Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters Solution

STEP 0: Pre-Calculation Summary
Formula Used
Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R]))
Tr = Trg/(((c+Vc)*8*P'c)/(3*[R]))
This formula uses 1 Constants, 5 Variables
Constants Used
[R] - Universal gas constant Value Taken As 8.31446261815324
Variables Used
Reduced Temperature - Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.
Temperature of Real Gas - (Measured in Kelvin) - Temperature of Real Gas is the degree or intensity of heat present in a substance or object.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Critical Volume - (Measured in Cubic Meter) - The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure.
Critical Pressure of Real Gas - (Measured in Pascal) - Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.
STEP 1: Convert Input(s) to Base Unit
Temperature of Real Gas: 300 Kelvin --> 300 Kelvin No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required
Critical Volume: 10 Liter --> 0.01 Cubic Meter (Check conversion here)
Critical Pressure of Real Gas: 4600000 Pascal --> 4600000 Pascal No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Tr = Trg/(((c+Vc)*8*P'c)/(3*[R])) --> 300/(((0.0002+0.01)*8*4600000)/(3*[R]))
Evaluating ... ...
Tr = 0.0199355721343188
STEP 3: Convert Result to Output's Unit
0.0199355721343188 --> No Conversion Required
FINAL ANSWER
0.0199355721343188 0.019936 <-- Reduced Temperature
(Calculation completed in 00.020 seconds)

Credits

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University of Hawaiʻi at Mānoa (UH Manoa), Hawaii, USA
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9 Reduced Temperature of Real Gas Calculators

Reduced Temperature of Real Gas using Clausius Equation given Reduced and Critical Parameters
Go Reduced Temperature = (((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model
Reduced Temperature of Real Gas using Clausius Equation given Critical and Actual Parameters
Go Reduced Temperature = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model
Reduced Temperature of Real Gas using Clausius Equation given Reduced and Actual Parameters
Go Reduced Temperature given RP AP = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Temperature of Real Gas
Reduced Temperature of Real Gas using Clausius Parameter b given Reduced and Actual Parameters
Go Reduced Temperature = Temperature of Real Gas/(((Volume of Real Gas/Reduced Volume)-Clausius Parameter b for Real Gas)*((4*(Pressure/Reduced Pressure))/[R]))
Reduced Temperature of Real Gas given Clausius Parameter c given Reduced and Actual Parameters
Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+(Volume of Real Gas/Reduced Volume))*8*(Pressure/Reduced Pressure))/(3*[R]))
Reduced Temperature of Real Gas using Clausius Parameter b and Actual Parameters
Go Reduced Temperature = Temperature of Real Gas/((Critical Volume-Clausius Parameter b for Real Gas)*((4*Critical Pressure of Real Gas)/[R]))
Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters
Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R]))
Reduced Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters
Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))
Reduced Temperature of Real Gas given Clausius Parameter and Actual Parameters
Go Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))

Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters Formula

Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R]))
Tr = Trg/(((c+Vc)*8*P'c)/(3*[R]))

What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters?

Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters calculator uses Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R])) to calculate the Reduced Temperature, The Reduced Temperature of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless. Reduced Temperature is denoted by Tr symbol.

How to calculate Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters using this online calculator? To use this online calculator for Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters, enter Temperature of Real Gas (Trg), Clausius Parameter c (c), Critical Volume (Vc) & Critical Pressure of Real Gas (P'c) and hit the calculate button. Here is how the Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters calculation can be explained with given input values -> 0.005648 = 300/(((0.0002+0.01)*8*4600000)/(3*[R])).

FAQ

What is Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters?
The Reduced Temperature of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless and is represented as Tr = Trg/(((c+Vc)*8*P'c)/(3*[R])) or Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R])). Temperature of Real Gas is the degree or intensity of heat present in a substance or object, Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas, The Critical Volume is the volume occupied by the unit mass of gas at critical temperature and pressure & Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.
How to calculate Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters?
The Reduced Temperature of real gas given Clausius parameter c and actual parameters formula is defined as the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless is calculated using Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+Critical Volume)*8*Critical Pressure of Real Gas)/(3*[R])). To calculate Reduced Temperature of Real Gas given Clausius Parameter c and Actual Parameters, you need Temperature of Real Gas (Trg), Clausius Parameter c (c), Critical Volume (Vc) & Critical Pressure of Real Gas (P'c). With our tool, you need to enter the respective value for Temperature of Real Gas, Clausius Parameter c, Critical Volume & Critical Pressure of Real Gas and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Reduced Temperature?
In this formula, Reduced Temperature uses Temperature of Real Gas, Clausius Parameter c, Critical Volume & Critical Pressure of Real Gas. We can use 7 other way(s) to calculate the same, which is/are as follows -
  • Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))
  • Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter a*64*(Pressure/Reduced Pressure))/(27*([R]^2)))^(1/3))
  • Reduced Temperature = Temperature of Real Gas/(((Clausius Parameter c+(Volume of Real Gas/Reduced Volume))*8*(Pressure/Reduced Pressure))/(3*[R]))
  • Reduced Temperature = ((Pressure+(Clausius Parameter a/(((Molar Volume+Clausius Parameter c)^2))))*((Molar Volume-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model
  • Reduced Temperature = (((Reduced Pressure*Critical Pressure of Real Gas)+(Clausius Parameter a/((((Reduced Molar Volume for Real Gas*Critical Molar Volume)+Clausius Parameter c)^2))))*(((Reduced Molar Volume for Real Gas*Critical Molar Volume)-Clausius Parameter b for Real Gas)/[R]))/Critical Temperature For Clausius Model
  • Reduced Temperature = Temperature of Real Gas/((Critical Volume-Clausius Parameter b for Real Gas)*((4*Critical Pressure of Real Gas)/[R]))
  • Reduced Temperature = Temperature of Real Gas/(((Volume of Real Gas/Reduced Volume)-Clausius Parameter b for Real Gas)*((4*(Pressure/Reduced Pressure))/[R]))
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