Length using Line Losses (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
L = Ploss*A*(Vm*cos(Φ))^2/(4*(P^2)*ρ)
This formula uses 1 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
Variables Used
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
STEP 1: Convert Input(s) to Base Unit
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
L = Ploss*A*(Vm*cos(Φ))^2/(4*(P^2)*ρ) --> 2.67*1.28*(230*cos(0.5235987755982))^2/(4*(300^2)*1.7E-05)
Evaluating ... ...
L = 22155.7647058824
STEP 3: Convert Result to Output's Unit
22155.7647058824 Meter --> No Conversion Required
FINAL ANSWER
22155.7647058824 22155.76 Meter <-- Length of Underground AC Wire
(Calculation completed in 00.004 seconds)

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23 Wire Parameters Calculators

Area of X-Section using Line Losses (1-Phase 2-Wire US)
Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Area of X-Section (1-Phase 2-Wire US)
Go Area of Underground AC Wire = (4)*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Length using Area of X-Section (1-Phase 2-Wire US)
Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
Length using Line Losses (1-Phase 2-Wire US)
Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
Volume of Conductor Material using Line Losses (1-Phase 2-Wire US)
Go Volume Of Conductor = 8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
Constant using Resistance (1-Phase 2-Wire US)
Go Constant Underground AC = (4*Power Transmitted*Length of Underground AC Wire*Resistance Underground AC*Area of Underground AC Wire)/(Line Losses*(Maximum Voltage Underground AC^2))
Length of Wire using Constant (1-Phase 2-Wire US)
Go Length of Underground AC Wire = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Power Transmitted)^2))
Constant using Load Current (1-Phase 2-Wire US)
Go Constant Underground AC = 2*(Current Underground AC^2)*(cos(Phase Difference)^2)*Resistivity*(Length of Underground AC Wire^2)/Line Losses
Constant (1-Phase 2-Wire US)
Go Constant Underground AC = 4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)
Constant using Line Losses (1-Phase 2-Wire US)
Go Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2)
Length using Load Current (1-Phase 2-Wire US)
Go Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)
Area of X-Section using Load Current (1-Phase 2-Wire US)
Go Area of Underground AC Wire = 2*(Current Underground AC)^2*Resistivity*Length of Underground AC Wire/(Line Losses)
Volume of Conductor Material using Load Current (1-Phase 2-Wire US)
Go Volume Of Conductor = 4*(Current Underground AC^2)*Resistivity*(Length of Underground AC Wire^2)/(Line Losses)
Constant using Area of X-Section (1-Phase 2-Wire US)
Go Constant Underground AC = Area of Underground AC Wire*Length of Underground AC Wire*(cos(Phase Difference))^2
Area of X-Section using Constant (1-Phase 2-Wire US)
Go Area of Underground AC Wire = Constant Underground AC/Length of Underground AC Wire*(cos(Phase Difference))^2
Length using Resistance (1-Phase 2-Wire US)
Go Length of Underground AC Wire = (Resistance Underground AC*Area of Underground AC Wire)/(Resistivity)
Area of X-Section using Resistance (1-Phase 2-Wire US)
Go Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/Resistance Underground AC
Constant using Volume of Conductor Material (1-Phase 2-Wire US)
Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference))^2/2
Volume of Conductor Material using Constant (1-Phase 2-Wire US)
Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
Voltage of Conductor Material (1-Phase 2-Wire US)
Go Volume Of Conductor = 2*Constant Underground AC/(cos(Phase Difference))^2
Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)
Go Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)
Length using Volume of Conductor Material (1-Phase 2-Wire US)
Go Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
Volume of Conductor Material using Area of X-Section (1-Phase 2-Wire US)
Go Volume Of Conductor = Area of Underground AC Wire*Length of Underground AC Wire*2

Length using Line Losses (1-Phase 2-Wire US) Formula

Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
L = Ploss*A*(Vm*cos(Φ))^2/(4*(P^2)*ρ)

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Length using Line Losses (1-Phase 2-Wire US)?

Length using Line Losses (1-Phase 2-Wire US) calculator uses Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity) to calculate the Length of Underground AC Wire, The Length using Line Losses (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system. Length of Underground AC Wire is denoted by L symbol.

How to calculate Length using Line Losses (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Length using Line Losses (1-Phase 2-Wire US), enter Line Losses (Ploss), Area of Underground AC Wire (A), Maximum Voltage Underground AC (Vm), Phase Difference (Φ), Power Transmitted (P) & Resistivity (ρ) and hit the calculate button. Here is how the Length using Line Losses (1-Phase 2-Wire US) calculation can be explained with given input values -> 22155.76 = 2.67*1.28*(230*cos(0.5235987755982))^2/(4*(300^2)*1.7E-05).

FAQ

What is Length using Line Losses (1-Phase 2-Wire US)?
The Length using Line Losses (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system and is represented as L = Ploss*A*(Vm*cos(Φ))^2/(4*(P^2)*ρ) or Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity). Line Losses is defined as the total losses occurring in an Underground AC line when in use, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work & Resistivity is the measure of how strongly a material opposes the flow of current through them.
How to calculate Length using Line Losses (1-Phase 2-Wire US)?
The Length using Line Losses (1-Phase 2-Wire US) formula is defined as the total length of the wire that used in the single-phase two-wire system is calculated using Length of Underground AC Wire = Line Losses*Area of Underground AC Wire*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity). To calculate Length using Line Losses (1-Phase 2-Wire US), you need Line Losses (Ploss), Area of Underground AC Wire (A), Maximum Voltage Underground AC (Vm), Phase Difference (Φ), Power Transmitted (P) & Resistivity (ρ). With our tool, you need to enter the respective value for Line Losses, Area of Underground AC Wire, Maximum Voltage Underground AC, Phase Difference, Power Transmitted & Resistivity and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Length of Underground AC Wire?
In this formula, Length of Underground AC Wire uses Line Losses, Area of Underground AC Wire, Maximum Voltage Underground AC, Phase Difference, Power Transmitted & Resistivity. We can use 5 other way(s) to calculate the same, which is/are as follows -
  • Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2/(4*(Power Transmitted^2)*Resistivity)
  • Length of Underground AC Wire = Volume Of Conductor/(2*Area of Underground AC Wire)
  • Length of Underground AC Wire = (Line Losses*Area of Underground AC Wire)/(2*(Current Underground AC)^2*Resistivity)
  • Length of Underground AC Wire = (Resistance Underground AC*Area of Underground AC Wire)/(Resistivity)
  • Length of Underground AC Wire = sqrt(Constant Underground AC*Line Losses*(Maximum Voltage Underground AC^2)/(4*Resistivity*(Power Transmitted)^2))
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