Power given Unit Power Solution

STEP 0: Pre-Calculation Summary
Formula Used
Hydroelectric Power = Unit Power*1000*Fall Height^(3/2)
Ph = Pu*1000*H^(3/2)
This formula uses 3 Variables
Variables Used
Hydroelectric Power - (Measured in Watt) - Hydroelectric Power depends on several factors such as the water flow rate, the height difference btw the water source & the turbine.
Unit Power - The unit power refers to the amount of power generated by a single generator unit. The maximum power output of a single generator unit.
Fall Height - (Measured in Meter) - Fall height, is an important factor in hydroelectric power generation. It refers to the vertical distance that the water falls from the intake point to the turbine.
STEP 1: Convert Input(s) to Base Unit
Unit Power: 1.3 --> No Conversion Required
Fall Height: 250 Meter --> 250 Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Ph = Pu*1000*H^(3/2) --> 1.3*1000*250^(3/2)
Evaluating ... ...
Ph = 5138701.19777362
STEP 3: Convert Result to Output's Unit
5138701.19777362 Watt -->5138.70119777362 Kilowatt (Check conversion here)
FINAL ANSWER
5138.70119777362 5138.701 Kilowatt <-- Hydroelectric Power
(Calculation completed in 00.004 seconds)

Credits

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Indian Institute of Technology,Roorlee (IITR), Roorkee
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23 Hydroelectric Power Plant Calculators

Dimensionless Specific Speed
Go Dimensionless Specific Speed = (Working Speed*sqrt(Hydroelectric Power/1000))/(sqrt(Water Density)*([g]*Fall Height)^(5/4))
Efficiency of Turbine given Energy
Go Turbine Efficiency = Energy/([g]*Water Density*Flow Rate*Fall Height*Operating Time per Year)
Energy Produced by Hydroelectric Power Plant
Go Energy = [g]*Water Density*Flow Rate*Fall Height*Turbine Efficiency*Operating Time per Year
Specific Speed of Turbine of Hydroelectric Power Plant
Go Specific Speed = (Working Speed*sqrt(Hydroelectric Power/1000))/Fall Height^(5/4)
Velocity of Jet from Nozzle
Go Velocity of Jet = Coefficient of Velocity*sqrt(2*[g]*Fall Height)
Head or Height of Fall of Water given Power
Go Fall Height = Hydroelectric Power/([g]*Water Density*Flow Rate)
Specific Speed of Single Jet Machine
Go Specific Speed of Single Jet Machine = Specific Speed of Multi Jet Machine/sqrt(Number of Jets)
Specific Speed of Multi Jet Machine
Go Specific Speed of Multi Jet Machine = sqrt(Number of Jets)*Specific Speed of Single Jet Machine
Flow Rate of Water given Power
Go Flow Rate = Hydroelectric Power/([g]*Water Density*Fall Height)
Tidal Energy
Go Tidal Power = 0.5*Area of Base*Water Density*[g]*Fall Height^2
Hydroelectric Power
Go Hydroelectric Power = [g]*Water Density*Flow Rate*Fall Height
Energy Produced by Hydroelectric Power Plant given Power
Go Energy = Hydroelectric Power*Turbine Efficiency*Operating Time per Year
Height of Fall of Pelton Wheel Turbine Power Plant
Go Fall Height = (Velocity of Jet^2)/(2*[g]*Coefficient of Velocity^2)
Diameter of Bucket
Go Bucket Circle Diameter = (60*Bucket Velocity)/(pi*Working Speed)
Speed of Bucket given Diameter and RPM
Go Bucket Velocity = (pi*Bucket Circle Diameter*Working Speed)/60
Number of Jets
Go Number of Jets = (Specific Speed of Multi Jet Machine/Specific Speed of Single Jet Machine)^2
Unit Speed of Turbine
Go Unit Speed = (Working Speed)/sqrt(Fall Height)
Speed of Turbine given Unit Speed
Go Working Speed = Unit Speed*sqrt(Fall Height)
Speed of Bucket given Angular Velocity and Radius
Go Bucket Velocity = Angular Velocity*Bucket Circle Diameter/2
Unit Power of Hydroelectric Power Plant
Go Unit Power = (Hydroelectric Power/1000)/Fall Height^(3/2)
Power given Unit Power
Go Hydroelectric Power = Unit Power*1000*Fall Height^(3/2)
Jet Ratio of Hydroelectric Power Plant
Go Jet Ratio = Bucket Circle Diameter/Nozzle Diameter
Angular Velocity of Wheel
Go Angular Velocity = (2*pi*Working Speed)/60

Power given Unit Power Formula

Hydroelectric Power = Unit Power*1000*Fall Height^(3/2)
Ph = Pu*1000*H^(3/2)

Who invented hydroelectricity?

In 1878, the world's first hydroelectric power scheme was developed at Cragside in Northumberland, England by William Armstrong. It was used to power a single arc lamp in his art gallery.

How to Calculate Power given Unit Power?

Power given Unit Power calculator uses Hydroelectric Power = Unit Power*1000*Fall Height^(3/2) to calculate the Hydroelectric Power, The Power given Unit Power formula is defined as the power generated by the Hydroelectric Power Plant. Hydroelectric Power is denoted by Ph symbol.

How to calculate Power given Unit Power using this online calculator? To use this online calculator for Power given Unit Power, enter Unit Power (Pu) & Fall Height (H) and hit the calculate button. Here is how the Power given Unit Power calculation can be explained with given input values -> 5.138701 = 1.3*1000*250^(3/2).

FAQ

What is Power given Unit Power?
The Power given Unit Power formula is defined as the power generated by the Hydroelectric Power Plant and is represented as Ph = Pu*1000*H^(3/2) or Hydroelectric Power = Unit Power*1000*Fall Height^(3/2). The unit power refers to the amount of power generated by a single generator unit. The maximum power output of a single generator unit & Fall height, is an important factor in hydroelectric power generation. It refers to the vertical distance that the water falls from the intake point to the turbine.
How to calculate Power given Unit Power?
The Power given Unit Power formula is defined as the power generated by the Hydroelectric Power Plant is calculated using Hydroelectric Power = Unit Power*1000*Fall Height^(3/2). To calculate Power given Unit Power, you need Unit Power (Pu) & Fall Height (H). With our tool, you need to enter the respective value for Unit Power & Fall Height and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Hydroelectric Power?
In this formula, Hydroelectric Power uses Unit Power & Fall Height. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Hydroelectric Power = [g]*Water Density*Flow Rate*Fall Height
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