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## Credits

Vishwakarma Government Engineering College (VGEC), Ahmedabad
Urvi Rathod has created this Calculator and 1000+ more calculators!
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## Load Current Using Area Of X-section (1-phase 3-wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
current6 = sqrt(Line Losses*Area/(Resistivity*Length*2))
I6 = sqrt(W*A/(ρ*l*2))
This formula uses 1 Functions, 4 Variables
Functions Used
sqrt - Squre root function, sqrt(Number)
Variables Used
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Area - The area is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Area: 50 Square Meter --> 50 Square Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
I6 = sqrt(W*A/(ρ*l*2)) --> sqrt(0.6*50/(1.7E-05*3*2))
Evaluating ... ...
I6 = 542.32614454664
STEP 3: Convert Result to Output's Unit
542.32614454664 Ampere --> No Conversion Required
542.32614454664 Ampere <-- Current Of 1-Φ 3-wire system
(Calculation completed in 00.016 seconds)

## < 9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-section (1-phase 3-wire US)
transmitted_power = sqrt(Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*Resistivity*Length)) Go
Angle Using Area Of X-section (1-phase 3-wire US)
theta = acos((2*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system))) Go
Maximum Voltage Using Area Of X-section (1-phase 3-wire US)
maximum_voltage = (2*Power Transmitted/cos(Theta))*sqrt(Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system)) Go
RMS Voltage Using Area Of X-section (1-phase 3-wire US)
rms_voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system)) Go
Power Factor Using Area Of X-section (1-phase 3-wire US)
power_factor = ((2*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system))) Go
Resistivity Using Area Of X-section (1-phase 3-wire US)
resistivity = Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*(Power Transmitted^2)*Length) Go
Length Using Area Of X-section (1-phase 3-wire US)
length = Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*(Power Transmitted^2)*Resistivity) Go
Line Losses Using Area Of X-section (1-phase 3-wire US)
line_losses = 2*Resistivity*Length*(Power Transmitted^2)/(Area Of 1-Φ 3-wire system*(Maximum Voltage^2*cos(Theta)^2)) Go
Load Current Using Area Of X-section (1-phase 3-wire US)
current6 = sqrt(Line Losses*Area/(Resistivity*Length*2)) Go

### Load Current Using Area Of X-section (1-phase 3-wire US) Formula

current6 = sqrt(Line Losses*Area/(Resistivity*Length*2))
I6 = sqrt(W*A/(ρ*l*2))

## Define Transmitted Power.

Transmitted Power is the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations.

## How to Calculate Load Current Using Area Of X-section (1-phase 3-wire US)?

Load Current Using Area Of X-section (1-phase 3-wire US) calculator uses current6 = sqrt(Line Losses*Area/(Resistivity*Length*2)) to calculate the Current Of 1-Φ 3-wire system, The Load Current Using Area Of X-section (1-phase 3-wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system. Current Of 1-Φ 3-wire system and is denoted by I6 symbol.

How to calculate Load Current Using Area Of X-section (1-phase 3-wire US) using this online calculator? To use this online calculator for Load Current Using Area Of X-section (1-phase 3-wire US), enter Line Losses (W), Area (A), Resistivity (ρ) and Length (l) and hit the calculate button. Here is how the Load Current Using Area Of X-section (1-phase 3-wire US) calculation can be explained with given input values -> 542.3261 = sqrt(0.6*50/(1.7E-05*3*2)).

### FAQ

What is Load Current Using Area Of X-section (1-phase 3-wire US)?
The Load Current Using Area Of X-section (1-phase 3-wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system and is represented as I6 = sqrt(W*A/(ρ*l*2)) or current6 = sqrt(Line Losses*Area/(Resistivity*Length*2)). Line Losses is defined as the losses that are produced in the line, The area is the amount of two-dimensional space taken up by an object, Resistivity is the measure of how strongly a material opposes the flow of current through them and Length is the measurement or extent of something from end to end.
How to calculate Load Current Using Area Of X-section (1-phase 3-wire US)?
The Load Current Using Area Of X-section (1-phase 3-wire US) formula is defined as the current that flows into the load of the single-phase two-wire underground system is calculated using current6 = sqrt(Line Losses*Area/(Resistivity*Length*2)). To calculate Load Current Using Area Of X-section (1-phase 3-wire US), you need Line Losses (W), Area (A), Resistivity (ρ) and Length (l). With our tool, you need to enter the respective value for Line Losses, Area, Resistivity and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Current Of 1-Φ 3-wire system?
In this formula, Current Of 1-Φ 3-wire system uses Line Losses, Area, Resistivity and Length. We can use 9 other way(s) to calculate the same, which is/are as follows -
• transmitted_power = sqrt(Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*Resistivity*Length))
• resistivity = Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*(Power Transmitted^2)*Length)
• length = Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*(Power Transmitted^2)*Resistivity)
• maximum_voltage = (2*Power Transmitted/cos(Theta))*sqrt(Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system))
• rms_voltage = (Power Transmitted/cos(Theta))*sqrt(2*Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system))
• power_factor = ((2*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system)))
• theta = acos((2*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/(Line Losses*Area Of 1-Φ 3-wire system)))
• current6 = sqrt(Line Losses*Area/(Resistivity*Length*2))
• line_losses = 2*Resistivity*Length*(Power Transmitted^2)/(Area Of 1-Φ 3-wire system*(Maximum Voltage^2*cos(Theta)^2))
Where is the Load Current Using Area Of X-section (1-phase 3-wire US) calculator used?
Among many, Load Current Using Area Of X-section (1-phase 3-wire US) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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