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Load Current Using Area Of X-Section (2-phase 4-wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
current7 = sqrt(Line Losses*Area Of 2-Φ 4-wire system/(2*Resistivity*Length))
C7 = sqrt(W*a7/(2*ρ*l))
This formula uses 1 Functions, 4 Variables
Functions Used
sqrt - Squre root function, sqrt(Number)
Variables Used
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Area Of 2-Φ 4-wire system - The Area Of 2-Φ 4-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
STEP 1: Convert Input(s) to Base Unit
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Area Of 2-Φ 4-wire system: 7 Square Meter --> 7 Square Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length: 3 Meter --> 3 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
C7 = sqrt(W*a7/(2*ρ*l)) --> sqrt(0.6*7/(2*1.7E-05*3))
Evaluating ... ...
C7 = 202.919862478357
STEP 3: Convert Result to Output's Unit
202.919862478357 Ampere --> No Conversion Required
FINAL ANSWER
202.919862478357 Ampere <-- Current Of 2-Φ 4-wire system
(Calculation completed in 00.017 seconds)

9 Area Of X-Section Calculators

Maximum Voltage Using Area Of X-Section (2-phase 4-wire US)
maximum_voltage = (2*Power Transmitted/cos(Theta))*sqrt(Resistivity*Length/(Line Losses*Area Of 2-Φ 4-wire system)) Go
Angle Using Area Of X-Section (2-phase 4-wire US)
theta = acos((2)*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/Line Losses*Area Of 2-Φ 4-wire system) Go
Power Transmitted Using Area Of X-Section (2-phase 4-wire US)
transmitted_power = Maximum Voltage*cos(Theta)*sqrt(Area Of 2-Φ 4-wire system*Line Losses/(4*Resistivity*Length)) Go
RMS Voltage Using Area Of X-Section (2-phase 4-wire US)
rms_voltage = (Power Transmitted/cos(Theta))*sqrt(Resistivity*Length/(Line Losses*Area Of 2-Φ 4-wire system)) Go
Line Losses Using Area Of X-Section (2-phase 4-wire US)
line_losses = 4*Resistivity*Length*(Power Transmitted^2)/(Area Of 2-Φ 4-wire system*(Maximum Voltage^2)*(cos(Theta)^2)) Go
Resistivity Using Area Of X-Section (2-phase 4-wire US)
resistivity = Area Of 2-Φ 4-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*Length*(Power Transmitted^2)) Go
Length Using Area Of X-Section (2-phase 4-wire US)
length = Area Of 2-Φ 4-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*Resistivity*(Power Transmitted^2)) Go
Power Factor Using Area Of X-Section (2-phase 4-wire US)
power_factor = ((2)*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/Line Losses*Area Of 2-Φ 4-wire system) Go
Load Current Using Area Of X-Section (2-phase 4-wire US)
current7 = sqrt(Line Losses*Area Of 2-Φ 4-wire system/(2*Resistivity*Length)) Go

Load Current Using Area Of X-Section (2-phase 4-wire US) Formula

current7 = sqrt(Line Losses*Area Of 2-Φ 4-wire system/(2*Resistivity*Length))
C7 = sqrt(W*a7/(2*ρ*l))

What is a load in a circuit?

An electrical load is an electrical component or portion of a circuit that consumes (active) electric power, such as electrical appliances and lights inside the home. The term may also refer to the power consumed by a circuit. This is opposed to a power source, such as a battery or generator, which produces power.

How to Calculate Load Current Using Area Of X-Section (2-phase 4-wire US)?

Load Current Using Area Of X-Section (2-phase 4-wire US) calculator uses current7 = sqrt(Line Losses*Area Of 2-Φ 4-wire system/(2*Resistivity*Length)) to calculate the Current Of 2-Φ 4-wire system, The Load Current Using Area Of X-Section (2-phase 4-wire US) formula is defined as the current that flows into the load of the two-phase three-wire underground system. Current Of 2-Φ 4-wire system and is denoted by C7 symbol.

How to calculate Load Current Using Area Of X-Section (2-phase 4-wire US) using this online calculator? To use this online calculator for Load Current Using Area Of X-Section (2-phase 4-wire US), enter Line Losses (W), Area Of 2-Φ 4-wire system (a7), Resistivity (ρ) and Length (l) and hit the calculate button. Here is how the Load Current Using Area Of X-Section (2-phase 4-wire US) calculation can be explained with given input values -> 202.9199 = sqrt(0.6*7/(2*1.7E-05*3)).

FAQ

What is Load Current Using Area Of X-Section (2-phase 4-wire US)?
The Load Current Using Area Of X-Section (2-phase 4-wire US) formula is defined as the current that flows into the load of the two-phase three-wire underground system and is represented as C7 = sqrt(W*a7/(2*ρ*l)) or current7 = sqrt(Line Losses*Area Of 2-Φ 4-wire system/(2*Resistivity*Length)). Line Losses is defined as the losses that are produced in the line, The Area Of 2-Φ 4-wire system is the amount of two-dimensional space taken up by an object, Resistivity is the measure of how strongly a material opposes the flow of current through them and Length is the measurement or extent of something from end to end.
How to calculate Load Current Using Area Of X-Section (2-phase 4-wire US)?
The Load Current Using Area Of X-Section (2-phase 4-wire US) formula is defined as the current that flows into the load of the two-phase three-wire underground system is calculated using current7 = sqrt(Line Losses*Area Of 2-Φ 4-wire system/(2*Resistivity*Length)). To calculate Load Current Using Area Of X-Section (2-phase 4-wire US), you need Line Losses (W), Area Of 2-Φ 4-wire system (a7), Resistivity (ρ) and Length (l). With our tool, you need to enter the respective value for Line Losses, Area Of 2-Φ 4-wire system, Resistivity and Length and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Current Of 2-Φ 4-wire system?
In this formula, Current Of 2-Φ 4-wire system uses Line Losses, Area Of 2-Φ 4-wire system, Resistivity and Length. We can use 9 other way(s) to calculate the same, which is/are as follows -
  • theta = acos((2)*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/Line Losses*Area Of 2-Φ 4-wire system)
  • power_factor = ((2)*Power Transmitted/Maximum Voltage)*sqrt(Resistivity*Length/Line Losses*Area Of 2-Φ 4-wire system)
  • maximum_voltage = (2*Power Transmitted/cos(Theta))*sqrt(Resistivity*Length/(Line Losses*Area Of 2-Φ 4-wire system))
  • line_losses = 4*Resistivity*Length*(Power Transmitted^2)/(Area Of 2-Φ 4-wire system*(Maximum Voltage^2)*(cos(Theta)^2))
  • transmitted_power = Maximum Voltage*cos(Theta)*sqrt(Area Of 2-Φ 4-wire system*Line Losses/(4*Resistivity*Length))
  • resistivity = Area Of 2-Φ 4-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*Length*(Power Transmitted^2))
  • length = Area Of 2-Φ 4-wire system*Line Losses*(Maximum Voltage^2)*(cos(Theta)^2)/(4*Resistivity*(Power Transmitted^2))
  • rms_voltage = (Power Transmitted/cos(Theta))*sqrt(Resistivity*Length/(Line Losses*Area Of 2-Φ 4-wire system))
  • current7 = sqrt(Line Losses*Area Of 2-Φ 4-wire system/(2*Resistivity*Length))
Where is the Load Current Using Area Of X-Section (2-phase 4-wire US) calculator used?
Among many, Load Current Using Area Of X-Section (2-phase 4-wire US) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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