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Osmania University (OU), Hyderabad
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## Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given Solution

STEP 0: Pre-Calculation Summary
Formula Used
minor_axis = 64*Moment of Inertia/(pi*Major axis^3)
b = 64*I/(pi*a^3)
This formula uses 1 Constants, 2 Variables
Constants Used
pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288
Variables Used
Moment of Inertia - Moment of Inertia is the measure of the resistance of a body to angular acceleration about a given axis. (Measured in Kilogram Meter²)
Major axis - Major axis is the line segment that crosses both the focal points of the ellipse. (Measured in Centimeter)
STEP 1: Convert Input(s) to Base Unit
Moment of Inertia: 1.125 Kilogram Meter² --> 1.125 Kilogram Meter² No Conversion Required
Major axis: 10 Centimeter --> 0.1 Meter (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
b = 64*I/(pi*a^3) --> 64*1.125/(pi*0.1^3)
Evaluating ... ...
b = 22918.3118052329
STEP 3: Convert Result to Output's Unit
22918.3118052329 Meter -->2291831.18052329 Centimeter (Check conversion here)
FINAL ANSWER
2291831.18052329 Centimeter <-- Minor axis
(Calculation completed in 00.016 seconds)

## < 10+ Arms of Cast Iron Pulley Calculators

Radius of Rim When Torque Transmitted by the Pulley is Given
radius_of_rim = Torque Transmitted by the Pulley/(Tangential Force at the end of Each Arm*(Number of arms/2)) Go
Number of Arms of the Pulley When Torque Transmitted by the Pulley is Given
number_of_arms = 2*Torque Transmitted by the Pulley/(Tangential Force at the end of Each Arm*Radius of Rim) Go
Torque Transmitted by the Pulley
torque_transmitted_by_the_pulley = Tangential Force at the end of Each Arm*Radius of Rim*(Number of arms/2) Go
Tangential Force at the End of Each Arm When Torque Transmitted by the Pulley is Given
tangential_force_at_end_of_each_arm = Torque Transmitted by the Pulley/(Radius of Rim*(Number of arms/2)) Go
Radius of Rim When Bending Moment Acting on the Arm is Given
radius_of_rim = Bending moment/Tangential Force at the end of Each Arm Go
Bending Moment Acting on the arm
bending_moment = Tangential Force at the end of Each Arm*Radius of Rim Go
Tangential Force at the End of Each Arm When Bending Moment acting on the Arm is Given
tangential_force_at_end_of_each_arm = Bending moment/Radius of Rim Go
Torque Transmitted by the Pulley When Bending Moment acting on the Arm is Given
torque_transmitted_by_the_pulley = Bending moment*Number of arms/2 Go
Bending Moment acting on the Arm in terms of Torque Transmitted by the Pulley
bending_moment = 2*Torque Transmitted by the Pulley/Number of arms Go
Number of Arms When Bending Moment acting on the Arm is Given
number_of_arms = 2*Torque Transmitted by the Pulley/Bending moment Go

### Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given Formula

minor_axis = 64*Moment of Inertia/(pi*Major axis^3)
b = 64*I/(pi*a^3)

## Define Moment of Inertia?

The moment of inertia, otherwise known as the mass moment of inertia, angular mass, second moment of mass, or most accurately, rotational inertia, of a rigid body is a quantity that determines the torque needed for a desired angular acceleration about a rotational axis, akin to how mass determines the force needed for a desired acceleration.

## How to Calculate Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given?

Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given calculator uses minor_axis = 64*Moment of Inertia/(pi*Major axis^3) to calculate the Minor axis, The Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given formula is defined as the shortest axis of the elliptical cross-section of the arm which is perpendicular to the major axis. Minor axis and is denoted by b symbol.

How to calculate Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given using this online calculator? To use this online calculator for Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given, enter Moment of Inertia (I) and Major axis (a) and hit the calculate button. Here is how the Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given calculation can be explained with given input values -> 2.292E+6 = 64*1.125/(pi*0.1^3).

### FAQ

What is Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given?
The Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given formula is defined as the shortest axis of the elliptical cross-section of the arm which is perpendicular to the major axis and is represented as b = 64*I/(pi*a^3) or minor_axis = 64*Moment of Inertia/(pi*Major axis^3). Moment of Inertia is the measure of the resistance of a body to angular acceleration about a given axis and Major axis is the line segment that crosses both the focal points of the ellipse.
How to calculate Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given?
The Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given formula is defined as the shortest axis of the elliptical cross-section of the arm which is perpendicular to the major axis is calculated using minor_axis = 64*Moment of Inertia/(pi*Major axis^3). To calculate Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given, you need Moment of Inertia (I) and Major axis (a). With our tool, you need to enter the respective value for Moment of Inertia and Major axis and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Minor axis?
In this formula, Minor axis uses Moment of Inertia and Major axis. We can use 10 other way(s) to calculate the same, which is/are as follows -
• torque_transmitted_by_the_pulley = Tangential Force at the end of Each Arm*Radius of Rim*(Number of arms/2)
• tangential_force_at_end_of_each_arm = Torque Transmitted by the Pulley/(Radius of Rim*(Number of arms/2))
• radius_of_rim = Torque Transmitted by the Pulley/(Tangential Force at the end of Each Arm*(Number of arms/2))
• number_of_arms = 2*Torque Transmitted by the Pulley/(Tangential Force at the end of Each Arm*Radius of Rim)
• bending_moment = Tangential Force at the end of Each Arm*Radius of Rim
• tangential_force_at_end_of_each_arm = Bending moment/Radius of Rim
• radius_of_rim = Bending moment/Tangential Force at the end of Each Arm
• bending_moment = 2*Torque Transmitted by the Pulley/Number of arms
• number_of_arms = 2*Torque Transmitted by the Pulley/Bending moment
• torque_transmitted_by_the_pulley = Bending moment*Number of arms/2
Where is the Minor Axis of the Elliptical Cross-Section of Arm When Moment of Inertia of the Arm is Given calculator used?
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