Ratio Molar Heat Capacity given Compressibility Solution

STEP 0: Pre-Calculation Summary
Formula Used
Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility
γ = KT/KS
This formula uses 3 Variables
Variables Used
Ratio of Molar Heat Capacity - The Ratio of Molar Heat Capacity is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume.
Isothermal Compressibility - (Measured in Square Meter per Newton) - The isothermal compressibility is the change in volume due to change in pressure at constant temperature.
Isentropic Compressibility - (Measured in Square Meter per Newton) - The Isentropic Compressibility is the change in volume due to change in pressure at constant entropy.
STEP 1: Convert Input(s) to Base Unit
Isothermal Compressibility: 75 Square Meter per Newton --> 75 Square Meter per Newton No Conversion Required
Isentropic Compressibility: 70 Square Meter per Newton --> 70 Square Meter per Newton No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
γ = KT/KS --> 75/70
Evaluating ... ...
γ = 1.07142857142857
STEP 3: Convert Result to Output's Unit
1.07142857142857 --> No Conversion Required
FINAL ANSWER
1.07142857142857 1.071429 <-- Ratio of Molar Heat Capacity
(Calculation completed in 00.004 seconds)

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7 Ratio of Molar Heat Capacity Calculators

Ratio of Molar Heat Capacity of Linear Molecule
Go Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
Ratio of Molar Heat Capacity given Molar Heat Capacity at Constant Pressure
Go Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/(Molar Specific Heat Capacity at Constant Pressure-[R])
Ratio of Molar Heat Capacity given Molar Heat Capacity at Constant Volume
Go Ratio of Molar Heat Capacity = (Molar Specific Heat Capacity at Constant Volume+[R])/Molar Specific Heat Capacity at Constant Volume
Ratio of Molar Heat Capacity
Go Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume
Ratio Molar Heat Capacity given Compressibility
Go Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility
Ratio of Molar Heat Capacity of Non-Linear Molecule
Go Ratio of Molar Heat Capacity = (4+((3*Atomicity)-6))/(3+((3*Atomicity)-6))
Ratio of Molar Heat Capacity given Degree of Freedom
Go Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)

Ratio Molar Heat Capacity given Compressibility Formula

Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility
γ = KT/KS

What are the postulates of kinetic theory of gases?

1) Actual volume of gas molecules is negligible in comparison to the total volume of the gas. 2) no force of attraction between the gas molecules. 3) Particles of gas are in constant random motion. 4) Particles of gas collide with each other and with the walls of the container. 5)Collisions are perfectly elastic. 6) Different particles of the gas, have different speeds. 7) The average kinetic energy of the gas molecule is directly proportional to the absolute temperature.

How to Calculate Ratio Molar Heat Capacity given Compressibility?

Ratio Molar Heat Capacity given Compressibility calculator uses Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility to calculate the Ratio of Molar Heat Capacity, The Ratio Molar Heat Capacity given Compressibility is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume. Ratio of Molar Heat Capacity is denoted by γ symbol.

How to calculate Ratio Molar Heat Capacity given Compressibility using this online calculator? To use this online calculator for Ratio Molar Heat Capacity given Compressibility, enter Isothermal Compressibility (KT) & Isentropic Compressibility (KS) and hit the calculate button. Here is how the Ratio Molar Heat Capacity given Compressibility calculation can be explained with given input values -> 1.071429 = 75/70.

FAQ

What is Ratio Molar Heat Capacity given Compressibility?
The Ratio Molar Heat Capacity given Compressibility is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume and is represented as γ = KT/KS or Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility. The isothermal compressibility is the change in volume due to change in pressure at constant temperature & The Isentropic Compressibility is the change in volume due to change in pressure at constant entropy.
How to calculate Ratio Molar Heat Capacity given Compressibility?
The Ratio Molar Heat Capacity given Compressibility is the ratio of the specific heat of the gas at a constant pressure to its specific heat at a constant volume is calculated using Ratio of Molar Heat Capacity = Isothermal Compressibility/Isentropic Compressibility. To calculate Ratio Molar Heat Capacity given Compressibility, you need Isothermal Compressibility (KT) & Isentropic Compressibility (KS). With our tool, you need to enter the respective value for Isothermal Compressibility & Isentropic Compressibility and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Ratio of Molar Heat Capacity?
In this formula, Ratio of Molar Heat Capacity uses Isothermal Compressibility & Isentropic Compressibility. We can use 6 other way(s) to calculate the same, which is/are as follows -
  • Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/Molar Specific Heat Capacity at Constant Volume
  • Ratio of Molar Heat Capacity = 1+(2/Degree of Freedom)
  • Ratio of Molar Heat Capacity = Molar Specific Heat Capacity at Constant Pressure/(Molar Specific Heat Capacity at Constant Pressure-[R])
  • Ratio of Molar Heat Capacity = (Molar Specific Heat Capacity at Constant Volume+[R])/Molar Specific Heat Capacity at Constant Volume
  • Ratio of Molar Heat Capacity = ((((3*Atomicity)-2.5)*[R])+[R])/(((3*Atomicity)-2.5)*[R])
  • Ratio of Molar Heat Capacity = (4+((3*Atomicity)-6))/(3+((3*Atomicity)-6))
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