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Power Transmitted Using Load Current (2-phase 4-wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
transmitted_power = Current Of 2-Φ 4-wire system*Maximum Voltage*cos(Theta)/sqrt(2)
P = C7*Vm*cos(ϑ)/sqrt(2)
This formula uses 2 Functions, 3 Variables
Functions Used
cos - Trigonometric cosine function, cos(Angle)
sqrt - Squre root function, sqrt(Number)
Variables Used
Current Of 2-Φ 4-wire system - Current Of 2-Φ 4-wire system the time rate of flow of charge through a cross-sectional area. (Measured in Ampere)
Maximum Voltage - Maximum Voltage the highest voltage rating for electrical devices (Measured in Volt)
Theta - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint. (Measured in Degree)
STEP 1: Convert Input(s) to Base Unit
Current Of 2-Φ 4-wire system: 8 Ampere --> 8 Ampere No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
P = C7*Vm*cos(ϑ)/sqrt(2) --> 8*60*cos(0.5235987755982)/sqrt(2)
Evaluating ... ...
P = 293.938769133981
STEP 3: Convert Result to Output's Unit
293.938769133981 Watt --> No Conversion Required
FINAL ANSWER
293.938769133981 Watt <-- Power Transmitted
(Calculation completed in 00.031 seconds)

11 Other formulas that you can solve using the same Inputs

Diagonal 1 of the parallelogram when sides and cosine β are given
diagonal_1 = sqrt((Side A)^2+(Side B)^2-2*Side A*Side B*cos(Theta)) Go
Diagonal 2 of the parallelogram when sides and cosine β are given
diagonal_2 = sqrt((Side A)^2+(Side B)^2+2*Side A*Side B*cos(Theta)) Go
Diagonal of a parallelogram when the area, diagonal, and angles between diagonals are given
diagonal_a = (2*Area)/(Diagonal B*sin(Theta)) Go
Radius of the Circumscribed Circle in terms of Cosine of Angle Adjacent to the Diagonal and Adjacent Side
radius_of_circumscribed_circle = Breadth/2*cos(Theta) Go
Area of rectangle in terms of sine of the acute angle between the diagonals and the diagonal of a rectangle
area = ((Diagonal)^2*sin(Theta))/2 Go
Breadth of rectangle when diagonal and angle between diagonals are given
breadth = Diagonal*cos(Theta/2) Go
Rectangle diagonal in terms of cosine of the angle that adjacent to the diagonal and the adjacent side of the angle
diagonal = Breadth/cos(Theta) Go
Rectangle diagonal in terms of sine of the angle
diagonal = Length/sin(Theta) Go
Side a of the parallelogram when the height and sine of an angle are given
side_a = Height/sin(Theta) Go
Side b of the parallelogram when the height and sine of an angle are given
side_b = Height/sin(Theta) Go
Angle between the rectangle diagonals when angle between the diagonal and rectangle side is given
angle_between_two_diagonals = 2*Theta Go

11 Other formulas that calculate the same Output

Power Transmitted Using Volume Of Conductor Material (2-phase 3-wire US)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(Resistivity*(((2+sqrt(2))*Length)^2))) Go
Power Transmitted Using Volume Of Conductor Material (2-phase 3-wire OS)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(Resistivity*(((2+sqrt(2))*Length)^2))) Go
Power Transmitted Using Volume Of Conductor Material (3-phase 4-wire OS)
transmitted_power = sqrt(3*Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(7*Resistivity*(Length)^2)) Go
Power Transmitted Using Volume Of Conductor Material (1-phase 3-wire OS)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(2.5*Resistivity*(Length)^2)) Go
Transmitted Power Using Volume Of Conductor Material(1-phase 3-wire US)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(10*Resistivity*(Length)^2)) Go
Power Transmitted Using Volume Of Conductor Material (1-Phase 2-Wire US)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(8*Resistivity*(Length)^2)) Go
Power Transmitted Using Volume Of Conductor Material (3-phase 4-wire US)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(7*Resistivity*(Length)^2)) Go
Power Transmitted Using Volume Of Conductor Material (3-phase 3-wire US)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(6*Resistivity*(Length)^2)) Go
Transmitted Power Using Volume Of Conductor Material(DC Three-Wire US)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage^2)/(5*Resistivity*(Length)^2)) Go
Transmitted Power Using Volume Of Conductor Material(2-Wire Mid-point Earthed OS)
transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage^2)/(Resistivity*(Length)^2)) Go
Power Transmitted(1-Phase 2-Wire US)
transmitted_power = Power Transmitted*(1) Go

