%

✖The Helmholtz Free Entropy is used to express the effect of electrostatic forces in an electrolyte on its thermodynamic state.ⓘ Helmholtz Free Entropy given Classical and Electric Part [Φ]

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Formula

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Helmholtz Free Entropy given Classical and Electric Part

Formula

`"Φ" = ("Φ"_{"k"}+"Φ"_{"e"})`

Example

`"118J/K"=("68J/K"+"50J/K")`

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Helmholtz Free Entropy given Classical and Electric Part Solution

STEP 0: Pre-Calculation Summary

Formula Used

Helmholtz Free Entropy = (Classical Helmholtz Free Entropy+Electric Helmholtz Free Entropy)
Φ = (Φ_k+Φ_e)
This formula uses 3 Variables

Variables Used

Helmholtz Free Entropy - (Measured in Joule per Kelvin) - The Helmholtz Free Entropy is used to express the effect of electrostatic forces in an electrolyte on its thermodynamic state.
Classical Helmholtz Free Entropy - (Measured in Joule per Kelvin) - The Classical helmholtz free entropy expresses the effect of electrostatic forces in an electrolyte on its classical thermodynamic state.
Electric Helmholtz Free Entropy - (Measured in Joule per Kelvin) - The Electric helmholtz free entropy is used to express the effect of electrostatic forces in an electrolyte on its electric thermodynamic state.

STEP 1: Convert Input(s) to Base Unit

Classical Helmholtz Free Entropy: 68 Joule per Kelvin --> 68 Joule per Kelvin No Conversion Required
Electric Helmholtz Free Entropy: 50 Joule per Kelvin --> 50 Joule per Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

Φ = (Φ_k+Φ_e) --> (68+50)

Evaluating ... ...

Φ = 118

STEP 3: Convert Result to Output's Unit

118 Joule per Kelvin --> No Conversion Required

FINAL ANSWER

118 Joule per Kelvin <-- Helmholtz Free Entropy

(Calculation completed in 00.004 seconds)

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Created by Prashant Singh

K J Somaiya College of science (K J Somaiya), Mumbai

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Volume given Gibbs and Helmholtz Free Entropy

Go Volume given Gibbs and Helmholtz Entropy = ((Helmholtz Entropy-Gibbs Free Entropy)*Temperature)/Pressure

Gibbs Free Entropy given Helmholtz Free Entropy

Go Gibbs Free Entropy = Helmholtz Free Entropy-((Pressure*Volume)/Temperature)

Pressure given Gibbs and Helmholtz Free Entropy

Go Pressure = ((Helmholtz Free Entropy-Gibbs Free Entropy)*Temperature)/Volume

Gibbs Free Energy Change

Go Gibbs Free Energy Change = -Number of Moles of Electron*[Faraday]/Electrode Potential of a System

Electrode Potential given Gibbs Free Energy

Go Electrode Potential = -Gibbs Free Energy Change/(Number of Moles of Electron*[Faraday])

Cell Potential given Change in Gibbs Free Energy

Go Cell Potential = -Gibbs Free Energy Change/(Moles of Electron Transferred*[Faraday])

Classical Part of Gibbs Free Entropy given Electric Part

Go Classical part gibbs free entropy = (Gibbs Free Entropy of System-Electric part gibbs free entropy)

Helmholtz Free Entropy

Go Helmholtz Free Entropy = (Entropy-(Internal Energy/Temperature))

Entropy given Internal Energy and Helmholtz Free Entropy

Go Entropy = Helmholtz Free Entropy+(Internal Energy/Temperature)

Internal Energy given Helmholtz Free Entropy and Entropy

Go Internal Energy = (Entropy-Helmholtz Free Entropy)*Temperature

Classical Part of Helmholtz Free Entropy given Electric Part

Go Classical Helmholtz Free Entropy = (Helmholtz Free Entropy-Electric Helmholtz Free Entropy)

Electric Part of Helmholtz Free Entropy given Classical Part

Go Electric Helmholtz Free Entropy = (Helmholtz Free Entropy-Classical Helmholtz Free Entropy)

