Mean radius of earth given attractive force potentials per unit mass for Sun Solution

STEP 0: Pre-Calculation Summary
Formula Used
Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun))
RM = sqrt((Vs*rs^3)/(f*Msun*Ps))
This formula uses 1 Functions, 6 Variables
Functions Used
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Mean Radius of the Earth - (Measured in Meter) - Mean Radius of the Earth [6,371 km] in terms of Attractive Force Potentials per unit Mass for the Moon.
Attractive Force Potentials for Sun - Attractive Force Potentials for Sun is the gravitational force exerted by the Sun on an object and can be described by the gravitational potential.
Distance - (Measured in Meter) - Distance from center of Earth to center of Sun. if the average radius of the Earth's orbit is 93 million miles (150 million km) then the radius of the Sun's counter orbit is about 280 miles (450 km).
Universal Constant - Universal Constant in terms of Radius of the Earth and Acceleration of Gravity.
Mass of the Sun - (Measured in Kilogram) - Mass of the Sun [1.989 × 10^30 kg] about 333,000 times the mass of the Earth.
Harmonic Polynomial Expansion Terms for Sun - Harmonic Polynomial Expansion Terms for Sun that collectively describe the relative positions of the earth, moon, and sun.
STEP 1: Convert Input(s) to Base Unit
Attractive Force Potentials for Sun: 1.6E+25 --> No Conversion Required
Distance: 150000000 Kilometer --> 150000000000 Meter (Check conversion here)
Universal Constant: 2 --> No Conversion Required
Mass of the Sun: 1.989E+30 Kilogram --> 1.989E+30 Kilogram No Conversion Required
Harmonic Polynomial Expansion Terms for Sun: 300000000000000 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
RM = sqrt((Vs*rs^3)/(f*Msun*Ps)) --> sqrt((1.6E+25*150000000000^3)/(2*1.989E+30*300000000000000))
Evaluating ... ...
RM = 6726727.93996312
STEP 3: Convert Result to Output's Unit
6726727.93996312 Meter -->6726.72793996312 Kilometer (Check conversion here)
FINAL ANSWER
6726.72793996312 6726.728 Kilometer <-- Mean Radius of the Earth
(Calculation completed in 00.011 seconds)

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Coorg Institute of Technology (CIT), Coorg
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13 Attractive Force Potentials Calculators

Moon's Tide-generating attractive Force Potential
Go Attractive Force Potentials for Moon = Universal Constant*Mass of the Moon*((1/Distance of point)-(1/Distance from center of Earth to center of Moon)-([Earth-R]*cos(Angle made by the distance of point)/Distance from center of Earth to center of Moon^2))
Tide-generating attractive Force Potential for Sun
Go Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)*((1/Distance of point)-(1/Distance)-(Mean Radius of the Earth*cos(Angle made by the distance of point)/Distance^2))
Mean radius of earth given attractive force potentials per unit mass for moon
Go Mean Radius of the Earth = sqrt((Attractive Force Potentials for Moon*Distance from center of Earth to center of Moon^3)/(Universal Constant*Mass of the Moon*Harmonic Polynomial Expansion Terms for Moon))
Attractive Force Potentials per unit Mass for Moon given Harmonic Polynomial Expansion
Go Attractive Force Potentials for Moon = (Universal Constant*Mass of the Moon)*(Mean Radius of the Earth^2/Distance from center of Earth to center of Moon^3)*Harmonic Polynomial Expansion Terms for Moon
Distance from center of earth to center of moon given attractive force potentials
Go Distance from center of Earth to center of Moon = (Mean Radius of the Earth^2*Universal Constant*[Moon-M]*Harmonic Polynomial Expansion Terms for Moon/Attractive Force Potentials for Moon)^(1/3)
Mean radius of earth given attractive force potentials per unit mass for Sun
Go Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun))
Attractive Force Potentials per unit Mass for Sun given Harmonic Polynomial Expansion
Go Attractive Force Potentials for Sun = Universal Constant*Mass of the Sun*(Mean Radius of the Earth^2/Distance^3)*Harmonic Polynomial Expansion Terms for Sun
Mass of Moon given attractive force potentials with harmonic polynomial expansion
Go Mass of the Moon = (Attractive Force Potentials for Moon*Distance from center of Earth to center of Moon^3)/([Earth-R]^2*Universal Constant*Harmonic Polynomial Expansion Terms for Moon)
Mass of Sun given attractive force potentials with harmonic polynomial expansion
Go Mass of the Sun = (Attractive Force Potentials for Sun*Distance^3)/([Earth-R]^2*Universal Constant*Harmonic Polynomial Expansion Terms for Sun)
Attractive Force Potentials per unit Mass for Moon
Go Attractive Force Potentials for Moon = (Universal Constant*Mass of the Moon)/Distance of point
Mass of Moon for Given Attractive Force Potentials
Go Mass of the Moon = (Attractive Force Potentials for Moon*Distance of point)/Universal Constant
Attractive Force Potentials per unit Mass for Sun
Go Attractive Force Potentials for Sun = (Universal Constant*Mass of the Sun)/Distance of point
Mass of Sun for Given Attractive Force Potentials
Go Mass of the Sun = (Attractive Force Potentials for Sun*Distance of point)/Universal Constant

