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Length Using Area Of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity)
l = a4*W*(Vm*cos(ϑ))^2/(4*(P^2)*ρ)
This formula uses 1 Functions, 6 Variables
Functions Used
cos - Trigonometric cosine function, cos(Angle)
Variables Used
Area Of 1-Φ 2-wire system - The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Maximum Voltage - Maximum Voltage the highest voltage rating for electrical devices (Measured in Volt)
Theta - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint. (Measured in Degree)
Power Transmitted - The Power Transmitted Value through a shaft. (Measured in Kilowatt)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
STEP 1: Convert Input(s) to Base Unit
Area Of 1-Φ 2-wire system: 6 Square Meter --> 6 Square Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Power Transmitted: 10 Kilowatt --> 10000 Watt (Check conversion here)
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
l = a4*W*(Vm*cos(ϑ))^2/(4*(P^2)*ρ) --> 6*0.6*(60*cos(0.5235987755982))^2/(4*(10000^2)*1.7E-05)
Evaluating ... ...
l = 1.42941176470588
STEP 3: Convert Result to Output's Unit
1.42941176470588 Meter --> No Conversion Required
FINAL ANSWER
1.42941176470588 Meter <-- Length
(Calculation completed in 00.031 seconds)

9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-Section (1-Phase 2-Wire US)
power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length)) Go
Maximum Voltage Using Area Of X-Section (1-Phase 2-Wire US)
maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2)) Go
RMS Voltage Using Area Of X-Section (1-Phase 2-Wire US)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-Section (1-Phase 2-Wire US)
power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2))) Go
Resistivity Using Area Of X-Section (1-Phase 2-Wire US)
resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2)) Go
Line Losses Using Area Of X-Section (1-Phase 2-Wire US)
line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Using Area Of X-Section (1-Phase 2-Wire US)
length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity) Go
Constant Using Area Of X-Section (1-Phase 2-Wire US)
constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2 Go
Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US)
volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2 Go

Length Using Area Of X-Section (1-Phase 2-Wire US) Formula

length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity)
l = a4*W*(Vm*cos(ϑ))^2/(4*(P^2)*ρ)

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Length Using Area Of X-Section (1-Phase 2-Wire US)?

Length Using Area Of X-Section (1-Phase 2-Wire US) calculator uses length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity) to calculate the Length, The Length Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system. Length and is denoted by l symbol.

How to calculate Length Using Area Of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Length Using Area Of X-Section (1-Phase 2-Wire US), enter Area Of 1-Φ 2-wire system (a4), Line Losses (W), Maximum Voltage (Vm), Theta (ϑ), Power Transmitted (P) and Resistivity (ρ) and hit the calculate button. Here is how the Length Using Area Of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 1.429412 = 6*0.6*(60*cos(0.5235987755982))^2/(4*(10000^2)*1.7E-05).

FAQ

What is Length Using Area Of X-Section (1-Phase 2-Wire US)?
The Length Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system and is represented as l = a4*W*(Vm*cos(ϑ))^2/(4*(P^2)*ρ) or length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity). The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object, Line Losses is defined as the losses that are produced in the line, Maximum Voltage the highest voltage rating for electrical devices, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint, The Power Transmitted Value through a shaft and Resistivity is the measure of how strongly a material opposes the flow of current through them.
How to calculate Length Using Area Of X-Section (1-Phase 2-Wire US)?
The Length Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system is calculated using length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity). To calculate Length Using Area Of X-Section (1-Phase 2-Wire US), you need Area Of 1-Φ 2-wire system (a4), Line Losses (W), Maximum Voltage (Vm), Theta (ϑ), Power Transmitted (P) and Resistivity (ρ). With our tool, you need to enter the respective value for Area Of 1-Φ 2-wire system, Line Losses, Maximum Voltage, Theta, Power Transmitted and Resistivity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Length?
In this formula, Length uses Area Of 1-Φ 2-wire system, Line Losses, Maximum Voltage, Theta, Power Transmitted and Resistivity. We can use 9 other way(s) to calculate the same, which is/are as follows -
  • power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length))
  • resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2))
  • length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity)
  • line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2))
  • maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2))
  • rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
  • power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2)))
  • constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2
  • volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2
Where is the Length Using Area Of X-Section (1-Phase 2-Wire US) calculator used?
Among many, Length Using Area Of X-Section (1-Phase 2-Wire US) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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