Molar Vapor Volume given rate of pressure change Calculator

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Relative Lowering of Vapour Pressure

Clausius-Clapeyron Equation

Depression in Freezing Point

Elevation in Boiling Point

Gibb's Phase Rule

Immiscible Liquids

Important Formulas of Clausius-Clapeyron Equation

Important Formulas of Colligative Properties

Osmotic Pressure

Van't Hoff Factor

✖Molal Liquid Volume is the volume of liquid substance.ⓘ Molal Liquid Volume [v]			+10% -10%
✖Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid.ⓘ Molal Heat of Vaporization [ΔH_v]			+10% -10%
✖The Change in Temperature is the difference between the initial and final temperature.ⓘ Change in Temperature [∆T]			+10% -10%
✖Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP.ⓘ Change in Pressure [ΔP]			+10% -10%
✖Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.ⓘ Absolute Temperature [T_abs]			+10% -10%

✖Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.ⓘ Molar Vapor Volume given rate of pressure change [V_m]

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Formula

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Molar Vapor Volume given rate of pressure change

Formula

`"V"_{"m"} = "v"+(("ΔH"_{"v"}*"∆T")/("ΔP"*"T"_{"abs"}))`

Example

`"25.64652m³/mol"="5.5m³"+(("11KJ/mol"*"50K")/("100Pa"*"273"))`

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Molar Vapor Volume given rate of pressure change Solution

STEP 0: Pre-Calculation Summary

Formula Used

Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature))
V_m = v+((ΔH_v*∆T)/(ΔP*T_abs))
This formula uses 6 Variables

Variables Used

Molar Volume - (Measured in Cubic Meter per Mole) - Molar Volume is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure.
Molal Liquid Volume - (Measured in Cubic Meter) - Molal Liquid Volume is the volume of liquid substance.
Molal Heat of Vaporization - (Measured in Joule Per Mole) - Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid.
Change in Temperature - (Measured in Kelvin) - The Change in Temperature is the difference between the initial and final temperature.
Change in Pressure - (Measured in Pascal) - Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP.
Absolute Temperature - Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.

STEP 1: Convert Input(s) to Base Unit

Molal Liquid Volume: 5.5 Cubic Meter --> 5.5 Cubic Meter No Conversion Required
Molal Heat of Vaporization: 11 KiloJoule Per Mole --> 11000 Joule Per Mole (Check conversion here)
Change in Temperature: 50 Kelvin --> 50 Kelvin No Conversion Required
Change in Pressure: 100 Pascal --> 100 Pascal No Conversion Required
Absolute Temperature: 273 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

V_m = v+((ΔH_v*∆T)/(ΔP*T_abs)) --> 5.5+((11000*50)/(100*273))

Evaluating ... ...

V_m = 25.6465201465201

STEP 3: Convert Result to Output's Unit

25.6465201465201 Cubic Meter per Mole --> No Conversion Required

FINAL ANSWER

25.6465201465201 ≈ 25.64652 Cubic Meter per Mole <-- Molar Volume

(Calculation completed in 00.004 seconds)

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Home » Chemistry » Solution and Colligative properties » Relative Lowering of Vapour Pressure » Molar Vapor Volume given rate of pressure change

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Created by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

Akshada Kulkarni has created this Calculator and 500+ more calculators!

Verified by Pragati Jaju

College Of Engineering (COEP), Pune

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< 21 Relative Lowering of Vapour Pressure Calculators

Molecular Mass of Solute given Relative Lowering of Vapour Pressure

Go Molecular Mass Solute = (Weight of Solute*Molecular Mass Solvent*Vapour Pressure of Pure Solvent)/((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Weight of solvent)

Weight of Solvent given Relative Lowering of Vapour Pressure

Go Weight of solvent = (Vapour Pressure of Pure Solvent*Weight of Solute*Molecular Mass Solvent)/((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Molecular Mass Solute)

Weight of Solute given Relative Lowering of Vapour Pressure

Go Weight of Solute = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Weight of solvent*Molecular Mass Solute)/(Vapour Pressure of Pure Solvent*Molecular Mass Solvent)

Percentage of Saturation given pressure

Go Percentage of saturation = 100*((Partial Pressure*(Total Pressure-Vapor Pressure of Pure Component A))/(Vapor Pressure of Pure Component A*(Total Pressure-Partial Pressure)))

Van't Hoff Factor for Relative Lowering of Vapour Pressure using Number of Moles

Go Van't Hoff Factor = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Number of Moles of Solvent)/(Number of Moles of Solute*Vapour Pressure of Pure Solvent)

Van't Hoff Factor for Relative Lowering of Vapour Pressure given Molecular Mass and Molality

Go Van't Hoff Factor = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Vapour Pressure of Pure Solvent*Molality*Molecular Mass Solvent)

Moles of Solvent in Dilute Solution given Relative Lowering of Vapour Pressure

Go Number of Moles of Solvent = (Number of Moles of Solute*Vapour Pressure of Pure Solvent)/(Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)

Moles of Solute in Dilute Solution given Relative Lowering of Vapour Pressure

Go Number of Moles of Solute = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*Number of Moles of Solvent)/Vapour Pressure of Pure Solvent