Mean radius of earth given attractive force potentials per unit mass for Sun Formula

Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun))
RM = sqrt((Vs*rs^3)/(f*Msun*Ps))

What do you mean by Tidal Force?

The Tidal Force is a gravitational effect that stretches a body along the line towards the center of mass of another body due to a gradient (difference in strength) in gravitational field from the other body; it is responsible for diverse phenomena, including tides, tidal locking, breaking apart of celestial bodies.

How to Calculate Mean radius of earth given attractive force potentials per unit mass for Sun?

Mean radius of earth given attractive force potentials per unit mass for Sun calculator uses Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun)) to calculate the Mean Radius of the Earth, The Mean radius of earth given attractive force potentials per unit mass for Sun formula is defined as a parameter influencing the attractive force potentials per unit mass for the moon and sun. Mean Radius of the Earth is denoted by RM symbol.

How to calculate Mean radius of earth given attractive force potentials per unit mass for Sun using this online calculator? To use this online calculator for Mean radius of earth given attractive force potentials per unit mass for Sun, enter Attractive Force Potentials for Sun (Vs), Distance (rs), Universal Constant (f), Mass of the Sun (Msun) & Harmonic Polynomial Expansion Terms for Sun (Ps) and hit the calculate button. Here is how the Mean radius of earth given attractive force potentials per unit mass for Sun calculation can be explained with given input values -> 6.726728 = sqrt((1.6E+25*150000000000^3)/(2*1.989E+30*300000000000000)).

FAQ

What is Mean radius of earth given attractive force potentials per unit mass for Sun?
The Mean radius of earth given attractive force potentials per unit mass for Sun formula is defined as a parameter influencing the attractive force potentials per unit mass for the moon and sun and is represented as RM = sqrt((Vs*rs^3)/(f*Msun*Ps)) or Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun)). Attractive Force Potentials for Sun is the gravitational force exerted by the Sun on an object and can be described by the gravitational potential, Distance from center of Earth to center of Sun. if the average radius of the Earth's orbit is 93 million miles (150 million km) then the radius of the Sun's counter orbit is about 280 miles (450 km), Universal Constant in terms of Radius of the Earth and Acceleration of Gravity, Mass of the Sun [1.989 × 10^30 kg] about 333,000 times the mass of the Earth & Harmonic Polynomial Expansion Terms for Sun that collectively describe the relative positions of the earth, moon, and sun.
How to calculate Mean radius of earth given attractive force potentials per unit mass for Sun?
The Mean radius of earth given attractive force potentials per unit mass for Sun formula is defined as a parameter influencing the attractive force potentials per unit mass for the moon and sun is calculated using Mean Radius of the Earth = sqrt((Attractive Force Potentials for Sun*Distance^3)/(Universal Constant*Mass of the Sun*Harmonic Polynomial Expansion Terms for Sun)). To calculate Mean radius of earth given attractive force potentials per unit mass for Sun, you need Attractive Force Potentials for Sun (Vs), Distance (rs), Universal Constant (f), Mass of the Sun (Msun) & Harmonic Polynomial Expansion Terms for Sun (Ps). With our tool, you need to enter the respective value for Attractive Force Potentials for Sun, Distance, Universal Constant, Mass of the Sun & Harmonic Polynomial Expansion Terms for Sun and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Mean Radius of the Earth?
In this formula, Mean Radius of the Earth uses Attractive Force Potentials for Sun, Distance, Universal Constant, Mass of the Sun & Harmonic Polynomial Expansion Terms for Sun. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Mean Radius of the Earth = sqrt((Attractive Force Potentials for Moon*Distance from center of Earth to center of Moon^3)/(Universal Constant*Mass of the Moon*Harmonic Polynomial Expansion Terms for Moon))
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