Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Calculator

✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of Underground AC Wire [A]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Underground AC [I]			+10% -10%

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) [ρ]

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Formula

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Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Formula

`"ρ" = "P"_{"loss"}*"A"/(2*"L"*("I"^2))`

Example

`"0.000879Ω*m"="2.67W"*"1.28m²"/(2*"24m"*(("9A")^2))`

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Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2))
ρ = P_loss*A/(2*L*(I^2))
This formula uses 5 Variables

Variables Used

Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.

STEP 1: Convert Input(s) to Base Unit

Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

ρ = P_loss*A/(2*L*(I^2)) --> 2.67*1.28/(2*24*(9^2))

Evaluating ... ...

ρ = 0.000879012345679012

STEP 3: Convert Result to Output's Unit

0.000879012345679012 Ohm Meter --> No Conversion Required

FINAL ANSWER

0.000879012345679012 ≈ 0.000879 Ohm Meter <-- Resistivity

(Calculation completed in 00.004 seconds)

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< 3 Resistance & Resistivity Calculators

Resistivity using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Go Resistivity = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Length of Underground AC Wire)

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Go Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2))

Resistance using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

Go Resistance Underground AC = Line Losses/(2*(Current Underground AC^2))

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula

Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2))
ρ = P_loss*A/(2*L*(I^2))

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) calculator uses Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2)) to calculate the Resistivity, The Resistivity using Line Losses (1-phase 2-wire Mid-point Earthed) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors. Resistivity is denoted by ρ symbol.

How to calculate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed), enter Line Losses (P_loss), Area of Underground AC Wire (A), Length of Underground AC Wire (L) & Current Underground AC (I) and hit the calculate button. Here is how the Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 0.000879 = 2.67*1.28/(2*24*(9^2)).

FAQ

What is Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

The Resistivity using Line Losses (1-phase 2-wire Mid-point Earthed) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors and is represented as ρ = P_loss*A/(2*L*(I^2)) or Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2)). Line Losses is defined as the total losses occurring in an Underground AC line when in use, Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system, Length of Underground AC Wire is the total length of the wire from one end to other end & Current Underground AC is defined as the current flowing through the overhead ac supply wire.

How to calculate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

The Resistivity using Line Losses (1-phase 2-wire Mid-point Earthed) formula is defined as a characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors is calculated using Resistivity = Line Losses*Area of Underground AC Wire/(2*Length of Underground AC Wire*(Current Underground AC^2)). To calculate Resistivity using Line Losses (1-Phase 2-Wire Mid-Point Earthed), you need Line Losses (P_loss), Area of Underground AC Wire (A), Length of Underground AC Wire (L) & Current Underground AC (I). With our tool, you need to enter the respective value for Line Losses, Area of Underground AC Wire, Length of Underground AC Wire & Current Underground AC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Resistivity?

In this formula, Resistivity uses Line Losses, Area of Underground AC Wire, Length of Underground AC Wire & Current Underground AC. We can use 1 other way(s) to calculate the same, which is/are as follows -

Resistivity = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Length of Underground AC Wire)

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