Molar Vapor Volume given rate of pressure change

Go Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature))

Molecular Mass of Solvent given Relative Lowering of Vapour Pressure

Go Molecular Mass Solvent = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molality*Vapour Pressure of Pure Solvent)

Molality using Relative Lowering of Vapour Pressure

Go Molality = ((Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)*1000)/(Molecular Mass Solvent*Vapour Pressure of Pure Solvent)

Relative Lowering of Vapour Pressure given Weight and Molecular Mass of Solute and Solvent

Go Relative Lowering of Vapour Pressure = (Weight of Solute*Molecular Mass Solvent)/(Weight of solvent*Molecular Mass Solute)

Relative Lowering of Vapour Pressure

Go Relative Lowering of Vapour Pressure = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent

Mole Fraction of Solute given Vapour Pressure

Go Mole Fraction of Solute = (Vapour Pressure of Pure Solvent-Vapour Pressure of Solvent in Solution)/Vapour Pressure of Pure Solvent

Ostwald-Walker Dynamic Method for Relative Lowering of Vapour Pressure

Go Relative Lowering of Vapour Pressure = Loss of Mass in Bulb Set B/(Loss of Mass in bulb set A+Loss of Mass in Bulb Set B)

Relative Lowering of Vapour Pressure given Number of Moles for Concentrated Solution

Go Relative Lowering of Vapour Pressure = Number of Moles of Solute/(Number of Moles of Solute+Number of Moles of Solvent)

Van't Hoff Relative Lowering of Vapour Pressure given Number of Moles

Go Relative Lowering of Vapour Pressure = (Van't Hoff Factor*Number of Moles of Solute)/Number of Moles of Solvent

Van't Hoff Relative Lowering of Vapour Pressure given Molecular Mass and Molality

Go Colligative Pressure given Van't Hoff factor = (Van't Hoff Factor*Molality*Molecular Mass Solvent)/1000

Mole Fraction of Solvent given Vapour Pressure

Go Mole Fraction of Solvent = Vapour Pressure of Solvent in Solution/Vapour Pressure of Pure Solvent

Relative Lowering of Vapour Pressure given Number of Moles for Dilute Solution

Go Relative Lowering of Vapour Pressure = Number of Moles of Solute/Number of Moles of Solvent

Relative Lowering of Vapour Pressure given Molecular Mass and Molality

Go Relative Lowering of Vapour Pressure = (Molality*Molecular Mass Solvent)/1000

Molar Vapor Volume given rate of pressure change Formula

Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature))
V_m = v+((ΔH_v*∆T)/(ΔP*T_abs))

What is Clausius- Clapeyron Equation ?

The rate of increase in vapor pressure per unit increase in temperature is given by the Clausius-Clapeyron equation. More generally the Clausius-Clapeyron equation pertains to the relationship between the pressure and temperature for conditions of equilibrium between two phases. The two phases could be vapor and solid for sublimation or solid and liquid for melting.

How to Calculate Molar Vapor Volume given rate of pressure change?

Molar Vapor Volume given rate of pressure change calculator uses Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature)) to calculate the Molar Volume, The Molar Vapor Volume given rate of pressure change is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure. Molar Volume is denoted by V_m symbol.

How to calculate Molar Vapor Volume given rate of pressure change using this online calculator? To use this online calculator for Molar Vapor Volume given rate of pressure change, enter Molal Liquid Volume (v), Molal Heat of Vaporization (ΔH_v), Change in Temperature (∆T), Change in Pressure (ΔP) & Absolute Temperature (T_abs) and hit the calculate button. Here is how the Molar Vapor Volume given rate of pressure change calculation can be explained with given input values -> 25.64652 = 5.5+((11000*50)/(100*273)).

FAQ

What is Molar Vapor Volume given rate of pressure change?

The Molar Vapor Volume given rate of pressure change is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure and is represented as V_m = v+((ΔH_v*∆T)/(ΔP*T_abs)) or Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature)). Molal Liquid Volume is the volume of liquid substance, Molal Heat of Vaporization is the energy needed to vaporize one mole of a liquid, The Change in Temperature is the difference between the initial and final temperature, Change in Pressure is defined as the difference between final pressure and initial pressure. In differential form it is represented as dP & Absolute Temperature is temperature measured using the Kelvin scale where zero is absolute zero.

How to calculate Molar Vapor Volume given rate of pressure change?

The Molar Vapor Volume given rate of pressure change is the volume occupied by one mole of a substance which can be a chemical element or a chemical compound at Standard Temperature and Pressure is calculated using Molar Volume = Molal Liquid Volume+((Molal Heat of Vaporization*Change in Temperature)/(Change in Pressure*Absolute Temperature)). To calculate Molar Vapor Volume given rate of pressure change, you need Molal Liquid Volume (v), Molal Heat of Vaporization (ΔH_v), Change in Temperature (∆T), Change in Pressure (ΔP) & Absolute Temperature (T_abs). With our tool, you need to enter the respective value for Molal Liquid Volume, Molal Heat of Vaporization, Change in Temperature, Change in Pressure & Absolute Temperature and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

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