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Interchange factor for two rectangles with common side at right angles to each other Solution

STEP 0: Pre-Calculation Summary
Formula Used
interchange_factor = Emissivity of body 1*Emissivity of body 2
f1-2 = ε1*ε2
This formula uses 2 Variables
Variables Used
Emissivity of body 1- Emissivity of body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
Emissivity of body 2- Emissivity of body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
STEP 1: Convert Input(s) to Base Unit
Emissivity of body 1: 0.4 --> No Conversion Required
Emissivity of body 2: 0.3 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
f1-2 = ε1*ε2 --> 0.4*0.3
Evaluating ... ...
f1-2 = 0.12
STEP 3: Convert Result to Output's Unit
0.12 --> No Conversion Required
0.12 <-- Interchange Factor
(Calculation completed in 00.000 seconds)

< 5 Interchange factor between surfaces Calculators

Interchange factor for infinitely long concentric cylinders
interchange_factor = ((1/Emissivity of body 1)+((Surface area of body 1/Surface area of body 2)*((1/Emissivity of body 2)-1)))^(-1) Go
Interchange factor for large body enclosed by another body
interchange_factor = ((1/Emissivity of body 1)+((Surface area of body 1/Surface area of body 2)*((1/Emissivity of body 2)-1)))^(-1) Go
Interchange factor for infinitely long concentric spheres
interchange_factor = ((1/Emissivity of body 1)+((Surface area of body 1/Surface area of body 2)*((1/Emissivity of body 2)-1)))^(-1) Go
Infinite parallel planes
interchange_factor = ((1/Emissivity of body 1)+(1/Emissivity of body 2)-1)^(-1) Go
Interchange factor for two rectangles with common side at right angles to each other
interchange_factor = Emissivity of body 1*Emissivity of body 2 Go

Interchange factor for two rectangles with common side at right angles to each other Formula

interchange_factor = Emissivity of body 1*Emissivity of body 2
f1-2 = ε1*ε2

What is Interchange factor?

Interchange factor is defined as the fraction of the energy leaving an isothermal area of a body that is incident upon the area of another body. It is also known as the Equivalent Emissivity.

What is Emissivity?

Emissivity is defined as the ratio of the energy radiated from a material's surface to that radiated from a perfect emitter known as a blackbody, at the same temperature and wavelength and under the same viewing conditions. It is a dimensionless number between 0 (for a perfect reflector) and 1 (for a perfect emitter).

How to Calculate Interchange factor for two rectangles with common side at right angles to each other?

Interchange factor for two rectangles with common side at right angles to each other calculator uses interchange_factor = Emissivity of body 1*Emissivity of body 2 to calculate the Interchange Factor, The Interchange factor for two rectangles with common side at right angles to each other formula calculates the interchange factor which is the fraction of the energy leaving the surface area of rectangle 1 that is incident upon the surface area of rectangle 2 where the common sides of rectangles are at right angles to each other. Interchange Factor is denoted by f1-2 symbol.

How to calculate Interchange factor for two rectangles with common side at right angles to each other using this online calculator? To use this online calculator for Interchange factor for two rectangles with common side at right angles to each other, enter Emissivity of body 1 1) & Emissivity of body 2 2) and hit the calculate button. Here is how the Interchange factor for two rectangles with common side at right angles to each other calculation can be explained with given input values -> 0.12 = 0.4*0.3.

FAQ

What is Interchange factor for two rectangles with common side at right angles to each other?
The Interchange factor for two rectangles with common side at right angles to each other formula calculates the interchange factor which is the fraction of the energy leaving the surface area of rectangle 1 that is incident upon the surface area of rectangle 2 where the common sides of rectangles are at right angles to each other and is represented as f1-2 = ε1*ε2 or interchange_factor = Emissivity of body 1*Emissivity of body 2. Emissivity of body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter & Emissivity of body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
How to calculate Interchange factor for two rectangles with common side at right angles to each other?
The Interchange factor for two rectangles with common side at right angles to each other formula calculates the interchange factor which is the fraction of the energy leaving the surface area of rectangle 1 that is incident upon the surface area of rectangle 2 where the common sides of rectangles are at right angles to each other is calculated using interchange_factor = Emissivity of body 1*Emissivity of body 2. To calculate Interchange factor for two rectangles with common side at right angles to each other, you need Emissivity of body 1 1) & Emissivity of body 2 2). With our tool, you need to enter the respective value for Emissivity of body 1 & Emissivity of body 2 and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Interchange Factor?
In this formula, Interchange Factor uses Emissivity of body 1 & Emissivity of body 2. We can use 5 other way(s) to calculate the same, which is/are as follows -
• interchange_factor = ((1/Emissivity of body 1)+(1/Emissivity of body 2)-1)^(-1)
• interchange_factor = ((1/Emissivity of body 1)+((Surface area of body 1/Surface area of body 2)*((1/Emissivity of body 2)-1)))^(-1)
• interchange_factor = ((1/Emissivity of body 1)+((Surface area of body 1/Surface area of body 2)*((1/Emissivity of body 2)-1)))^(-1)
• interchange_factor = Emissivity of body 1*Emissivity of body 2
• interchange_factor = ((1/Emissivity of body 1)+((Surface area of body 1/Surface area of body 2)*((1/Emissivity of body 2)-1)))^(-1) Let Others Know