Helmholtz Free Entropy given Classical and Electric Part

Go Helmholtz Free Entropy = (Classical Helmholtz Free Entropy+Electric Helmholtz Free Entropy)

Gibbs Free Energy

Go Gibbs Free Energy = Enthalpy-Temperature*Entropy

Helmholtz Free Energy given Helmholtz Free Entropy and Temperature

Go Helmholtz Free Energy of System = -(Helmholtz Free Entropy*Temperature)

Helmholtz Free Entropy given Helmholtz Free Energy

Go Helmholtz Free Entropy = -(Helmholtz Free Energy of System/Temperature)

Gibbs Free Energy given Gibbs Free Entropy

Go Gibbs Free Energy = (-Gibbs Free Entropy*Temperature)

Helmholtz Free Entropy given Classical and Electric Part Formula

Helmholtz Free Entropy = (Classical Helmholtz Free Entropy+Electric Helmholtz Free Entropy)
Φ = (Φ_k+Φ_e)

What is Debye–Hückel limiting law?

The chemists Peter Debye and Erich Hückel noticed that solutions that contain ionic solutes do not behave ideally even at very low concentrations. So, while the concentration of the solutes is fundamental to the calculation of the dynamics of a solution, they theorized that an extra factor that they termed gamma is necessary to the calculation of the activity coefficients of the solution. Hence they developed the Debye–Hückel equation and Debye–Hückel limiting law. The activity is only proportional to the concentration and is altered by a factor known as the activity coefficient . This factor takes into account the interaction energy of ions in solution.

How to Calculate Helmholtz Free Entropy given Classical and Electric Part?

Helmholtz Free Entropy given Classical and Electric Part calculator uses Helmholtz Free Entropy = (Classical Helmholtz Free Entropy+Electric Helmholtz Free Entropy) to calculate the Helmholtz Free Entropy, The Helmholtz free entropy given classical and electric part formula is defined as the submission of classical and electric part of Helmholtz free entropy. Helmholtz Free Entropy is denoted by Φ symbol.

How to calculate Helmholtz Free Entropy given Classical and Electric Part using this online calculator? To use this online calculator for Helmholtz Free Entropy given Classical and Electric Part, enter Classical Helmholtz Free Entropy (Φ_k) & Electric Helmholtz Free Entropy (Φ_e) and hit the calculate button. Here is how the Helmholtz Free Entropy given Classical and Electric Part calculation can be explained with given input values -> 118 = (68+50).

FAQ

What is Helmholtz Free Entropy given Classical and Electric Part?

The Helmholtz free entropy given classical and electric part formula is defined as the submission of classical and electric part of Helmholtz free entropy and is represented as Φ = (Φ_k+Φ_e) or Helmholtz Free Entropy = (Classical Helmholtz Free Entropy+Electric Helmholtz Free Entropy). The Classical helmholtz free entropy expresses the effect of electrostatic forces in an electrolyte on its classical thermodynamic state & The Electric helmholtz free entropy is used to express the effect of electrostatic forces in an electrolyte on its electric thermodynamic state.

How to calculate Helmholtz Free Entropy given Classical and Electric Part?

The Helmholtz free entropy given classical and electric part formula is defined as the submission of classical and electric part of Helmholtz free entropy is calculated using Helmholtz Free Entropy = (Classical Helmholtz Free Entropy+Electric Helmholtz Free Entropy). To calculate Helmholtz Free Entropy given Classical and Electric Part, you need Classical Helmholtz Free Entropy (Φ_k) & Electric Helmholtz Free Entropy (Φ_e). With our tool, you need to enter the respective value for Classical Helmholtz Free Entropy & Electric Helmholtz Free Entropy and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Helmholtz Free Entropy?

In this formula, Helmholtz Free Entropy uses Classical Helmholtz Free Entropy & Electric Helmholtz Free Entropy. We can use 2 other way(s) to calculate the same, which is/are as follows -

Helmholtz Free Entropy = (Entropy-(Internal Energy/Temperature))
Helmholtz Free Entropy = -(Helmholtz Free Energy of System/Temperature)

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