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## Resistivity Using Area Of X-Section (1-Phase 2-Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2))
ρ = a4*(Vm^2)*W*((cos(ϑ))^2)/((4)*l*(P^2))
This formula uses 1 Functions, 6 Variables
Functions Used
cos - Trigonometric cosine function, cos(Angle)
Variables Used
Area Of 1-Φ 2-wire system - The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object. (Measured in Square Meter)
Maximum Voltage - Maximum Voltage the highest voltage rating for electrical devices (Measured in Volt)
Line Losses - Line Losses is defined as the losses that are produced in the line. (Measured in Watt)
Theta - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint. (Measured in Degree)
Length - Length is the measurement or extent of something from end to end. (Measured in Meter)
Power Transmitted - The Power Transmitted Value through a shaft. (Measured in Kilowatt)
STEP 1: Convert Input(s) to Base Unit
Area Of 1-Φ 2-wire system: 6 Square Meter --> 6 Square Meter No Conversion Required
Maximum Voltage: 60 Volt --> 60 Volt No Conversion Required
Line Losses: 0.6 Watt --> 0.6 Watt No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Length: 3 Meter --> 3 Meter No Conversion Required
Power Transmitted: 10 Kilowatt --> 10000 Watt (Check conversion here)
STEP 2: Evaluate Formula
Substituting Input Values in Formula
ρ = a4*(Vm^2)*W*((cos(ϑ))^2)/((4)*l*(P^2)) --> 6*(60^2)*0.6*((cos(0.5235987755982))^2)/((4)*3*(10000^2))
Evaluating ... ...
ρ = 8.1E-06
STEP 3: Convert Result to Output's Unit
8.1E-06 Ohm Meter --> No Conversion Required
8.1E-06 Ohm Meter <-- Resistivity
(Calculation completed in 00.031 seconds)

## < 9 Area Of X-Section Calculators

Power Transmitted Using Area Of X-Section (1-Phase 2-Wire US)
power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length)) Go
Maximum Voltage Using Area Of X-Section (1-Phase 2-Wire US)
maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2)) Go
RMS Voltage Using Area Of X-Section (1-Phase 2-Wire US)
rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2))) Go
Power Factor Using Area Of X-Section (1-Phase 2-Wire US)
power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2))) Go
Resistivity Using Area Of X-Section (1-Phase 2-Wire US)
resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2)) Go
Line Losses Using Area Of X-Section (1-Phase 2-Wire US)
line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2)) Go
Length Using Area Of X-Section (1-Phase 2-Wire US)
length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity) Go
Constant Using Area Of X-Section (1-Phase 2-Wire US)
constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2 Go
Volume Of Conductor Material Using Area Of X-Section (1-Phase 2-Wire US)
volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2 Go

### Resistivity Using Area Of X-Section (1-Phase 2-Wire US) Formula

resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2))
ρ = a4*(Vm^2)*W*((cos(ϑ))^2)/((4)*l*(P^2))

## What is the value of maximum voltage and volume of conductor material in 1-phase 2-wire system?

The volume of conductor material required in this system is 2/cos2θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is vm so that r.m.s. value of voltage between them is vm/√2.

## How to Calculate Resistivity Using Area Of X-Section (1-Phase 2-Wire US)?

Resistivity Using Area Of X-Section (1-Phase 2-Wire US) calculator uses resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2)) to calculate the Resistivity, The Resistivity Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity and is denoted by ρ symbol.

How to calculate Resistivity Using Area Of X-Section (1-Phase 2-Wire US) using this online calculator? To use this online calculator for Resistivity Using Area Of X-Section (1-Phase 2-Wire US), enter Area Of 1-Φ 2-wire system (a4), Maximum Voltage (Vm), Line Losses (W), Theta (ϑ), Length (l) and Power Transmitted (P) and hit the calculate button. Here is how the Resistivity Using Area Of X-Section (1-Phase 2-Wire US) calculation can be explained with given input values -> 8.100E-6 = 6*(60^2)*0.6*((cos(0.5235987755982))^2)/((4)*3*(10000^2)).

### FAQ

What is Resistivity Using Area Of X-Section (1-Phase 2-Wire US)?
The Resistivity Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = a4*(Vm^2)*W*((cos(ϑ))^2)/((4)*l*(P^2)) or resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2)). The Area Of 1-Φ 2-wire system is the amount of two-dimensional space taken up by an object, Maximum Voltage the highest voltage rating for electrical devices, Line Losses is defined as the losses that are produced in the line, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint, Length is the measurement or extent of something from end to end and The Power Transmitted Value through a shaft.
How to calculate Resistivity Using Area Of X-Section (1-Phase 2-Wire US)?
The Resistivity Using Area Of X-Section (1-Phase 2-Wire US) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2)). To calculate Resistivity Using Area Of X-Section (1-Phase 2-Wire US), you need Area Of 1-Φ 2-wire system (a4), Maximum Voltage (Vm), Line Losses (W), Theta (ϑ), Length (l) and Power Transmitted (P). With our tool, you need to enter the respective value for Area Of 1-Φ 2-wire system, Maximum Voltage, Line Losses, Theta, Length and Power Transmitted and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Resistivity?
In this formula, Resistivity uses Area Of 1-Φ 2-wire system, Maximum Voltage, Line Losses, Theta, Length and Power Transmitted. We can use 9 other way(s) to calculate the same, which is/are as follows -
• power_transmitted = sqrt((Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2))/(4*Resistivity*Length))
• resistivity = Area Of 1-Φ 2-wire system*(Maximum Voltage^2)*Line Losses*((cos(Theta))^2)/((4)*Length*(Power Transmitted^2))
• length = Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage*cos(Theta))^2/(4*(Power Transmitted^2)*Resistivity)
• line_losses = (4*Length*Resistivity*(Power Transmitted^2))/(Area Of X-Section*(Maximum Voltage^2)*((cos(Theta))^2))
• maximum_voltage = sqrt((4*Length*Resistivity*(Power Transmitted^2))/(Area Of 1-Φ 2-wire system*Line Losses*(cos(Theta))^2))
• rms_voltage = sqrt((2*Length*Resistivity*(Power Transmitted^2))/(Area Of 2-Φ 3-wire system*Line Losses*((cos(Theta))^2)))
• power_factor = sqrt(((4)*(Power Transmitted^2)*Resistivity*Length)/(Area Of 1-Φ 2-wire system*Line Losses*(Maximum Voltage^2)))
• constant = Area Of 1-Φ 2-wire system*Length*(cos(Theta))^2
• volume_of_conductor_material = Area Of 1-Φ 2-wire system*Length*2
Where is the Resistivity Using Area Of X-Section (1-Phase 2-Wire US) calculator used?
Among many, Resistivity Using Area Of X-Section (1-Phase 2-Wire US) calculator is widely used in real life applications like {FormulaUses}. Here are few more real life examples -
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