Power Transmitted Using Load Current (2-phase 4-wire US) Formula

transmitted_power = Current Of 2-Φ 4-wire system*Maximum Voltage*cos(Theta)/sqrt(2)
P = C7*Vm*cos(ϑ)/sqrt(2)

What is the value of maximum voltage in 2-phase 4-wire underground system?

The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

How to Calculate Power Transmitted Using Load Current (2-phase 4-wire US)?

Power Transmitted Using Load Current (2-phase 4-wire US) calculator uses transmitted_power = Current Of 2-Φ 4-wire system*Maximum Voltage*cos(Theta)/sqrt(2) to calculate the Power Transmitted, The Power Transmitted Using Load Current (2-phase 4-wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations. Power Transmitted and is denoted by P symbol.

How to calculate Power Transmitted Using Load Current (2-phase 4-wire US) using this online calculator? To use this online calculator for Power Transmitted Using Load Current (2-phase 4-wire US), enter Current Of 2-Φ 4-wire system (C7), Maximum Voltage (Vm) and Theta (ϑ) and hit the calculate button. Here is how the Power Transmitted Using Load Current (2-phase 4-wire US) calculation can be explained with given input values -> 293.9388 = 8*60*cos(0.5235987755982)/sqrt(2).

FAQ

What is Power Transmitted Using Load Current (2-phase 4-wire US)?
The Power Transmitted Using Load Current (2-phase 4-wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations and is represented as P = C7*Vm*cos(ϑ)/sqrt(2) or transmitted_power = Current Of 2-Φ 4-wire system*Maximum Voltage*cos(Theta)/sqrt(2). Current Of 2-Φ 4-wire system the time rate of flow of charge through a cross-sectional area, Maximum Voltage the highest voltage rating for electrical devices and Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
How to calculate Power Transmitted Using Load Current (2-phase 4-wire US)?
The Power Transmitted Using Load Current (2-phase 4-wire US) formula is defined as the bulk movement of electrical energy from a generating site, such as a power station or power plant, to an electrical substation where voltage is transformed and distributed to consumers or other substations is calculated using transmitted_power = Current Of 2-Φ 4-wire system*Maximum Voltage*cos(Theta)/sqrt(2). To calculate Power Transmitted Using Load Current (2-phase 4-wire US), you need Current Of 2-Φ 4-wire system (C7), Maximum Voltage (Vm) and Theta (ϑ). With our tool, you need to enter the respective value for Current Of 2-Φ 4-wire system, Maximum Voltage and Theta and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Power Transmitted?
In this formula, Power Transmitted uses Current Of 2-Φ 4-wire system, Maximum Voltage and Theta. We can use 11 other way(s) to calculate the same, which is/are as follows -
  • transmitted_power = Power Transmitted*(1)
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(8*Resistivity*(Length)^2))
  • transmitted_power = sqrt(3*Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(7*Resistivity*(Length)^2))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(7*Resistivity*(Length)^2))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(6*Resistivity*(Length)^2))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(Resistivity*(((2+sqrt(2))*Length)^2)))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(Resistivity*(((2+sqrt(2))*Length)^2)))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(2.5*Resistivity*(Length)^2))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage^2)/(5*Resistivity*(Length)^2))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage*cos(Theta))^2/(10*Resistivity*(Length)^2))
  • transmitted_power = sqrt(Line Losses*Volume Of Conductor Material*(Maximum Voltage^2)/(Resistivity*(Length)^2))
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