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## Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) Solution

STEP 0: Pre-Calculation Summary
Formula Used
maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
Vm = sqrt((l*ρ*(P^2))/(a6*W*((cos(ϑ))^2)))
This formula uses 2 Functions, 6 Variables
Functions Used
cos - Trigonometric cosine function, cos(Angle)
sqrt - Squre root function, sqrt(Number)
Variables Used
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
Resistivity - Resistivity is the measure of how strongly a material opposes the flow of current through them. (Measured in Ohm Meter)
Power Transmitted - The Power Transmitted Value through a shaft. (Measured in Kilowatt)
Area Of 1-Φ 3-wire system - The Area Of 1-Φ 3-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Theta - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint. (Measured in Degree)
STEP 1: Convert Input(s) to Base Unit
Length: 3 Meter --> 3 Meter No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 10 Kilowatt --> 10000 Watt (Check conversion here)
Area Of 1-Φ 3-wire system: 6 Square Meter --> 6 Square Meter No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vm = sqrt((l*ρ*(P^2))/(a6*W*((cos(ϑ))^2))) --> sqrt((3*1.7E-05*(10000^2))/(6*0.6*((cos(0.5235987755982))^2)))
Evaluating ... ...
Vm = 43.4613493680177
STEP 3: Convert Result to Output's Unit
43.4613493680177 Volt --> No Conversion Required
FINAL ANSWER
43.4613493680177 Volt <-- Maximum Voltage
(Calculation completed in 00.016 seconds)

## < 8 Area Of X-Section Calculators

Power Transmitted Using Area Of X-section(1-phase 3-wire OS)
power_transmitted = sqrt((Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length)) Go
Maximum Voltage Using Area Of X-section(1-phase 3-wire OS)
maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2))) Go
RMS Voltage Using Area Of X-Section(1-Phase 3-Wire OS)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-section(1-phase 3-wire OS)
power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2))) Go
Line Losses Using Area Of X-section(1-phase 3-wire OS)
line_losses = (Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Of Wire Using Area Of X-section(1-phase 3-wire OS)
length = Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2)) Go
Resistivity Using Area Of X-section(1-phase 3-wire OS)
resistivity = Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2)) Go
Load Current Using Area Of X-section(1-Phase 3-Wire OS)
current6 = sqrt(Area Of 1-Φ 3-wire system*Line Losses/(2*Resistivity*Length)) Go

### Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) Formula

maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
Vm = sqrt((l*ρ*(P^2))/(a6*W*((cos(ϑ))^2)))

## What is the value of maximum voltage and volume of conductor material in 1-phase 3-wire system?

The volume of conductor material required in this system is 5/8cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is 2vm so that r.m.s. value of voltage between them is √2vm.

## How to Calculate Maximum Voltage Using Area Of X-section(1-phase 3-wire OS)?

Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) calculator uses maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2))) to calculate the Maximum Voltage, The Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage and is denoted by Vm symbol.

How to calculate Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) using this online calculator? To use this online calculator for Maximum Voltage Using Area Of X-section(1-phase 3-wire OS), enter Length (l), Resistivity (ρ), Power Transmitted (P), Area Of 1-Φ 3-wire system (a6), Line Losses (W) and Theta (ϑ) and hit the calculate button. Here is how the Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) calculation can be explained with given input values -> 43.46135 = sqrt((3*1.7E-05*(10000^2))/(6*0.6*((cos(0.5235987755982))^2))).

### FAQ

What is Maximum Voltage Using Area Of X-section(1-phase 3-wire OS)?
The Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition and is represented as Vm = sqrt((l*ρ*(P^2))/(a6*W*((cos(ϑ))^2))) or maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2))). Length is the measurement or extent of something from end to end, Resistivity is the measure of how strongly a material opposes the flow of current through them, The Power Transmitted Value through a shaft, The Area Of 1-Φ 3-wire system is the amount of two-dimensional space taken up by an object, Line Losses is defined as the losses that are produced in the line and Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
How to calculate Maximum Voltage Using Area Of X-section(1-phase 3-wire OS)?
The Maximum Voltage Using Area Of X-section(1-phase 3-wire OS) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition is calculated using maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2))). To calculate Maximum Voltage Using Area Of X-section(1-phase 3-wire OS), you need Length (l), Resistivity (ρ), Power Transmitted (P), Area Of 1-Φ 3-wire system (a6), Line Losses (W) and Theta (ϑ). With our tool, you need to enter the respective value for Length, Resistivity, Power Transmitted, Area Of 1-Φ 3-wire system, Line Losses and Theta and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Maximum Voltage?
In this formula, Maximum Voltage uses Length, Resistivity, Power Transmitted, Area Of 1-Φ 3-wire system, Line Losses and Theta. We can use 8 other way(s) to calculate the same, which is/are as follows -
• length = Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Resistivity*(Power Transmitted^2))
• resistivity = Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/(Length*(Power Transmitted^2))
• power_transmitted = sqrt((Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(Resistivity*Length))
• line_losses = (Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*(Maximum Voltage^2)*((cos(Theta))^2))
• maximum_voltage = sqrt((Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
• power_factor = sqrt((Power Transmitted^2)*Resistivity*Length/(Area Of 1-Φ 3-wire system*Line Losses*(Maximum Voltage^2)))
• rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
• current6 = sqrt(Area Of 1-Φ 3-wire system*Line Losses/(2*Resistivity*Length))
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