Radius 1 given Rotational Frequency Calculator

✖Velocity of particle with mass m1 is the rate at which particle (of mass m1) moves.ⓘ Velocity of Particle with Mass m1 [v₁]			+10% -10%
✖Rotational Frequency is defined as the number of rotations per unit time or reciprocal of the time period of one complete rotation.ⓘ Rotational Frequency [ν_rot]			+10% -10%

✖Mass 2 of Diatomic Molecule is the quantity of matter in a body 1 regardless of its volume or of any forces acting on it.ⓘ Radius 1 given Rotational Frequency [m_d2]

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Formula

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Radius 1 given Rotational Frequency

Formula

`"m"_{"d2"} = "v"_{"1"}/(2*pi*"ν"_{"rot"})`

Example

`"0.025465kg"="1.6m/s"/(2*pi*"10Hz")`

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Radius 1 given Rotational Frequency Solution

STEP 0: Pre-Calculation Summary

Formula Used

Mass 2 of Diatomic Molecule = Velocity of Particle with Mass m1/(2*pi*Rotational Frequency)
m_d2 = v₁/(2*pi*ν_rot)
This formula uses 1 Constants, 3 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Variables Used

Mass 2 of Diatomic Molecule - (Measured in Kilogram) - Mass 2 of Diatomic Molecule is the quantity of matter in a body 1 regardless of its volume or of any forces acting on it.
Velocity of Particle with Mass m1 - (Measured in Meter per Second) - Velocity of particle with mass m1 is the rate at which particle (of mass m1) moves.
Rotational Frequency - (Measured in Hertz) - Rotational Frequency is defined as the number of rotations per unit time or reciprocal of the time period of one complete rotation.

STEP 1: Convert Input(s) to Base Unit

Velocity of Particle with Mass m1: 1.6 Meter per Second --> 1.6 Meter per Second No Conversion Required
Rotational Frequency: 10 Hertz --> 10 Hertz No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

m_d2 = v₁/(2*pi*ν_rot) --> 1.6/(2*pi*10)

Evaluating ... ...

m_d2 = 0.0254647908947033

STEP 3: Convert Result to Output's Unit

0.0254647908947033 Kilogram --> No Conversion Required

FINAL ANSWER

0.0254647908947033 ≈ 0.025465 Kilogram <-- Mass 2 of Diatomic Molecule

(Calculation completed in 00.004 seconds)

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Home » Chemistry » Analytical chemistry » Molecular Spectroscopy » Rotational Spectroscopy » Reduced Mass and Radius of Diatomic Molecule » Radius 1 given Rotational Frequency

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Created by Nishant Sihag

Indian Institute of Technology (IIT), Delhi

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Verified by Akshada Kulkarni

National Institute of Information Technology (NIIT), Neemrana

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< 13 Reduced Mass and Radius of Diatomic Molecule Calculators

Radius 2 given Moment of Inertia

Go Radius 2 given Moment of Inertia = sqrt((Moment of Inertia-(Mass 1*Radius of Mass 1^2))/Mass 2)

Radius 1 given Moment of Inertia

Go Mass 2 of Diatomic Molecule = sqrt((Moment of Inertia-(Mass 2*Radius of Mass 2^2))/Mass 1)

Mass 2 given Moment of Inertia

Go Mass 2 given Moment of Inertia = (Moment of Inertia-(Mass 1*Radius of Mass 1^2))/Radius of Mass 2^2

Mass 1 given Moment of Inertia

Go Mass2 of object1 = (Moment of Inertia-(Mass 2*Radius of Mass 2^2))/Radius of Mass 1^2

Radius 1 given Rotational Frequency

Go Mass 2 of Diatomic Molecule = Velocity of Particle with Mass m1/(2*pi*Rotational Frequency)

Radius 1 of Rotation given Masses and Bond Length

Go Radius 1 of Rotation = Mass 2*Bond Length/(Mass 1+Mass 2)

Radius 2 of Rotation given Masses and Bond Length

Go Radius of Mass 2 = Mass 1*Bond Length/(Mass 1+Mass 2)

Radius 2 given Rotational Frequency

Go Radius of Mass 2 = Velocity of Particle with Mass m2/(2*pi*Rotational Frequency)

Reduced Mass

Go Reduced Mass = ((Mass 1*Mass 2)/(Mass 1+Mass 2))

Mass 1 of Diatomic Molecule

Go Mass 1 of Diatomic Molecule = Mass 2*Radius of Mass 2/Radius of Mass 1

Mass 2 of Diatomic Molecule

Go Mass 2 of Diatomic Molecule = Mass 1*Radius of Mass 1/Radius of Mass 2

Radius 2 of Rotation

Go Radius 1 given Rotational Frequency = Mass 1*Radius of Mass 1/Mass 2

Radius 1 of Rotation

Go Radius 1 of Rotation = Mass 2*Radius of Mass 2/Mass 1

< 13 Reduced Mass and Radius of Diatomic Molecule Calculators

Radius 2 given Moment of Inertia

Go Radius 2 given Moment of Inertia = sqrt((Moment of Inertia-(Mass 1*Radius of Mass 1^2))/Mass 2)

Radius 1 given Moment of Inertia

Go Mass 2 of Diatomic Molecule = sqrt((Moment of Inertia-(Mass 2*Radius of Mass 2^2))/Mass 1)

