Line Losses using Volume of Conductor Material(DC Three-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Line Losses = 5*Resistivity*((Power Transmitted*Length of Wire DC)^2)/(Volume Of Conductor*(Maximum Voltage^2))
Pline = 5*ρ*((P*l)^2)/(V*(Vm^2))
This formula uses 6 Variables
Variables Used
Line Losses - (Measured in Watt) - Line Losses is defined as the losses that are produced in the line.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Length of Wire DC - (Measured in Meter) - Length of Wire DC is the measurement or extent of something from end to end.
Volume Of Conductor - (Measured in Cubic Meter) - Volume Of Conductor the 3-dimensional space enclosed by a conductor material.
Maximum Voltage - (Measured in Volt) - Maximum Voltage the highest voltage rating for electrical devices.
STEP 1: Convert Input(s) to Base Unit
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Length of Wire DC: 3.2 Meter --> 3.2 Meter No Conversion Required
Volume Of Conductor: 35 Cubic Meter --> 35 Cubic Meter No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Pline = 5*ρ*((P*l)^2)/(V*(Vm^2)) --> 5*1.7E-05*((300*3.2)^2)/(35*(60^2))
Evaluating ... ...
Pline = 0.000621714285714286
STEP 3: Convert Result to Output's Unit
0.000621714285714286 Watt --> No Conversion Required
FINAL ANSWER
0.000621714285714286 0.000622 Watt <-- Line Losses
(Calculation completed in 00.004 seconds)

Credits

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15 Wire Parameters Calculators

Volume of Conductor Material using Resistance (DC Three-Wire US)
​ Go Volume Of Conductor = (5*(Power Transmitted^2)*Resistance underground DC*Length of Wire DC*Area of underground dc wire)/(Line Losses*(Maximum Voltage^2))
Length using Volume of Conductor Material(DC Three-Wire US)
​ Go Length of Wire DC = sqrt(Volume Of Conductor*Line Losses*(Maximum Voltage^2)/((5)*Resistivity*(Power Transmitted^2)))
Length using Area of X-Section (DC Three-Wire US)
​ Go Length of Wire DC = Area of underground dc wire*Line Losses*(Maximum Voltage^2)/(2*Resistivity*(Power Transmitted^2))
Area of X-Section (DC Three-Wire US)
​ Go Area of underground dc wire = 2*(Power Transmitted^2)*Resistivity*Length of Wire DC/(Line Losses*(Maximum Voltage^2))
Line Losses (DC Three-Wire US)
​ Go Line Losses = 2*(Power Transmitted^2)*Resistivity*Length of Wire DC/((Maximum Voltage^2)*Area of underground dc wire)
Volume of Conductor Material (DC Three-Wire US)
​ Go Volume Of Conductor = 5*(Power Transmitted^2)*Resistivity*(Length of Wire DC^2)/(Line Losses*(Maximum Voltage^2))
Line Losses using Volume of Conductor Material(DC Three-Wire US)
​ Go Line Losses = 5*Resistivity*((Power Transmitted*Length of Wire DC)^2)/(Volume Of Conductor*(Maximum Voltage^2))
Line Losses using Area of X-Section (DC Three-Wire US)
​ Go Line Losses = 2*(Current underground DC^2)*Resistivity*Length of Wire DC/(Area of underground dc wire)
Length using Line Losses (DC Three-Wire US)
​ Go Length of Wire DC = Area of underground dc wire*Line Losses/(2*Resistivity*(Current underground DC^2))
Volume of Conductor Material using Load Current (DC Three-Wire US)
​ Go Volume Of Conductor = 5*Resistivity*(Length of Wire DC^2)*(Current underground DC^2)/Line Losses
Line Losses using Resistance (DC Three-Wire US)
​ Go Line Losses = 2*(Power Transmitted^2)*Resistance underground DC/((Maximum Voltage^2))
Area of X-section using Volume of Conductor Material(DC Three-Wire US)
​ Go Area of underground dc wire = Volume Of Conductor/(2.5*Length of Wire DC)
Volume of Conductor Material using Area and Length(DC Three-Wire US)
​ Go Volume Of Conductor = 2.5*Area of underground dc wire*Length of Wire DC
Constant using Volume of Conductor Material(DC Three-Wire US)
​ Go Constant underground dc = Volume Of Conductor/(1.25)
Volume of Conductor Material using Constant(DC Three-Wire US)
​ Go Volume Of Conductor = 1.25*Constant underground dc

