Intensity terms of Number of Photons absorbed in 1 second Solution

STEP 0: Pre-Calculation Summary
Formula Used
Intensity in number of photons = Intensity in J per second/Energy per Quantum
Ia = I/EQuantum
This formula uses 3 Variables
Variables Used
Intensity in number of photons - Intensity in number of photons is the intensity which is in terms of the number of photons which is absorbed in the time interval of 1 second.
Intensity in J per second - (Measured in Watt) - Intensity in J per second is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy.
Energy per Quantum - (Measured in Joule) - Energy per Quantum is the energy of a molecule per quantum of radiation which is absorbed during a photochemical reaction.
STEP 1: Convert Input(s) to Base Unit
Intensity in J per second: 10 Joule per Second --> 10 Watt (Check conversion here)
Energy per Quantum: 95 Joule --> 95 Joule No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Ia = I/EQuantum --> 10/95
Evaluating ... ...
Ia = 0.105263157894737
STEP 3: Convert Result to Output's Unit
0.105263157894737 --> No Conversion Required
FINAL ANSWER
0.105263157894737 0.105263 <-- Intensity in number of photons
(Calculation completed in 00.004 seconds)

Credits

Created by Akshada Kulkarni
National Institute of Information Technology (NIIT), Neemrana
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18 Stark-Einstein law Calculators

Energy of Photochemical Reaction terms of Wavelength
Go Energy in Photochemical Reaction = ([Avaga-no]*[hP]*[c])/Wavelength
Wavelength given Energy of Reaction
Go Wavelength = ([Avaga-no]*[hP]*[c])/Energy in Photochemical Reaction
Number of Quanta absorbed in 1 second using Quantum Efficiency of Reactant
Go Number of Quanta Absorbed = Reactant Molecules Consumed per Second /Quantum efficiency for reactants
Number of Molecules of Reactant consumed in 1 second
Go Reactant Molecules Consumed per Second = Quantum efficiency for reactants*Number of Quanta Absorbed
Quantum Efficiency for Disappearance of Reactant
Go Quantum efficiency for reactants = Reactant Molecules Consumed per Second/Number of Quanta Absorbed
Number of Quanta absorbed in 1 second using Quantum Efficiency of Products
Go Number of Quanta Absorbed = Product Molecules Formed per Second /Quantum Efficiency for Products
Number of Molecules of Product formed in 1 second
Go Product Molecules Formed per Second = Quantum Efficiency for Products*Number of Quanta Absorbed
Quantum Efficiency for Formation of Product
Go Quantum Efficiency for Products = Product Molecules Formed per Second/Number of Quanta Absorbed
Frequency given Energy of Reaction
Go Frequency = Energy in Photochemical Reaction/[Avaga-no]*[hP]
Energy of Photochemical Reaction
Go Energy in Photochemical Reaction = [Avaga-no]*[hP]*Frequency
Intensity of Transmitted Light
Go Intensity of Transmitted Light = Intensity of incident light-Intensity of Light Absorbed
Intensity of Incident Light
Go Intensity of incident light = Intensity of Light Absorbed+Intensity of Transmitted Light
Intensity of Light Absorbed
Go Intensity of Light Absorbed = Intensity of incident light-Intensity of Transmitted Light
Intensity in J per second given Intensity terms of Photons
Go Intensity in J per second = Intensity in number of photons*Energy per Quantum
Intensity terms of Number of Photons absorbed in 1 second
Go Intensity in number of photons = Intensity in J per second/Energy per Quantum
Energy per Quantum given Intensity
Go Energy per Quantum = Intensity in J per second/Intensity in number of photons
Energy per Quantum of Radiation terms of Wavelength
Go Energy per Quantum = ([hP]*[c])/Wavelength
Energy per Quantum of Radiation Absorbed
Go Energy per Quantum = [hP]*Frequency

Intensity terms of Number of Photons absorbed in 1 second Formula

Intensity in number of photons = Intensity in J per second/Energy per Quantum
Ia = I/EQuantum

What is Stark-Einstein law of photochemical equivalence?

Stark-Einstein law of photochemical equivalence can be stated as follows:
Each molecule taking part in a photochemical reaction absorbs one quantum of radiation
which causes the reaction. This law is applicable to the primary act of excitation of a molecule by light absorption. This law helps in calculating the quantum efficiency which is a measure of the efficiency of the use of light in a photochemical reaction.

What is Grotthuss-Draper Law?

According to this law, only the light that is absorbed by a molecule can produce a
photochemical change in it. This means that it is not sufficient to pass light through a
substance to bring about a chemical reaction; but the light must be absorbed by it.
Stark-Einstein law of photochemical equivalence provides a quantum mechanical form to
Grotthuss-Draper law.

How to Calculate Intensity terms of Number of Photons absorbed in 1 second?

Intensity terms of Number of Photons absorbed in 1 second calculator uses Intensity in number of photons = Intensity in J per second/Energy per Quantum to calculate the Intensity in number of photons, The Intensity terms of number of photons absorbed in 1 second formula is defined as the intensity which is in terms of the number of photons which is absorbed in the time interval of 1 second. Intensity in number of photons is denoted by Ia symbol.

How to calculate Intensity terms of Number of Photons absorbed in 1 second using this online calculator? To use this online calculator for Intensity terms of Number of Photons absorbed in 1 second, enter Intensity in J per second (I) & Energy per Quantum (EQuantum) and hit the calculate button. Here is how the Intensity terms of Number of Photons absorbed in 1 second calculation can be explained with given input values -> 0.105263 = 10/95.

FAQ

What is Intensity terms of Number of Photons absorbed in 1 second?
The Intensity terms of number of photons absorbed in 1 second formula is defined as the intensity which is in terms of the number of photons which is absorbed in the time interval of 1 second and is represented as Ia = I/EQuantum or Intensity in number of photons = Intensity in J per second/Energy per Quantum. Intensity in J per second is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy & Energy per Quantum is the energy of a molecule per quantum of radiation which is absorbed during a photochemical reaction.
How to calculate Intensity terms of Number of Photons absorbed in 1 second?
The Intensity terms of number of photons absorbed in 1 second formula is defined as the intensity which is in terms of the number of photons which is absorbed in the time interval of 1 second is calculated using Intensity in number of photons = Intensity in J per second/Energy per Quantum. To calculate Intensity terms of Number of Photons absorbed in 1 second, you need Intensity in J per second (I) & Energy per Quantum (EQuantum). With our tool, you need to enter the respective value for Intensity in J per second & Energy per Quantum and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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