Maximum Voltage using Constant (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Maximum Voltage Underground AC = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*Line Losses))
Vm = sqrt(4*ρ*(P*L)^2/(K*Ploss))
This formula uses 1 Functions, 6 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Constant Underground AC - Constant Underground AC is defined as the constant of line of a Overhead supply system.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
STEP 1: Convert Input(s) to Base Unit
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Constant Underground AC: 0.87 --> No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Vm = sqrt(4*ρ*(P*L)^2/(K*Ploss)) --> sqrt(4*1.7E-05*(300*24)^2/(0.87*2.67))
Evaluating ... ...
Vm = 38.9557612772643
STEP 3: Convert Result to Output's Unit
38.9557612772643 Volt --> No Conversion Required
FINAL ANSWER
38.9557612772643 38.95576 Volt <-- Maximum Voltage Underground AC
(Calculation completed in 00.004 seconds)

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17 Current & Voltage Calculators

Maximum Voltage using Area of X-Section (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = sqrt((4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*Line Losses*(cos(Phase Difference))^2))
RMS Voltage using Area of X-Section (1-Phase 2-Wire US)
Go Root Mean Square Voltage = sqrt((2*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*Line Losses*((cos(Phase Difference))^2)))
Maximum Voltage using Volume of Conductor Material (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = sqrt(8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
Maximum Voltage using Line Losses (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference)
RMS Voltage using Line Losses (1-Phase 2-Wire US)
Go Root Mean Square Voltage = 2*Power Transmitted*sqrt(2*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference)
RMS Voltage using Volume of Conductor Material (1-Phase 2-Wire US)
Go Root Mean Square Voltage = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(cos(Phase Difference))^2*Volume Of Conductor))
Load Current using Constant (1-Phase 2-Wire US)
Go Current Underground AC = sqrt(Constant Underground AC*Line Losses/(2*Resistivity*(Length of Underground AC Wire*cos(Phase Difference))^2))
Maximum Voltage using Constant (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*Line Losses))
RMS Voltage using Constant (1-Phase 2-Wire US)
Go Root Mean Square Voltage = 2*Power Transmitted*Length of Underground AC Wire*sqrt(2*Resistivity/(Line Losses*Constant Underground AC))
RMS Voltage using Resistance (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(2*Resistance Underground AC/Line Losses)/cos(Phase Difference)
Maximum Voltage using Resistance (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistance Underground AC/Line Losses)/cos(Phase Difference)
Load Current using Line Losses (1-Phase 2-Wire US)
Go Current Underground AC = sqrt(Line Losses*Area of Underground AC Wire/(2*Resistivity*Length of Underground AC Wire))
Maximum Voltage using Load Current (1-Phase 2-Wire US)
Go Maximum Voltage Underground AC = (sqrt(2))*Power Transmitted/(Current Underground AC*(cos(Phase Difference)))
Load Current (1-Phase 2-Wire US)
Go Current Underground AC = Power Transmitted*sqrt(2)/(Maximum Voltage Underground AC*cos(Phase Difference))
RMS Voltage using Load Current (1-Phase 2-Wire US)
Go Root Mean Square Voltage = Power Transmitted/(Current Underground AC*cos(Phase Difference))
Load Current using Resistance (1-Phase 2-Wire US)
Go Current Underground AC = sqrt(Line Losses/(2*Resistance Underground AC))
RMS Voltage(1-Phase 2-Wire US)
Go Root Mean Square Voltage = Maximum Voltage Underground AC/sqrt(2)

Maximum Voltage using Constant (1-Phase 2-Wire US) Formula

Maximum Voltage Underground AC = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*Line Losses))
Vm = sqrt(4*ρ*(P*L)^2/(K*Ploss))

What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Maximum Voltage using Constant (1-Phase 2-Wire US)?

Maximum Voltage using Constant (1-Phase 2-Wire US) calculator uses Maximum Voltage Underground AC = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*Line Losses)) to calculate the Maximum Voltage Underground AC, The Maximum Voltage using Constant (1-Phase 2-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition. Maximum Voltage Underground AC is denoted by Vm symbol.

How to calculate Maximum Voltage using Constant (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Maximum Voltage using Constant (1-Phase 2-Wire US), enter Resistivity (ρ), Power Transmitted (P), Length of Underground AC Wire (L), Constant Underground AC (K) & Line Losses (Ploss) and hit the calculate button. Here is how the Maximum Voltage using Constant (1-Phase 2-Wire US) calculation can be explained with given input values -> 38.95576 = sqrt(4*1.7E-05*(300*24)^2/(0.87*2.67)).

FAQ

What is Maximum Voltage using Constant (1-Phase 2-Wire US)?
The Maximum Voltage using Constant (1-Phase 2-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition and is represented as Vm = sqrt(4*ρ*(P*L)^2/(K*Ploss)) or Maximum Voltage Underground AC = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*Line Losses)). Resistivity is the measure of how strongly a material opposes the flow of current through them, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Length of Underground AC Wire is the total length of the wire from one end to other end, Constant Underground AC is defined as the constant of line of a Overhead supply system & Line Losses is defined as the total losses occurring in an Underground AC line when in use.
How to calculate Maximum Voltage using Constant (1-Phase 2-Wire US)?
The Maximum Voltage using Constant (1-Phase 2-Wire US) formula is defined as the highest voltage rating for electrical devices and equipment that can be used with the voltage definition is calculated using Maximum Voltage Underground AC = sqrt(4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Constant Underground AC*Line Losses)). To calculate Maximum Voltage using Constant (1-Phase 2-Wire US), you need Resistivity (ρ), Power Transmitted (P), Length of Underground AC Wire (L), Constant Underground AC (K) & Line Losses (Ploss). With our tool, you need to enter the respective value for Resistivity, Power Transmitted, Length of Underground AC Wire, Constant Underground AC & Line Losses and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Maximum Voltage Underground AC?
In this formula, Maximum Voltage Underground AC uses Resistivity, Power Transmitted, Length of Underground AC Wire, Constant Underground AC & Line Losses. We can use 6 other way(s) to calculate the same, which is/are as follows -
  • Maximum Voltage Underground AC = sqrt((4*Length of Underground AC Wire*Resistivity*(Power Transmitted^2))/(Area of Underground AC Wire*Line Losses*(cos(Phase Difference))^2))
  • Maximum Voltage Underground AC = sqrt(8*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*Volume Of Conductor*(cos(Phase Difference))^2))
  • Maximum Voltage Underground AC = (sqrt(2))*Power Transmitted/(Current Underground AC*(cos(Phase Difference)))
  • Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses))/cos(Phase Difference)
  • Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(Resistance Underground AC/Line Losses)/cos(Phase Difference)
  • Maximum Voltage Underground AC = 2*Power Transmitted*sqrt(2*Resistance Underground AC/Line Losses)/cos(Phase Difference)
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