Line Losses using Volume of Conductor Material(DC Three-Wire US) Formula

Line Losses = 5*Resistivity*((Power Transmitted*Length of Wire DC)^2)/(Volume Of Conductor*(Maximum Voltage^2))
Pline = 5*ρ*((P*l)^2)/(V*(Vm^2))

What is a 3 wire dc system?

This is basically a combination of two series-connected unipolar DC systems. It consists of three conductors, two outer conductors (one is positive and the other is negative), and one middle conductor which acts as neutral.

How to Calculate Line Losses using Volume of Conductor Material(DC Three-Wire US)?

Line Losses using Volume of Conductor Material(DC Three-Wire US) calculator uses Line Losses = 5*Resistivity*((Power Transmitted*Length of Wire DC)^2)/(Volume Of Conductor*(Maximum Voltage^2)) to calculate the Line Losses, The Line Losses using Volume of Conductor Material(DC Three-Wire US) formula is defined as a loss of electric energy due to the heating of line wires by the current. Line Losses is denoted by Pline symbol.

How to calculate Line Losses using Volume of Conductor Material(DC Three-Wire US) using this online calculator? To use this online calculator for Line Losses using Volume of Conductor Material(DC Three-Wire US), enter Resistivity (ρ), Power Transmitted (P), Length of Wire DC (l), Volume Of Conductor (V) & Maximum Voltage (Vm) and hit the calculate button. Here is how the Line Losses using Volume of Conductor Material(DC Three-Wire US) calculation can be explained with given input values -> 0.000622 = 5*1.7E-05*((300*3.2)^2)/(35*(60^2)).

FAQ

What is Line Losses using Volume of Conductor Material(DC Three-Wire US)?
The Line Losses using Volume of Conductor Material(DC Three-Wire US) formula is defined as a loss of electric energy due to the heating of line wires by the current and is represented as Pline = 5*ρ*((P*l)^2)/(V*(Vm^2)) or Line Losses = 5*Resistivity*((Power Transmitted*Length of Wire DC)^2)/(Volume Of Conductor*(Maximum Voltage^2)). Resistivity is the measure of how strongly a material opposes the flow of current through them, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Length of Wire DC is the measurement or extent of something from end to end, Volume Of Conductor the 3-dimensional space enclosed by a conductor material & Maximum Voltage the highest voltage rating for electrical devices.
How to calculate Line Losses using Volume of Conductor Material(DC Three-Wire US)?
The Line Losses using Volume of Conductor Material(DC Three-Wire US) formula is defined as a loss of electric energy due to the heating of line wires by the current is calculated using Line Losses = 5*Resistivity*((Power Transmitted*Length of Wire DC)^2)/(Volume Of Conductor*(Maximum Voltage^2)). To calculate Line Losses using Volume of Conductor Material(DC Three-Wire US), you need Resistivity (ρ), Power Transmitted (P), Length of Wire DC (l), Volume Of Conductor (V) & Maximum Voltage (Vm). With our tool, you need to enter the respective value for Resistivity, Power Transmitted, Length of Wire DC, Volume Of Conductor & Maximum Voltage and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Line Losses?
In this formula, Line Losses uses Resistivity, Power Transmitted, Length of Wire DC, Volume Of Conductor & Maximum Voltage. We can use 3 other way(s) to calculate the same, which is/are as follows -
  • Line Losses = 2*(Power Transmitted^2)*Resistivity*Length of Wire DC/((Maximum Voltage^2)*Area of underground dc wire)
  • Line Losses = 2*(Current underground DC^2)*Resistivity*Length of Wire DC/(Area of underground dc wire)
  • Line Losses = 2*(Power Transmitted^2)*Resistance underground DC/((Maximum Voltage^2))
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