Mass 2 given Moment of Inertia

Go Mass 2 given Moment of Inertia = (Moment of Inertia-(Mass 1*Radius of Mass 1^2))/Radius of Mass 2^2

Mass 1 given Moment of Inertia

Go Mass2 of object1 = (Moment of Inertia-(Mass 2*Radius of Mass 2^2))/Radius of Mass 1^2

Radius 1 given Rotational Frequency

Go Mass 2 of Diatomic Molecule = Velocity of Particle with Mass m1/(2*pi*Rotational Frequency)

Radius 1 of Rotation given Masses and Bond Length

Go Radius 1 of Rotation = Mass 2*Bond Length/(Mass 1+Mass 2)

Radius 2 of Rotation given Masses and Bond Length

Go Radius of Mass 2 = Mass 1*Bond Length/(Mass 1+Mass 2)

Radius 2 given Rotational Frequency

Go Radius of Mass 2 = Velocity of Particle with Mass m2/(2*pi*Rotational Frequency)

Reduced Mass

Go Reduced Mass = ((Mass 1*Mass 2)/(Mass 1+Mass 2))

Mass 1 of Diatomic Molecule

Go Mass 1 of Diatomic Molecule = Mass 2*Radius of Mass 2/Radius of Mass 1

Mass 2 of Diatomic Molecule

Go Mass 2 of Diatomic Molecule = Mass 1*Radius of Mass 1/Radius of Mass 2

Radius 2 of Rotation

Go Radius 1 given Rotational Frequency = Mass 1*Radius of Mass 1/Mass 2

Radius 1 of Rotation

Go Radius 1 of Rotation = Mass 2*Radius of Mass 2/Mass 1

Radius 1 given Rotational Frequency Formula

Mass 2 of Diatomic Molecule = Velocity of Particle with Mass m1/(2*pi*Rotational Frequency)
m_d2 = v₁/(2*pi*ν_rot)

How to get Radius 1 when rotational frequency is given?

We know linear velocity (v) is radius(r) times the angular velocity (ω) {i.e. v=r*ω} ,and angular velocity (ω) is equal to the product of the rotational frequency (f) and the constant 2pi {ω= 2*pi* f} . So considering these two relations give us a simple relation of radius {i.e. r= velocity/(2*pi*f) } and thus we obtain Radius 1.

How to Calculate Radius 1 given Rotational Frequency?

Radius 1 given Rotational Frequency calculator uses Mass 2 of Diatomic Molecule = Velocity of Particle with Mass m1/(2*pi*Rotational Frequency) to calculate the Mass 2 of Diatomic Molecule, The Radius 1 given rotational frequency formula is defined to relate radius with velocity and rotational frequency. The linear velocity is the radius times the angular velocity and further the relation of angular velocity with frequency (angular velocity = 2*pi* frequency). So by these equations, the radius is velocity divided by (2 * pi times Rotational frequency). Mass 2 of Diatomic Molecule is denoted by m_d2 symbol.

How to calculate Radius 1 given Rotational Frequency using this online calculator? To use this online calculator for Radius 1 given Rotational Frequency, enter Velocity of Particle with Mass m1 (v₁) & Rotational Frequency (ν_rot) and hit the calculate button. Here is how the Radius 1 given Rotational Frequency calculation can be explained with given input values -> 0.025465 = 1.6/(2*pi*10).

FAQ

What is Radius 1 given Rotational Frequency?

The Radius 1 given rotational frequency formula is defined to relate radius with velocity and rotational frequency. The linear velocity is the radius times the angular velocity and further the relation of angular velocity with frequency (angular velocity = 2*pi* frequency). So by these equations, the radius is velocity divided by (2 * pi times Rotational frequency) and is represented as m_d2 = v₁/(2*pi*ν_rot) or Mass 2 of Diatomic Molecule = Velocity of Particle with Mass m1/(2*pi*Rotational Frequency). Velocity of particle with mass m1 is the rate at which particle (of mass m1) moves & Rotational Frequency is defined as the number of rotations per unit time or reciprocal of the time period of one complete rotation.

How to calculate Radius 1 given Rotational Frequency?

The Radius 1 given rotational frequency formula is defined to relate radius with velocity and rotational frequency. The linear velocity is the radius times the angular velocity and further the relation of angular velocity with frequency (angular velocity = 2*pi* frequency). So by these equations, the radius is velocity divided by (2 * pi times Rotational frequency) is calculated using Mass 2 of Diatomic Molecule = Velocity of Particle with Mass m1/(2*pi*Rotational Frequency). To calculate Radius 1 given Rotational Frequency, you need Velocity of Particle with Mass m1 (v₁) & Rotational Frequency (ν_rot). With our tool, you need to enter the respective value for Velocity of Particle with Mass m1 & Rotational Frequency and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Mass 2 of Diatomic Molecule?

In this formula, Mass 2 of Diatomic Molecule uses Velocity of Particle with Mass m1 & Rotational Frequency. We can use 4 other way(s) to calculate the same, which is/are as follows -

Mass 2 of Diatomic Molecule = Mass 1*Radius of Mass 1/Radius of Mass 2
Mass 2 of Diatomic Molecule = sqrt((Moment of Inertia-(Mass 2*Radius of Mass 2^2))/Mass 1)
Mass 2 of Diatomic Molecule = Mass 1*Radius of Mass 1/Radius of Mass 2
Mass 2 of Diatomic Molecule = sqrt((Moment of Inertia-(Mass 2*Radius of Mass 2^2))/Mass 1)

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